2021 Edexcel A Level Maths Mechanics Walkthrough

[@hollyr3527]

This was so helpful thank you so much. Have my mechanics exam tomorrow and have been struggling with mechanics through the whole course but this really helped 😊

[@MrAstburyMaths]

Glad it helped!

[@adamwood696]

Incredibly helpful for last minute applied revision! Thank you so much!

[@A7TGzed]

14:25 why did u say R=mg and not R=mgcos

[@leaaaaaaal-cr4fm]

Someone said it’s because, there is no mass acting on the ladder like a person or a box on the ladder which we would resolve like you said, instead it’s just a ladder so it feels no reaction force hence we simply resolve vertically. I was so confused lol

[@ohmreggienius]

I just wanted to say that I find your explanations excellent. Well done :)

[@amirah3791]

god i'm failing tomorrow

[@chaimamoali6346]

same im dyin rn

[@MrAstburyMaths]

You got this!!

[@alexritter222]

My turn to fail tomorrow

[@Yazan-xr7ys]

@@alexritter222 and mine

[@issyv.w748]

@@alexritter222oh same 🥲

[@jeddslade3540]

These are really helpful, thank you !

[@amirah3791]

i keep getting confused - when do we use < and when do we use = for the coeff of friction equation ????

[@Acryl1ic616]

Use = when it’s in equilibrium and < when the ladder starts sliding to the left

[@r3ma1n36]

Thank you so much for this your channel is a goldmine

[@n3vious211]

Hey sir, for the projectiles question. If you consider up as positive for the vertical motion. The displacement would be -70 and the acceleration would be positive, so 10?

[@ollielloydjones5774]

gravity as a force acts downwards vertically. this means that if up is positive, then acceleration is negative therefore acceleration is -10 :)

[@リオ利緒]

@@ollielloydjones5774 so when we do Suvat vertically and horizontally, are we only looking at the initial acceleration? isn't it only -10 at the stand, 0 at the bottom, then +10 at the end?

[@abeeha7567]

Are we meant to take acceleration as -10 or -9.8 because in a 2020 paper, he took acceleration of -9.8 to a similar question like this.

[@リオ利緒]

@@abeeha7567 it states in the question to use a=10

[@AlevelStudent-c1y]

For Q2, part d, would you just say “ the string would have a mass/weight” Would this be enough to get the mark?

[@laiilaaaaaaa]

explained beautifully thank u

[@MrAstburyMaths]

Glad you liked it

[@alexandrugeangos714]

Can I just differentiate in column vector form for 1a and b or do I have to use SUVAT because I got the same answers

[@alexandrugeangos714]

* Integrate

[@Txze-j2c]

Thank you so much extremely helpful ❤❤❤❤

[@prab479]

In projectiles questions, how do you know when s/a/u/v are negative?

[@jxpt8935]

Depends what you take positive. If you take upwards positive, gravity acts downwards so its negative

[@amirah3791]

23:00 i don't understand why 60 is v and not u ? since u was 65cosa, why is v taking on its value ???

[@davidworley5254]

v = u as there is no air resistance

[@aryazaziz2773]

im pretty sure when youre solving upwards v=u so you can take the velocity as the vertical u component

[@abeeha7567]

For the projectile question, are we meant to take acceleration as -10 or -9.8? because in a 2020 paper, he took acceleration of -9.8 to a similar question like this

[@Zimbabwe1911]

in the question it says the acceleration is modelled as having magnitude 10, but if it doesn't mention this in a different one probs use 9.8

[@Zimbabwe1911]

so assume 9.8 unless ur told otherwise like in this example

[@christabel2651]

more mechanics videos please🙏🏾🙏🏾

[@Txze-j2c]

Please do more of these

[@patrickflores8583]

goat

[@kimberlygillian9230]

hello, Thank you for the video. on qn 2 why isn't there a reaction force at the angle? and why is there one at A even if its going to be moving. i read somewhere that the reaction force only occurs at turning points and places that make contact with the surface. please help

[@Mara.J.Spencer]

Because that A is in contact with the surface of the plane, so there is always a reaction force in the perpendicular direction to the surface, the angle is 90°