2096. Step-By-Step Directions From a Binary Tree Node to Another | LCA | Backtracking | 2 Pointers

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Aryan Mittal

Aryan Mittal

Күн бұрын

Пікірлер: 14
@Ayush37262
@Ayush37262 3 ай бұрын
You are quite better than codestorywithMIK
@ArhamSheikh-kl1bo
@ArhamSheikh-kl1bo 3 ай бұрын
Explanation is always at next level 🔥
@prathamgolwala9282
@prathamgolwala9282 3 ай бұрын
Bhaiya Dp on trees ka crash course pls 🙏
@harshlimbachiya7510
@harshlimbachiya7510 3 ай бұрын
Great Thumbnails ++
@abhishekshukla5484
@abhishekshukla5484 3 ай бұрын
If u upload explaination notes it will be fine
@AyushSharma-tj1kp
@AyushSharma-tj1kp 3 ай бұрын
This is giving memory exceed limit error how to fix that??
@jimspatel2407
@jimspatel2407 3 ай бұрын
You need to pass the string by reference. may be you are trying to passing string without reference.
@rishabhranjan5162
@rishabhranjan5162 3 ай бұрын
passing string without reference leads to making a copy of the string for every recursive call, thus leading to memory exceed limit
@AyushSharma-tj1kp
@AyushSharma-tj1kp 3 ай бұрын
@@rishabhranjan5162 ok thanks got it
@tgayush1424
@tgayush1424 3 ай бұрын
i have one question ,is it good to use global variables ? Using global variables is not a good way to write solution for a problem i guess.
@akshaanshsrivastava9817
@akshaanshsrivastava9817 3 ай бұрын
Very Heavy Explanation..
@curlyoreki
@curlyoreki 3 ай бұрын
also link the refrence problem you are using in the problem
@badasspandit1886
@badasspandit1886 3 ай бұрын
house robber 3 kraa do Mnnit se hi hoon
@tgayush1424
@tgayush1424 3 ай бұрын
No need to take j can be done with i alone - int i = 0, n1 = rootToStartPath.size(), n2 = rootToDestPath.size(); int lcaLenFromRoot = 0; while(i
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