214.Shortest Palindrome || Leetcode || Solved&Explained || C++

[@avneedadhich9185]

My search for it's solution finally came to an end . Thanks for such a great explanation .

[@shikharai-tl4vb]

you tried well Understanding a problem and effectively explaining it to others are two entirely different skills.

[@abhishekverma7604]

thanks for the algorithm,since code part is way too easy and self implementable...

[@aanchaljain4610]

Glad it helped!

[@AdityaKumar-be7hx]

Great explanation! Only tip is we can reuse the "t" variable instead of creating a new shorter string. return t.substr(0, s.size()-i)+s;

[@aanchaljain4610]

Thank you

[@ujwalchawla6721]

keep going🤘

[@VishalYadav-gk1kg]

Very Nice Explanation Mam, Thank you !

[@materialscience8301]

thanks for make it. your explanation is very well 😊😊 i hope you will continue ..& grow

[@aanchaljain4610]

sure!thank you

[@eklavyacodinghub]

thanks ma'am for making this concept so easy

[@Rahul-kw6zf]

Finally After 2 days got h pretty good solution!! Understood❤

[@satyamaditya384]

Thank you ma'am for such a great explanation, I had been struggling with KMP too, but now concepts are crystal clear. Thanks a lot!!!

[@anonymoustrolls7952]

she just taught KMP, good explanation

[@priyanshupriyam174]

Thanks a lot ma'am, cleared my kmp concepts well.

[@unclezee7369]

Best explanation so far

[@PankajKumar-pk9dm]

loved the approach and awesome explanation

[@shh442]

class Solution: def shortestPalindrome(self, s: str) -> str: if s == s[::-1]: return s n = len(s) # Loop to find the largest palindrome prefix for i in range(n, 0, -1): if s[:i] == s[:i][::-1]: break # Add the reverse of the suffix to the start of the string suffix = s[i:] return suffix[::-1] + s

[@ss8273]

thanks sister explained very well🙌🙌

[@aanchaljain4610]

Thank you

[@silent-st1no]

very very good explanation, thank you so much you are the great❤

[@aanchaljain4610]

Thanks ❤

[@ArnabBhadra02]

Is it possible to solve Using longest common substring between s and rev(s) and after that return the total length -s

[@hackingkingdom5634]

Nice approach Helpful✋

[@aanchaljain4610]

Glad it was helpful!

[@hhcdghjjgsdrt235]

You got one subscriber

[@soumya_suman]

Thank You !!!

[@path8799]

Understood💯❤

[@naive-fleek7420]

you are soo smart

[@Yourcodehelper]

todays daily problem

[@machans-203]

But it doesn't pass all test cases.. for string "aabba" the ans is "abbaabba" how is it possible And also, "abb" -> ans: "bbabb"

[@harmankour1711]

because given is we are allowed to add in the front only and it is passing all the test case just check your code again

[@VivekSharma-sk3vp]

Memory Limit Exceeded!!😭😭

[@raviroy84]

Clear explaination❤

[@srikarsaini]

10:06 Here we should not increment "j". There is a mistake in explanation. Check the code we are not incrementing "j" there in else statement. we are only changing the pointer "i".