#22 Python Tutorial for Beginners | Break Continue Pass in Python

[@Arjunsiva]

My college life would be great if I had a professor like you in my college

[@arjunchavan9669]

Hey Arjun! Never met another Arjun

[@anmol3457]

Arjun siva it really wouldn’t because we usually find another problem with the professor.

[@akash6327]

damn really :) i would not study at all or daily 1 hour would be enough to get a rank :)

[@faridhaf8626]

Agreed

[@PaWoW-PW]

@@arjunchavan9669 cap, Arjun's are everywhere

[@rajtiwari6645]

av=6 x=int(input('how many candies do you want')) for i in range(0,x): if i

[@DevendraSingh-xt2wn]

#fibonacci list1 = [0, 1] for i in range(48): list1.append(list1[-1]+list1[-2]) print('bye') print(list1)

[@rajjoshi4302]

Smart Logic

[@anon5788]

This is very nice approach. learnt a new thing

[@chandhrusrinivasan9595]

Woow

[@rubanaugastin9049]

What's out put of this code

[@viswa_mulukutla]

hey, looks simple but whats the logic here.. can you explain

[@AmitKhuranaSir]

i am experienced programmer so watching on 2x speed but for your bbye i slow down the speed!!!!! your way of saying bbye is awesome

[@Ihsan_almohsin]

Break : to end the loop. It uses with if statement to put a condition so you can break the loop and exit. Continue : to skip the remaining code of the loop when a certain condition happen (like in if statement), but still looping. Pass: uses for impty blocks when you don't have a code to write.

[@alejrandom6592]

thx!

[@YourHotMan]

can someone explain me...why he use * while i

[@goutambanerjee185]

@@YourHotMan i means no. of candies & x is the Limit of candies no. i.e. total candies want

[@uday2159]

@@YourHotMan it's not * bro it is colon :

[@publicenemy1415]

Here it looked like continue & pass are the same. Whats the difference? Used continue to skip number div. by 3 & used pass to skip odd numbers.

[@jurrulokeshyadav842]

I will complete my python within 1 week by your teaching sir. I thank you very much sir for teaching this course.

[@siddharthrajan616]

yeah I am planning to complete it in a single night lol

[@tudos9209]

@@siddharthrajan616 quite possible though

[@shyamjaiswal3432]

@@siddharthrajan616 😂😂🤣 exectly

[@akarshasudheer6626]

To check if a given number is prime or not: i=2 p = int(input("Enter a number:")) while i

[@ankitrawat_data]

your code will fail on 0 and 1

[@rraushan1000]

I had literally searched whole KZbin in search of a video that could explain me loops but I didn't get one. Then, I found this channel and finally I understood loops and even make programs using while and for loops. Thank you Navin sir :)

[@pradeepchandertiwari2883]

My vending machine is not working even with the same code

[@BhuveshDhiman]

x=int(input("Enter a no.")) s=0 i=1 while(i

[@suryanshugarg10]

good one

[@BhuveshDhiman]

@@suryanshugarg10 thank you

[@darshitthakar7999]

Nice one .

[@divyasree24]

why do we need to check s==2:;why not s==1?

[@joseph481994]

@@divyasree24 a prime number is divisible by 1 and itself implying that the "if" block would have executed twice if the number was prime.

[@rohithsardar187]

2. a=int(input("enter a integer")) count=0 for i in range(1,a+1): if(a%i==0): count=count+1 if count==2: print(a)

[@flamboyantperson5936]

When you will start with "Machine Learning"? It's going to be awesome if you teach us.

[@anindian4601]

Not only machine learning we want Artificial Intelligence TOO.

[@ashwiniambhore3056]

+1

[@talhaordukaya2204]

For the first one: a = 1 b = 1 for i in range(50): print(a) print(b) a = a + b b = b + a

[@lalithkumar4794]

niceee

[@YashhC]

Epic. But this code prints 100 Fibonacci numbers because we print a and b both till i=50. so use range(25). IDK how to do it with odd numbers like 51 because we can't take 25(50 nos), 26(52 nos) and 25.5 is not a thing.

[@talhaordukaya2204]

@@YashhC Yes, you are right. Here is the code. It works exactly like you want. I arranged for you :) a, b = 1, 1 print(a) for i in range(49): print(b) b, a = a + b, b

[@YashhC]

@@talhaordukaya2204 Yes that makes more sense! This can do any amt of numbers ^^

[@kr.vinay4669]

Please replace a= 0 to start sequence with 0

[@tirthshah3350]

I had just started your python tutorial and it was the best. One request is that at last please also show how to make games and software in python.

[@divyanshusingh6105]

You are a really great man.... I learned from you and practise some programs and i did it... First time in my life i can create the logic..🙌🙌🙌

[@stmpcol]

Teaching is an art. You've got it man👍 very logical progression for beginners.

[@ahilanbhattacharya3402]

sir you are a very great teacher i am 13 years old and i am learning python and as well i could understand each and every thing you say..you're teaching style is really great..

[@sainikhila4027]

fibonacci solution a = [0,1] for i in range(0,49): b = a[-1]+a[-2] a.append(b) print(a)

[@babasahebbhosale7908]

b=a [0]+a [1] is also right na

[@Bharathsuru]

@@babasahebbhosale7908 no it's wrong if you do like that you will get [0,1,1,1,1,1,1...........]

[@hjjkgdgfdgf]

@@babasahebbhosale7908 If you do that, it will keep adding only first 2 numbers and that would be 0+1 always. Doing a[-1] + a[-2] would do a sum of last 2 digits, which is what is needed for fibonacci series

[@princeraj7106]

x=int(input('enter a number')) i=2 while i

[@vivekrenikunta2398]

According to your code, 9 is a prime no which it is not.

[@princeraj7106]

@@vivekrenikunta2398 Recheck it.. Its certainly giving not a prime number as 9 as an input... I think u misinterpreted the output...Try again using proper indentation...!

[@vivekrenikunta2398]

Yeahh... I'm sorry'😅

[@princeraj7106]

@@vivekrenikunta2398 no issues...

[@dharmishtabasita666]

n=int(input("enter the number for checking it is prime or not:")) i=2 while i

[@bsmaheshkumar5328]

Why we need udemy when we have a professor like you. Outstanding explanation.

[@frenchfatfather]

for real?

[@DineshKumar-xi8rv]

Sir I am in 7th grade and you are one of the best coding teacher ever as well as your examples make easy to understanding coding in py.

[@selvib7634]

I have never heard a explanation about loop... Brilliant explanation 👌... Thanks a lot sir.

[@divyanshusingh6105]

1-n=int(input("Enter no of Sequence:")) def fib(n): a,b=0,1 while b

[@sankalparora7254]

a=int(input("enter a number")) if(a==2): print('prime number') else: for i in range (2,a): if(a%i==0): print('not a prime') break if(i==(a-1)): print("prime number")

[@sandeepch]

i like i(i==a-1)

[@vernanonix]

@@sandeepch If you limit your range to the square root of a, you'll go faster. Granted, I don't think range will take a float number so you might need to ceil it. But essentially half of the factors exist before the square root and half exist after. But if you check everything in the first half, you'll find their pair in the second half. Thus you only need to check the first half.

[@omkarpathak4759]

Sir the way of your teaching has just made learning python so easy and I'm blessed to learn from you sir. Hope i could meet you some day.

[@mahmoudamin8534]

1st 50 fib numbers : first = 1 second = 1 temp = 0 for i in range (50): if i == 0 or i == 1 : print(1) else: print(first+second) temp = first+second first = second second = temp

[@syedaqib2912]

super it really works...

[@sardarrashid639]

print(i) it will work

[@fatihavc8453]

from math import sqrt x = int(input('Enter a number to check primeness: ')) n = 2 for i in range(1,x-1): if x%n==0: print("not a prime") break elif n==x-1: print("prime") break n += 1

[@alirezafahama9299]

a,b=0,1 for i in range(0,51,1): print(a,end=' ') a,b=b,a+b

[@peacefullmusic8374]

is it correct?

[@FactsDiscoveryyoutube]

availableCandy = 20 numberCandy =int(input("How many candies you want")) #i =1 #while iavailableCandy: print("sorry!out of Stock") break print("Candy") i=i+1 print("Bye!Have a good Day")

[@Sagarnamaa]

Fib: x=0 y=1 for i in range(0,50): print(x," ", end="") next=x+y x=y y=next

[@adarshsahani1947]

well but 0 is not first in series

[@Sagarnamaa]

@@Svcollections941 crt ?

[@sombithsen177]

Ass 2: i=int(input('Enter a number: ')) n=2 while n

[@androygaminghk1197]

Tq for your teachings sir....u made python easy to learn and understand... Waiting for machine learning teachings...

[@Sumanth30796]

fibonacci series a=0 b=1 print(a) print(b) for i in range(0,10): c=a+b print(c) a=b b=c

[@alejrandom6592]

I love that you use analogies to explain abstract concepts, great video!

[@hallo-xp2wh]

first one answer c=0 i=1 print(c+1) while i

[@vaishnavigoswami2891]

you r the only one best teacher....thank u so much, sir....just because of u all the concept are clear now

[@vernanonix]

I made my previous prime checker better. Super satisfied: x=int(input("For what number would you like to check primeness? ")) factor=2 while factorx/factor: print(x,"is a prime number.")

[@indranujdas5917]

1. Fibonacci Series Code: x=0 y=1 print('The Fibonacci Series will be: ') print(x) print(y) i=1 while i

[@rohansinha6309]

Thanks buddy 😄

[@bmguitarhub6135]

why 48 not 50?

[@akarshasudheer6626]

@@bmguitarhub6135 Because we are already printing value 0 and 1 before entering while loop so that leaves us with 48 more values to complete first 50 fibonacci numbers

[@bmguitarhub6135]

@@akarshasudheer6626 yeah, thank youuu

[@Manoj_Max]

Can you explain 'pass' statement clearly....for yy we are use that condition??...plz anybody

[@shivanshpandey7239]

FIBONACCI SERIES: a,b=0,1 while a

[@jhz5071]

Candy program using for loop: available = 5 x = int(input('How many candies you want? ')) for i in range(1, x + 1): if i > available: print('Out of stock!') break else: print(i, 'candy!!')

[@jhz5071]

@Capt. John Price Where I missed that? I don't think we need i==1 anywhere in this program?

[@jhz5071]

@Capt. John Price You mean I should initialize it first? As per my understanding, i is an iterator here and range function gives it an initial value as well which is 1 in this case because I have mentioned it, otherwise it'd have been 0. Please correct me if I am wrong.

[@J.S.W0822]

n=int(input ("enter the any number")) i=1 List=[] for i in range (1,n+1): if (n%i==0): List.append (i) print (List) if len(List)

[@abusaeedansari7231]

x = int(input("Enter the Number : ")) # To find the given number is prime for not z = 2 for i in range(1, x): if x % z == 0: if x == z: print(z, " Is a prime number..") else: print(x, " is not a prime number...") break else: z += 1 #Finally done

[@cv5033]

But 4 also gives 0 remainder but it is not prime

[@prabhatranjan1078]

@@cv5033 Then it will print not prime

[@sumant5588]

this code fails for input 1.

[@linuso77]

@@sumant5588 aap batao 1 prime ya not prime .....1 ko consider nhi karte ...i want to just add command for 1 input from user it will show invalid or u can show any thing u want to

[@mtromanff320]

You are just rocking🔥....the way of teaching is out of world 🫡

[@Staab0]

a = 10007 b = a if a==1: print(a, "Is not prime") while b > 2: b -= 1 if a%b==0: print(a, "is divisible by", b, ",", a, "is not prime") break if b==2: print(a, "Is a prime")

[@arunavsen2234]

brilliant

[@abpkl609]

QUIZ ANSWER : 1. fib1=0 fib2=1 for i in range(0,50): if i

[@maisharubaiat5012]

Hello. My question is couldn't we use continue for the code you've written for pass and vice versa? Isn't the logic same for both continue and pass?

[@harishharidas8504]

Even i was thinking the same : Got an Anwser ... "Continue forces the loop to start at the next iteration while pass means "there is no code to execute here" and will continue through the remainder or the loop body. Continue will jump back to the top of the loop. pass will continue processing.."

[@kirubhaharkannan5461]

Diff b/w Continue and Pass: Continue skip the loop , will not executes the below statements and goes to top of loop, where pass executes the remaining logic. Example below. Continue : for i in range(11): if (i%2==0): continue print( i , " is odd") ---------------------------------------- 1 is odd 3 is odd 5 is odd 7 is odd 9 is odd Pass : for i in range(11): if (i%2==0): pass print( i , " is an number") --------------------------------------------- 0 is an number 1 is an number 2 is an number 3 is an number 4 is an number 5 is an number 6 is an number 7 is an number 8 is an number 9 is an number 10 is an number

[@nakeebraut8676]

a=int(input('How many candies?')) av=5 i=1 While iav: Print('candies left=, end='') Print (av) break Print ('candy') i=i+1

[@nshul16]

Sir I am Agrim of class 8 and I want to learn python because I like coding and programming (as you say programming is so fun😉)and I am learning by your videos. Thank you a lot sir and please keep guiding us.

[@easydatascience2508]

You can check mine too. The detailed Python playlist provides all the tuturials, and source files.

[@kirubhaharkannan5461]

Diff b/w Continue and Pass: Continue skip the loop , will not executes the below statements and goes to top of loop, where pass executes the remaining logic. Example below. Continue : for i in range(11): if (i%2==0): continue print( i , " is odd") ---------------------------------------- 1 is odd 3 is odd 5 is odd 7 is odd 9 is odd Pass : for i in range(11): if (i%2==0): pass print( i , " is an number") --------------------------------------------- 0 is an number 1 is an number 2 is an number 3 is an number 4 is an number 5 is an number 6 is an number 7 is an number 8 is an number 9 is an number 10 is an number

[@tejasteja6653]

# for prime number x=int(input("enter the no.")) b=False if x==1 or x==2: print("prime number") elif x==0: print('zero') else: for i in range(2,x): if x%i==0: b=True if b: print('not prime') else: print('prime')

[@anindian4601]

av=6 x=int(input("how many candies you want :")) i = 1 while iav: print("Please Collect",i-1,"Candies &",x-av," Candies are Out of Stock ") break print(i,"Candy") i+=1

[@naumanhameed900]

list = [0,1] for i in range(49): list.append(list[-1]+list[-2]) print("Fibonacci Sequence is = ", end="") for i in list: print(i, end=" ")

[@aravindtnpsc4568]

Your condition will print 51 fibonacci numbers

[@ezhilan1]

awesome logic sir.Great

[@zakiasmaa6834]

Teaching is an art. thank youuuuuuuuuuu

[@prithvirajmaity4600]

easiest solution for fibonacci x,y=0,1 while y

[@paharididi6501]

Cool bro

[@prithvirajmaity4600]

@ENTERTAINMENT WORLD i ran the loop till 50, it will run fibonacci numbers till 50

[@shantiratha6276]

You are the best teacher of python on this planet 🌍🌍🌍

[@webbrain19]

fib50 = [0, 1] for i in range(2, 50): fib_next = fib50[-1] + fib50[-2] fib50.append(fib_next) print(fib50)

[@touristknud5434]

Great course! The answer beneath looks correct to find out if a number is prime. x=int(input("is this number prime?")) for i in range (2,x): if x%i==0: print (x, " is not prime") break else : print (x, "is prime") break

[@radmonk8843]

a dude can u explain me the logic plz

[@lokeshsharma4363]

this will throw an error for values like 9

[@DonaldOkonkwo-n5e]

No output would be visible if for a number like 2

[@urvi.sharma]

1) First 50 Fibonacci Numbers x = [0,1] for i in range(1,50): y = x[-1]+x[-2] x.append(y) print(x) 2) import math as m x = int(input("Enter a number")) if x == 1: print("Neither") else: for i in range(2,int(m.sqrt(x))+1): if x % i == 0: print(x, "is not Prime") break else: print(x, " is Prime")

[@smitparthe2341]

its (1,51) because 50 gets excluded

[@adityajaiswal2891]

Thanks sir, I'm from Mechanical background and just joined Infosys..... Ur videos are helping me alot in my training period. 🙏🏼

[@venkatahariprasad8753]

n = int(input('enter the no fibonnacci num')) n1=0 n2=1 print(n,"first fibonacci numbers are",) print(n1,' ',n2,end='\t') i=0 while i

[@nagapranithasamudrala2224]

first=0 second=1 print(first) print(second) for i in range(0,48): next=first+second print(next) first=second second=next

[@tanzimulayaantanaf8969]

0 is not included in a fibonacci series

[@Sagarnamaa]

Prime Number: x = int(input("Enter Number")) if x==0 or x==1: print("NP") else: i=2 while i

[@khairahammed5187]

This is the only channel which made me satisfied :) Thanks dude

[@vernanonix]

For prime numbers: x=int(input("For what number would you like to check primeness? ")) factor=2 upper=x while factorupper: print(x,"is a prime number.") The point of the upper variable is to limit the number of actual operations needed to check. I'm checking one by one going up a list. But I know for a fact that once the numbers are dividing by are bigger than their results, it's a pointless task. So I'm basically constantly updating my upper bound for what I can check. Granted, I could also just set the while loop to only work when factor is less than x/factor, which does save memory. But I got way too much pleasure figuring out this method.

[@vernanonix]

@Papa Bear Your logic is fine, but you end up checking a lot of unnecessary numbers when in reality, if you find a factor n such that 1

[@yashm05]

x = int(input("how many candies you want?")) if x

[@adarshsahani1947]

still print 10 candies but the avialble candy is 5

[@Hydgodharollu]

in else statement print(' candies'*5) instead of print(' candies'*x) or first take available=5, then print(' candies'*available) x = int(input("how many candies you want?")) available=10 if x

[@tejas1674]

print("WE HAVE 10 CANDY ONLY") a=10 x=int(input("Enter the number of candy?")) i=1 while ia: print("Out of stock") break print("candy") i +=1 print("Thank you for visiting")

[@riaz_ay]

Prime no checking: x=int(input("enter no:") for i in range(2,x,1): If x%i==0: print("no not prime") break else: print("no is prime")

[@anandhisiva93]

Its not working for x=1

[@anandhisiva93]

x=int(input("Enter an ineger: ")) if x>1: for i in range(2,x): if (x%i == 0): print("Its not a prime number") break else: print("Its a Prime number") else: print("Its not a prime number")

[@angelo90th]

@@anandhisiva93 1 is not a prime number

[@neerajbaishya781]

This doesn't work for 15

[@ML.ArtificialIntelligence]

x=int(input("enter a number")) i=2 while i

[@DeshDeepak08]

num = int(input("enter number of digits you want in series (minimum 2): ")) first = 0 second = 1 print(" fibonacci series is:") print(first, ",", second, end=", ") for i in range(2, num): next = first + second print(next, end=", ") first = second second = next

[@DrBhavaniRaoReddi]

# Print prime numbers p = int(input('UNtil which number do you want the prime Numbers?')) # For loop to generate numbers till the user input for num in range (2, p+1): # all prime numbers are greater than 1 if num > 1: # For loop to generate divisor, and if it is not divisible, escapes the loop and prints the out of range number for i in range(2, num): if (num % i) == 0: break else: print(num)

[@gianluigi5828]

This video is awesome. I understood everything thanks a lot

[@viveksonkar3033]

import math total = 0 P_num = int(input("Enter the value")) for i in range(1,P_num + 1): remainder = P_num % i if remainder == 0: total = total + 1 if total == 2: print(f"{P_num} is prime Number") else: print (f"{P_num} is not Prime number") Thank you so much Teluskon

[@harshvora1922]

Number is prime or not: x = int(input("Enter a number: ")) i = 2 while i

[@janandanyoganadan616]

superb

[@janandanyoganadan616]

but does not work for negative nubers

[@BhuveshDhiman]

i=1 a=0 b=1 print(a) print(b) while i

[@chughprabhkirat4141]

#fibonccai series first = 0 second = 1 print(first,",",second, end=",") for i in range(2,50): next = first+second print(next, end=",") first = second second = next #Check if a given number is prime or not num = int(input("Enter any number ")) if num>1: for i in range(2,num): if num%i==0: print("Not a prime number.") break else: print('it is a prime number') else: print('not a prime number')

[@epoxy55]

Error in third line

[@abhishekdhillon8731]

x = int(input("Enter any nO :")) i = 2 while i < x: if x % i == 0: print("not a prime ") break else: print("prime") break i += 1

[@vetrimech6020]

doesnt work for num 9 etc

[@Yashwanth-k7u]

Start Ai&Ml

[@Rajadahana]

This is how I understood the three concepts. break - terminates the loop, or comes out of the loop continue - goes to the start of the loop pass - as the word suggests, goes to the next step in the loop

[@sanjag]

This has been so incredibly helpful. Thank you!!!

[@hrpasisia3033]

1. Print first 50 fibonacci numbers lim = 50 count = 0 n1 = 0 n2 = 1 while count < lim: print(n1) last_number = n1 + n2 n1 = n2 n2 = last_number count += 1 2. Check a given number is prime or not num = int(input("Enter Number : ")) if(num==2): print('Prime') else: for i in range(2,num): if num % i == 0: print("Not prime") break else: print("Prime")

[@harithareddy1731]

Really great effort Sir..It was really amazing ..!

[@apurvakrishna7181]

# Program to display the Fibonacci sequence up to n-th term nterms = int(input("How many terms? ")) # first two terms n1, n2 = 0, 1 count = 0 # check if the number of terms is valid if nterms

[@ayyapand3671]

Q. 1) a =int(input("Enter a Number ")) n1, n2 = range(2) b = 0 While b

[@chaparalasrinivasrao7503]

Hi, Your python videos are very useful. Can you guide me how to improve my program skills because I don't have any programming knowledge before.

[@vernanonix]

And one last pass at the prime number question because I'm having fun with this one in particular. Readded the upper variable to cut down on operations while only storing one more variable. Added checks for anything less than 2. I had fun with this one. x=int(input("For what integer would you like to check primeness? ")) from math import sqrt if x

[@satwikdua]

how about this? x = int(input("give a number")) i = 2 while i

[@madhavmishra6937]

Hi Navin, First of all kudos on your wonderful work! I have a doubt here regarding the difference b/w "pass" & "continue". Even if we look at the example in this video....even if we had used "continue" instead if "pass", odd numbers could have got printed. So, my doubt is that if both the keywords (pass & continue) are asking to ignore the remaining code of the loop 'for that iteration', then what is exactly different about them?? Thanks in advance!

[@madhavmishra6937]

Thanks...that cleared the air considerably....

[@vedhakrishnapanchami2026]

if we use continue it completely skips the whole process and proceeds for the next iteration in the for loop but whereas pass gets exit from that particular block and execute the remaining block

[@vedhakrishnapanchami2026]

like wise in the given code , pass goes to else block and if we use continue it doesnt go to else block

[@ankursahu4731]

x = [0,1] for i in range(0,50,1): if (i

[@tariquelislamtamim1649]

#Solution (according to this video) 1. First 50 Fibonnaci Numbers: n1=0 n2=1 sum=n1+n2 for i in range(1,51): print(sum) sum=n1+n2 n1=n2 n2=sum print("Bye") 2. Check Prime Number (works for any number) num = int(input("Enter a positive integer number: ")) if (num>0): for i in range(2,(num+1)): if (num%i)==0: break if(i==num): print(num," is a prime number!") else: print(num, " is not a prime number! ") else: print(num," is not a valid number!") print("Bye")

[@niteshjaiswal2752]

For the 2nd question’s answer:- if a user enters 1 it throws an error message, : “name error : name i is not defined” Another best solution for 2nd Question is below:- Check a given number is prime or not? x = int(input("enter a number please")) if x == 0: print("Please enter a number greater than 0") elif x > 0: if x % 2 != 0 or x == 2: print("It is a prime number please") else: print("It is not a prime number please") else: print("Please enter a positive number")

[@anvitasuvarna1421]

@@niteshjaiswal2752 9 is not a prime number, but your code says it is. The conditions have to be changed.

[@DevSharma-eg3sx]

@@niteshjaiswal2752 your ans is right for even number not for prime no.

[@HighVibez01]

Just started learning.. converted to for loop x=int(input("enter the value")) for i in range(0,x): if x>av: print('out of stock') break print("candy")

[@samarthsaxena3998]

#Check the number is prime or not num = int(input("Enter no")) for i in range(2,num): if num % i == 0: print("Not prime") break else: print("Prime")

[@shyamal5935]

2) num = int(input("Enter a number")) for i in range(1, num-1): if num % (num-i) == 0: print("non prime number") break else: print("prime number")

[@EylulTurksever]

after i reaches (num/2), it is no longer needed to try further to see if its dividable. almost half of the processing is unnecessary in this case.

[@kibreabhaileselassie5136]

When you will start with "Machine Learning"?pls

[@anindian4601]

Not only machine learning we want Artificial Intelligence TOO.

[@dhayanandshanmugam7183]

def Fib(n): if n==0: return 0 elif n==1: return 1 else: return Fib(n-1)+Fib(n-2) for n in range(2,50): print(Fib(n)) n=n+1 Code to print Fibonacci numbers

[@sufiyanmogal1527]

# 2nd assignment Prime Number Finder num = int(input('enter a number ')) prime = True for i in range(2,num): if(num%i==0): prime = False break if prime: print("This Number is prime") else: print("This Number is not prime")

[@idreesahmed7403]

a = int(input("Enter Any Number : ")) count = 1 for i in range(1,a): if a % i == 0: count +=1 if count == 2 : print(a,"is prime") else: print(a,"Is not a prime")

[@akshayak4007]

Your code is wrong

[@akshayak4007]

Range should be a+1

[@vinaybojjalwar]

For 50 fibonacci series First=0 Second=1 Temp=0 For i in range(49) Print(temp) First=second Second=temp Temp=first+second

[@ashish7750]

0 1 2 3 5 8 13 21 output is not the correct Fibonacci series.

[@bhajanmandlimumbai]

though the logic is correct

[@srikrithibharadwaj6779]

Hi Sir, all your sessions are awesome 👏 Thanku so much🙏🏻 I’ve a question.. can’t we use continue instead of pass statement ?

[@abharani7283]

I have also the same doubt as both works in A same way 😳

[@srikrithibharadwaj6779]

Yup

[@tanzimulayaantanaf8969]

no, you can't use. Those are two different thing. Try to use debug to see what's the difference.

[@ManishSharma-lt6ig]

a=0 b=1 c=1 print(a,end=' ') print(b,end=' ') while c

[@KaizokuxMoto]

Ye m hu 23 ko mera exam h Or ye mere preparation ho ri h . Thank you sir