24 - Induction - Self-inductance & mutual inductance

[@g_plnc]

Thanks! This was just what I needed for a little extra clarity. Nice backward writing skills too haha.

[@CogverseAcademy]

!emoclew er'uoy

[@entropyz5242]

If i is increasing to the right, the induced emf opposes that increase. If i am not mistaken, the direction of your emf arrow in the self induced coil should be the other way around from how you drew it.

[@CogverseAcademy]

Erick Zamora indeed, if we assume i(t) is increasing, then the induced emf should go the other way to driven an induced current that opposes the increase in i(t). The way it is currently drawn would be correct if i(t) were decreasing: the induced emf would drive an induced current that would oppose the decrease in i(t). Good catch! Thanks for letting us know.

[@clarachristensen3194]

I think he may have it right, it confused me too, so I kept looking at other videos until I realized that the emf is in the opposite direction of the current. I think that current flows towards the positive terminal of the voltage generator in a circut, so that would make it "opposite" of voltage. Please correct me if I'm wrong

[@clarachristensen3194]

That is why emf would then be negative to oppose the increasing flux...

[@TheVorazz]

Dude I’ve been playing with my hands for 10 minutes because I didn’t understand why I was wrong, what a relief

[@buckybarnes7337]

Mutual inductance is where we have two coils placed next to each other. Self inductance is where we only use one coil. The increase in magnetic flux in particular direction will cause induced current to produce magnetic field in an opposite direction in order to reduce the increasing magnetic flux. -When the current in coil 1 increases, the number of magnetic field, B will increase too. This causing the magnetic flux to increase too. This end up producing the induced EMf, group: Anis Afzan Nur syafiqah bt Lukman Nurul Batrisyia Abdul aziz

[@1R_D_Z]

Me in 2020 still wondering how he was writing backwards

[@somebody251]

He is not writing backwards when they edit it they flip the video sideways so that its readable

[@yoniasfaw2042]

that was a good explanation but i think i must know more about the constant as it may confuse

[@AbhiShek-nv3vq]

Awesome

[@hayleyvella1894]

Quick question, are you writing backwards man? If so, awesome job :)

[@yniq9769]

he definetly mirrored the image

[@07aniketdeysarkar26]

@@yniq9769 Look closely he's drawing it reversed only !! I also thought that first

[@yniq9769]

@@07aniketdeysarkar26 how do you determine that?

[@07aniketdeysarkar26]

@@yniq9769 Just follow his hand !! He wrote the epsilon just opposite to what we write !

[@yniq9769]

@@07aniketdeysarkar26 ye, he starts from the top, then mirrors it to make it possible for us to read. There is no way in determining wether he just mirrored it or learned a totally new style of writing/processing information. Except that one way is way more convenient ;)

[@zikermu]

Excellent explanations .Thanks a lot

[@nicolehiladavila145]

Beautiful explanation thank you!

[@muhammadamirul8524]

What is the condition to differentiate the occurrence of lenz’s law and mutual induction/ inductive coupling? Since both circuit arrangement looks exactly alike but different direction of magnetic field.

[@bostonmassachusetts6867]

I love the color!

[@frizstyler]

Are you left handed and drawing normally on some weird electronic board system or are you incredibly good at drawing oppositely??

[@gustavohupfer4466]

I was also thinking about that, but then i realized, they just have to mirror de image so it is normal for us to read.

[@frizstyler]

@@gustavohupfer4466 right. He s left handed then.

[@gauthamsaravanabava5976]

If I am not wrong I think there should be a negative sign even in mutual inductance Emf2 = - M21 (di1/dt)

[@WailTheDesigner]

i think the same

[@WailTheDesigner]

let's speak about e2 , the current i1 is increasing and this means d(i1)/dt is positive so e2 is positive , we know that the secondary is like a generator (the same principle of transformer) so the current pass from + to - . for that he must reverse the polarity of e2 because he draw it in wrong way according to his drawing the current pass from - to + and that is wrong.

[@WailTheDesigner]

listen carefully the second coil is like generator for the second circuit. the current pass from + to - of the generator (that means from + to - outside the loop of the inductance and from - to + inside the loop of the inductance) and we also know that if e2 is positive that is mean that the direction of the arrow is from - to + so by using these two rules he must change the direction of the arrow of e2 becuase he drawn it passing from the + to - Reverse the right direction (i said that he drawn it from + to - because the arrowhead Where the current enters, so the arrowhead is in the - and not in the + and that is wrong)

[@kanishkbanker]

Maybe he did it on purpose... :/

[@juanfelipe8484]

Since we increased the current in the mutual inductance solenoid, wouldn’t we get an opposing current as well?

[@hresoldier-xl5xl]

Yes, it will act as a AC "battery".

[@raspberry765]

Why is delta phi / delta t = delta I / delta t? Which equation shows this proportionality?

[@charmendro]

does self inductance mean u can have perpetual energy with an AC circuit and self inductance? ik im wrong

[@evelynliu8447]

Super helpful

[@opgamewiz2995]

Can i get help with this when the voltage is induced why does the magnetic field created always have to oppose the magnetic field that was there before like why the voltage just flow in the same direction

[@CogverseAcademy]

Opgamewiz the induced voltage across the inductor driven an indiced current (that creates B induced) to oppose the *change in magnetic flux*. Does that make sense?

[@opgamewiz2995]

@@CogverseAcademy I understand now since yesterday after hours looking around on the internet thanks away though

[@yoniasfaw2042]

that was a good explanation

[@BappuDebNath]

I am just looking at board, which I can't see off course!

[@AmirKhan-tq8ll]

For producing current in coil we need to change flux . why uniform flux didn't produce current practically . i have got answer theoretically. PLZ i will wait

[@aksh4749]

Uniform flux= no change in flux so induced emf will be zero as induced emf is directly proportional to derivative of flux with respect to time?

[@aksh4749]

Correct me if I'm wrong

[@MegaDrna]

Thank you for the video is very good, clear explanation and comprehensive drawings, but I didn't get how to calculate M, the mutual inductance coefficient?

[@CogverseAcademy]

Often times M is given. However, it can be calculated too. You would need to know specifics about each solenoid (number of coils, length and radius for each). I do not go over the derivation in these videos but if you look it up you should find that M = µ0*N1*N2*Pi*r²*L where N1 and N2 are the number of coils, r is the radius and L is the length.

[@vichukm99]

Why take M1=M2=M

[@mohamedkamal6050]

U are proffisseor

[@chaitanyagiri76]

does self inductance cause increased resistance in the circiut because of oppposing current it produces ?

[@CogverseAcademy]

No, the resistance of the circuit is not affected by the self-inductance. However, the net current is affected because the induced current (from the inductor) always opposes the change in current.

[@POLMAZURKA]

change the technique: write out kvl =0 , for each equation.

[@chamanthswarup6596]

what is relation between mutual inductance and self inductance coils

[@ashasalelkar7457]

chamant swarup That would be the coefficient of coupling. It is represented by k. K = M/√L1*√L2. L1 is the self inductance in coil 1 and L2 for coil 2.

[@faisalali2001]

Is this guy just writing casually backwards? Its better than my normal handwriting ffs

[@ubeydaltuntas6140]

Thanks bro

[@onyxtechnologyx]

@1R_D_Z me still in 2023 impressing

[@kanishkbanker]

The arrow in self-inductance! I think it is wrongly portrayed.

[@WailTheDesigner]

i think there is a mistake you have to write in the mutual inductance [ - M21 (di1/dt) ] instead of [ + M21 (di1/dt) ]

[@jeffreyonce6772]

better in x1.25 speed

[@Math-Molecules]

kzbin.info/www/bejne/inWtnYiLp96CbKc

[@yoniasfaw2042]

that was a good explanation but i think i must know more about the constant as it may confuse

[@yoniasfaw2042]

that was a good explanation

[@charmendro]

does self inductance mean u can have perpetual energy with an AC circuit and self inductance? ik im wrong

[@mostafaahmednasr621]

theoretically yes , because there is 0 resistance for inductors.

[@BappuDebNath]

I am just looking at board, which I can't see off course!