24 THERMODYNAMIC STABILITY | Coordination Compounds | IIT ADVANCED | JEE MAIN | CHEMISTRY 12

[@malavathprashanthnayak2456]

Sir as you said at 2:25 a question was asked in Jee adv 2020

[@shirshgyan6778]

Another wonderful lecture Thanks sir

[@adityaghai220]

Sir app pe aapki videos chal nahi rahi hai ( chemistry ) ??? Please help sir By the way you are a great teacher sir

[@Abhinav-zv4hs]

Check Mohit Tyagi Channel Biro

[@prezputin2233]

@@Abhinav-zv4hs he is watching on Mohit tyagi channel 😂😂😂😂

[@-Borax]

16:53 The major reason for the high Kf is the strength of the bond b/w the cental atom and ligand (Jitna jyada strong bond banega, Kf ki value jyada and complex will be highly stable!

[@-Borax]

Reminder For Me: Idhar ke baad se firse Take ss and notes when you get time (Just stop the video and take notes of whatever written on the sceen and timestamps if any, Dont Rewatch the videos again!) 22/06/2024

[@iitian7278]

Sir i promise I'll crack jee adv mains and boards 💫💪

[@devanshusharma1682]

Sir thermodynamic stability ligand ke field strength par depend karegi and haa toh kaise ? NCERT 9.31 Exercise

[@vansh7311]

excellent explaination but just a request sir pls can u remov some ads it brks the flow......

[@napalmbhoji]

Thank you Sir.

[@-Borax]

12:38 Thermodynamic Stability starts

[@ScrutinizersSight]

Sir aap padhate ho 100% fir notes banane me hame samaz aata hai 😂

[@AbhishekKumar-us6wf]

Head me kaise unpaired paired pata chal jaata hai

[@amitsingh2782]

Thanks sir

[@tobrozofficial5204]

7:07 shouldnt the value of x be 0 since there arent any extra pairs of electrons

[@kmishra514]

That has to be kept in mind while calculating CFSE. When you calculate spin magnetic moment, you just check the no. of unpaired electron. So, while calculating spin magnetic moment, you will consider x=3.

[@letmynamebeequaltox2961]

x here stands for no of unpaired e not no of extra pairs

[@shook3487]

70 Done

[@stephaniekim6800]

cn of cu in blue vitriol is 4 or 6??

[@calculus3097]

6

[@gnani..31]

6(two from sulphate ions and four from water ligands

[@swatisingh5094]

6

[@VarunKakwani15]

6 - 4 h2o directly bonded and 2 sulphate ion , forming an octahedral geometry in polymeric form

[@kavi5990]

Was mentioned clearly in the last lecture (saying this so that people in future may benefit)