#26 Arrow function in JavaScript

[@_mc_hon_3219]

All these years, I haven't seen anyone explain arrow functions any better

[@muminulislamsayem]

let input1 = Math.abs(5); let input2 = Math.abs(-7); let sum = (num1,num2) => num1 + num2; let result = sum(input1,input2); console.log(result);

[@MdAyub-wl4hk]

Thank you dude 😎

[@pavelkundu5977]

const add = (a,b) => Math.abs(a) + Math.abs(b) console.log(add(-2,-5))

[@shreyashkhurud7217]

5:07 Answer: let add = (a,b) => { if(a

[@yagneshacharya2461]

i took paid course from other but i cant understood arrow functions there , so i came here 😂😂😂,,, atlast we all have to come to 'mentors of all mentors'

[@cordovajose5693]

This was easy for me because I saw your Java Lambda videos some time ago. You did a great job explaining how an anonymoys class can be converted into a lambda expression.

[@mithunrathod6714]

time stamp: 5:10 // Assignment => let addition = function(num1, num2) { if (num1 > -1 && num2>-1){ console.log(num1 + num2); } else{ console.log("One of those number is negative"); } } addition(1400, 56); Output -- 1456

[@prajjwalchauhan2165]

you didn't mentioned return statement bro! her's the ans:- let add = (a,b) => { if (a > 0 && b >0){ return a + b }else { return ("Error"); } } console.log(add(2,5));

[@shreyashkhurud7217]

You are both wrong! he told to add the numbers even if one of them or both are negative! Here's the right answer let add = (a,b) => { if(a

[@thequantum-plator]

@@shreyashkhurud7217 lol no, he said add the numbers only if they are positive. Those 2 commentators understood the question right. Listen carefully at 5:27

[@asap4064]

@@shreyashkhurud7217 bro you should also add another else if where both the numbers are negative

[@Harimanideep]

@@shreyashkhurud7217 you are also wrong man!! what is the use of if statements in your code!!

[@little_things_31]

let add = (num1, num2) => (num1

[@devanshusachdev7367]

Enjoying your course a lot! It's great to be a part of your alienArmy👽 Here's my solution for the assignment question: let func = (num1, num2) => (num1>=0 && num2>=0)?num1+num2:"positive numbers only";

[@chetan_nada]

We can use Math.abs(num1) + Math.abs(num2) for converting negative to positive.

[@parthshah1314]

Sir you are the inspiration and you are the one of the best guide. Keep going sir we all supports you.

[@navamshuram]

let a1 = Math.abs(5); let a2 = Math.abs(-7); let sum = (num1,num2) => num1 + num2; let result = sum(a1,a2); console.log(result);

[@satheesh1290]

let add=(n1,n2)=> { let n3=Math.abs(n1); let n4=Math.abs(n2); return n3+n4; } sum=add(4,-9); console.log(sum);

[@NithinS-bm8qt]

const add = (num1, num2) => { const condition1 = Math.sign(num1); const condition2 = Math.sign(num2); if ((condition1 && condition2) === 1) return num1+num2 else return ('given num is zero or negative') } let result = add(1,9); console.log(result);

[@rohithyarramsetty5600]

What's the validation here? *if ((condition1 && condition2) === 1)*

[@sombithsen177]

Solution to question at 5:30 let n1=6,n2=-4 let add=(n1,n2)=>{ if (n1

[@ananthasri3324]

let doit = function(num1,num2){ if(num1>=0&&num2>=0){ console.log(num1+num2) } else{ console.log(num1) } } doit(50,-5)

[@heshamahmad4101]

let add = (num1,num2) => Math.abs(num1) + Math.abs(num2); let result = add(-5,-6) console.log(result)

[@anushadurgam7614]

let sum =(a,b)=>{ if (a

[@Nani-fm9dd]

let add = (num1,num2) => num1+num2; let a=Math.abs(5); let b=Math.abs(-7); let result = add(a,b); console.log(result);

[@joerowe9814]

great use of comments in the lower half of the screen. Nice pace. Not too long. I have watched a lot of bad videos trying to teach fat arrow functions and this is the best Thank you. @Telusko

[@it-095shivampatel4]

let n1=+prompt("enter first num"); let n2=+prompt("enter second num"); let sum =add(n1,n2); let add = (n1,n2)=>Math.abs(n1)+Math.abs(n2); console.log(sum);

[@mohakahuja8541]

let a=4;let b=* Math.abs(-6);let add=(num1,num2)=>num1+num2;let output=add(a,b);console.log(output);

[@mangoshala8174]

Thanks, I was a bit confused with arrow functions which you made it so simple to understand.

[@andreap9756]

Right! For me too.

[@digambarsawant1116]

let add = (num1,num2)=> (Math.abs(num1)+Math.abs(num2)) ; let result=add(5,-6); console.log(result);

[@alexkakhnovskyi4113]

he didn't mention one of the main features of the arrow functions. Arrow functions do not bind their own "this", instead, they inherit the one from the parent scope

[@sumanth1846]

Thank you so much sir , clear explanation love from telugu people

[@alinapeng8602]

Assignment answer: let add = (num1, num2) => { if(num1

[@AmeerMuawia-i4p]

5:10 let add = function(num1,num2) { if (num2 < 0) { let positive_coverter = -1; num2 = positive_coverter*num2; return num1+num2; } else return num1+num2; } let result = add(3,-8) console.log(result);

[@rahulgiri1253]

we can do different way- 1st way without inbuiled func:- let add=(num1,num2) => num1+(num2*-1); let result=add(5,-6) console.log(result) 2nd let add=(num1,num2) => num1+(-num2); let result=add(5,-6) console.log(result) 3rd way with inbuiled let add=(num1,num2) => num1+num2; let num1=Math.abs(5) let num2=Math.abs(-6) let result=add(num1,num2) console.log(result)

[@sidharthpillai]

I made the 1000th like. Thanks Navin. Having concepts simple and crisp makes it easy for daily learning.

[@thecreator9164]

last question answer: let add=(num1,num2)=>{ if (num1>0 && num2>0) return num1+num2 else return "Only positive numbers are allowed as input" } let result=add(3,-4) console.log(result)

[@tarundhati6499]

function add(num1,num2) { return num1 +num2; } num1 =10; num2 =-17; let result= add(10,-17) if (num1

[@kavalikishore-xg9wt]

let sum=(num1,num2)=>{ result=num1+num2; if (result>0){ console.log(`value is ${result} +ve`); }else{ console.log('enter correct value'); } } sum(5,6)

[@IMAYAVARABAN_SILAMBAM_ADIMURAI]

let t = (n1, n2) => (n1

[@pavelkundu5977]

const add = (a,b) => Math.abs(a) + Math.abs(b) console.log(add(-2,-5))

[@swapnilthakar7845]

var add = (num1,num2) => Math.abs(num1) + Math.abs(num2) var result = add(-10,-10) console.log(result) // it will print 20 .

[@abhishekns6802]

let add = (a,b) => { if (a

[@srinuvasu6747]

const sumOfElements = (a,b) => { let result = (a > 0 && b > 0) ? a+b : `input only positive numbers`; console.log(result); } sumOfElements(5,2);

[@srinuvasu6747]

any changes let me know brother thank you very much

[@anushapatel6043]

// Assignment // const add = (num1, num2) => { if(num1>0 && num2>0) { return num1 + num2 } else { return "negative number" } } let result = add(2,-3) console.log(result);

[@ishad17-ml1si]

let ans = (a,b) => { let num1 = Math.abs(a) let num2 = Math.abs(b) return num1 + num2; } console.log(ans(-78,22)); // 100 is the output

[@jaggu7714]

assignment ..... let user = (a,b) => a + b a= 1 b= 2 let result = user(a,b) if(b

[@Prashuva]

let add = (num1, num2) => { let n1 = Math.abs(num1); let n2 = Math.abs(num2); return n1 +n2; } let result =add(1,-14); console.log(result);

[@andreap9756]

After all this time, I can say I understand what the hell a arrow function is now!!!! Dude thanks :)

[@bharathreddy2350]

let n1=Math.abs(3) let n2=Math.abs(-4) let add=(n1,n2)=>n1+n2; let R=add(n1,n2) console.log(R)

[@kiran5432]

let add=(a,b)=>{ if(a>=0&&b>=0) return a+b else console.log("one of the input is negative") } let result=add(2,-3) console.log(result)

[@pradlife7987]

As usual - very well explained

[@barbarasanchezvasquez2242]

My answer of the exercise at 5:06: //By @iamsanbarb let add = (num1, num2) => num1 + num2; let result = add(Math.abs(5),Math.abs(-6)); console.log(result);

[@abroadlifestory193]

let a = Math.abs(6) let b = Math.abs(-7) let sum = (num1,num2)=> (num1+num2) let result = sum (a,b) console.log(result);

[@rudrasaiprasad]

let add = (n1, n2) => { if(n1 / (n1 * (-1)) == -1 || n2 / (n2 * (-1)) == -1) { return "-ve number alert" }else{ return n1+n2; } }; console.log(add(5,6)); this will give you the always positive output.

[@souravmandal3868]

The code for the assignment is: let add = (num1, num2) => { if (num1 > 0 && num2 > 0) return num1 + num2; else return "Can't add negative numbers"; } const prompt = require("prompt-sync") ({sigint: true}); let num1 = Number.parseInt (prompt ("Enter the first number: ")); let num2 = Number.parseInt (prompt ("Enter the second number: ")); let ans = add (num1, num2); console.log (ans);

[@alexissorianooo]

I challenged myself to use Ternary Operator: (it is not a best practice to use nested ternary operators) let addNeg = (num1, num2) =>{ return num1

[@LoU3107]

Whats the benefit in this case using an arrow function instead of function expression? For now, I see the difference is that you can save the brackets if its only 1 statement and you can remove the return keyword.

[@BigGus87]

its just shorthand. no actual difference

[@BigGus87]

you can remove the return keyword even if its a regular function btw.

[@mrgamerzyt3945]

let a, b; let func1 = (a, b) => Math.abs(a) + Math.abs(b); console.log(func1(2, -3));

[@AlexanderAlex-x2j]

7:31 let add = (num1, num2)=> { if (num1 > 0 && num2 >0) return num1 + num2 ; else console.log("Please add positive numbers only"); // return undefined; } let result = add (5,-6); console.log(result);

[@KanikaSri-o4b]

let hbd = (num1,num2) => num1 + num2 ; let ver = hbd(Math.abs(5) , Math.abs(-6)); console.log(ver)

[@codexakshay2348]

Assignment Question: let addPos = (a,b) => Math.abs(a)+Math.abs(b) console.log(addPos(-6,-3))

[@muralivelayudam8079]

let sum = function (n1, n2) { var result = n1 + n2; if (result > 0) { console.log("+VE"); } else if (result < 0) { console.log("-VE"); } }; sum(5, -6); //MuraliVelyudam//

[@satheesh1290]

what if (-5,6)

[@milankbudha]

let add = (num1,num2) => num1 + num2; console.log(add(5,6));//it will also work

[@amirhafidz5470]

let add = (num1,num2) => Math.abs(num1)+Math.abs(num2) console.log(add(6,-5))

[@sonujhariya]

let add = (num1, num2) => { if (num1

[@salauddinsallu4209]

let addsum = (num1,num2,num3=1) => { //arrow function return num1 + num2 + num3 } let sak = addsum(15,Math.abs(-6)); console.log(sak)

[@aswintr2052]

let add=(n1,n2)=>n1+n2 let rslt=add(-9,-6) console.log(rslt*-1)

[@asokthegreat7781]

let add = (num1, num2) => num2

[@cs.nolife]

let add = (num1, num2) => { return convertToPositive(num1) + convertToPositive(num2); } let convertToPositive = (num) => { return num > 0 ? num : num * -1; } let sum = add(10, -5); console.log(sum);

[@siddheshbhise2056]

let sum = (a,b) => { a = Math.abs(a) b = Math.abs(b) return(a + b) } console.log(sum(10,-20));

[@kevinkiprotich9502]

let addPositiveValuesOnly=(num1,num2)=>{ return Math.abs(num1)+Math.abs(num2) } let result=addPositiveValuesOnly(-6,5); console.log(result);

[@zeusheelantzu]

1. let add = (num,num1) => { if(num && num1 >= 0) { let result = num + num1 console.log(result) }else { console.log('Stay positive..') } } add(5,-6) 2. let add = (num,num1) => { if(num < 0) { num = Math.abs(num) }if(num1 < 0) { num1 = Math.abs(num1) } return num + num1 } let result = add(5,6) console.log(result) 3. let add = (num, num1) => num&&num1 >= 0 ? num+num1 : "Stay positive.." let result = add(5,-6) console.log(result)

[@InfoAnishGarg]

So useful, i always use this. Just love it 💕

[@coconut4974]

let negetive = (num1,num2) => { return sum } a = 9920 b= 50 sum = a+b if (a > 0 && b > 0) { console.log(negetive(sum)); } else { console.log("dont allow negative numbers"); }

[@asal3169]

let add = (a,b) => { if (a+b < 0){ return "the number will be less than 0" } return a+b } console.log(add(2,3));

[@rameenana]

Nice of you to make a video to help others. Though you seem to understand how to write an arrow function, I don’t think you understand the purpose of it. Use a Class in combination with .this That’ll help your audience understand the purpose of the code and then why you write it will make sense. And dude, don’t say things like “I know it doesn’t make sense but…” You can say that about an advanced topic you’ll cover in the future but you can’t say that about the core topic you’re teaching. Hope this helps. Good luck mate.

[@tektektuktuk4086]

Such a good explanation

[@jno1lilno]

so can you use a arrow function with more than one statement ? and if so do you still have to include the curly brackets?

[@smrpkrl]

yeah we can use arrow fucntion if it has multiple statements also..it's just that if you are using arrow function and your arrow function has only one statement, you dont need to use curly brackets and if your one statement arrow function returns something, you dont need to even write "return".

[@pooja_chowdari]

not only in arrow functions whenever you want to group multiple statements you have to use curly braces

[@rajarajang8713]

let add = function(num1, num2) { num1 = (num1 < 0) ? num1 * -1 : num1; num2 = (num2 < 0) ? num2 * -1 : num2; return num1 + num2; } let result = add(5, -6); console.log(result); is that right or wrong?

[@sivahb484]

Let add= (num1 , num2) => Math.abs(num1) + Math.abs(num2);

[@anandjha101]

Instead of num1* -1 you can do -(num1);

[@anandjha101]

@@sivahb484 good way to save lines

[@anandjha101]

@@sivahb484 but you should implement your own class and in that your own abs function

[@SnobbyLion]

GREAT explanation! Thank you!

[@elakkiyanandhini7974]

let addition = (num1,num2) => { if (num1 < 0 || num2 < 0) { return "Negative Numbers not accepted"; } return num1 + num2; } console.log(addition(3,-2));

[@sirojohnodilla9990]

let add = (num1,num2) => { if(num1 < 0 || num2 < 0){ console.log(`Negative Number detected!`) } else{ let result = Number(num1) + Number(num2) console.log(`The result is ${result}`) } } let num1 = prompt("Enter first number:") let num2 = prompt("Enter second number:") add(num1,num2)

[@MrTranimation]

Great tutorials man!

[@jno1lilno]

my guess let add = (num1,num2) => { console.log(num1+ num2); } let sum = add let result =sum(5,6)

[@AmeerMuawia-i4p]

let add = function(num1,num2) { if (num2 < 0) { return num1-num2; } else return num1+num2; } let result = add(3,8) console.log(result);

[@Ram-sm8pp]

const add = (num1, num2) => { num1

[@juliettemiso1521]

Returns the sum if both numbers are positive const add = (x , y) =>{ if ( x > 0 && y > 0 ){ return x + y ; } else{ return "please enter positive numbers" ; } } console.log(add(5 , 6));

[@SaravananVeeramaniiAI]

let add = (num1,num2) => { if(num1

[@VishwajeetSingh-mx8pn]

let add=(num1,num2)=>{ if(num2

[@aminalwamba2007]

this is amazing thank you so much

[@Mohamed-bu1yt]

This video is very useful and understandable thanks

[@DannyH77]

wow so much cleaner . thank you

[@ngawangtashi326]

let add = (n1, n2) => { function conv_n1(){ if(n1

[@Ananthasri-k2r]

let add = (num1,num2) =>{ if(num1 > 0 && num2 > 0 ){ return num1 + num2 } else { return 'Entered number is negative number you need to change' } } console.log(add(5,-1))

[@sivakishore5829]

let sum = (num1,num2) => num1 +(-(num2)); let result = sum(5,-5); console.log(result); VM1474:3 10

[@eheper]

Nice explanation.

[@KishorkumarAmuluru]

Using if else operator ------------------------------------ let sum = (number1, number2) => { if(number1 > 0 && number2 > 0) return(number1 + number2); else console.log("One of those number is negative"); } let result = sum(8,-2); console.log(result); Using Ternary operator ------------------------------------ let sum = (number1, number2) => { return (number1 > 0 && number2 > 0) ? (number1 + number2) : "One of those number is negative"; } let result = sum(8,12); console.log(result);

[@PR-kq3px]

let add = (num1, num2) => num1 && num2 > 0 ? num1 + num2 : "unvalid positive num"; console.log(add(5, 8))

[@charlestoneoyoo]

great explanation

[@vijayram5743]

let add=function(num1,num2){ if(num1

[@Sayem-y4h]

function numbers(num1, num2) { if (num1 > 0 && num2 > 0) { return num1 + num2; } else { console.log("The number is negetive"); } } let addition = numbers(5, 6); console.log(addition);

[@ganeshjaggineni4097]

NICE SUPER EXCELLENT MOTIVATED

[@saritharamagiri1634]

Hi Naveen, please make videos on reactJS it would be helpful.

[@TheTechCritic11]

SIR IS MACBOOK PREFERED FOR PROGRAMMING OVER WINDOWS?

[@dipersonmaharjan2015]

you can program on both but in my opinion because majority of the population has windows youtubers or others shows programming in windows.

[@shrshawn]

let sum = (num1,num2) => (num1 >= 0 && num2 >=0) ? num1 + num2 : (num1 >=0 ? num1 : num2); is this the answer? my logic is- only add nos if both are non negative. else return any no which is non negative

[@anandjha101]

Very easy questions for me because I have learned data structure and algorithms But I have learned my first programming language from you🥰🥰