26.xray.diffraction

[@AliAli-lb9hi]

Please. how can we use the XRD to calculate the N content in GaNAs?

[@junyang9698]

There's a mistake in the final equation. It should be nλ=2dsinθ for the constructive interference.

[@yanjundong3707]

I love you, you gives great explaination.

[@Hero101010]

Thank you for sharing, it really helped me understand this phenomenon :)

[@TheHarjaap]

i understand that we can calculate theeta and the wavelength of the X-Ray being used, but how do we know what value of n we need to substitute in? That value could be anything.... Please help

[@blahblah4159]

The number n i think is given by the computer that is conected to.the difractometer (it is a machine that uses xrays to find the structure of crystaline )

[@HT-rq5pi]

so technically speaking there is no diffraction that is actually used in xray diffraction crystallography? its is only scattering (which we assume to be reflection for simplicity)

[@richardp6upb]

is it not nlambda = 2dsin(theta)?

[@benninjin1427]

@Richard y You are correct nλ=2d sin⁡θ

[@betongitarre]

This formula seems to describe destructive interference, not constructive.

[@lucasleiva6145]

yes, acording to the picture it must be 2dsin(theta)

[@prasadvelidi9944]

from the diagram above path difference should be 2dsin theta

[@mendumofficial]

well im from germany, but god damn buddy, you saved me! awesome video, its perfect, thank you!

[@01rai01]

yes I get it! hate to Bragg about it.

[@mattfarrugia8831]

that is correct