3.76 | A throat spray is 1.40% by mass phenol, C6H5OH, in water. If the solution has a density of

A throat spray is 1.40% by mass phenol, C6H5OH, in water. If the solution has a density of 0.9956 g/mL, calculate the molarity of the solution.
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[@michaelfulkerson2400]

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[@xiaos3198]

This is a little complicated or am I just slow. why put 1.40 g? then why put 100g? (to cancel out 100?).

[@rameezmalik8263]

Yeah that's exactly right. So we are only given %mass (which is 1.40g) & according to the formula we know that %mass = (mass of solute / mass of solution) * 100%. So we aren't provided with the mass of the solute nor the mass of solution but we know that some variable value will give us 1.40 grams no matter what. So we try to logically figure out the mass of the two missing variables (mass of solute and mass of solution) by cancelling numbers out in the formula. So we have a 100 and to cancel that out we would need a 100 in the denominator. Mathematically 100/100 is 1 and this would leave the following formula: %mass (which we know to be 1.40 grams) = mass of solute * 1. Now, here we can just divide both sides of the equation by 1 to isolate the variable, mass of solute which gives us the following: mass of solute = 1.40 grams. I hope that makes sense :)