30-60-90 triangle example problem | Right triangles and trigonometry | Geometry | Khan Academy

[@TheGuitaristOfGod]

An easier way (I paused the video before Sal started solving) was to find BE first (BEA - 30/60/90 triangle), then find BD(same as above, this time in the BDC triangle). You then notice that the measure of angle BDE is 30 (complementary angle) which is the same as DBE (trisector). From these you can see that BDE is an isosceles triangle so EB = DE. After this you simply calculate the perimeter as usual.

[@j2zel]

Hello, question. At 4:13, after figuring out the length of BE, could you have also assumed the DE was of equal length since triangle BED has two 30 degree angles and is therefore isosceles? Meaning that BE and DE should be of equal lengths, correct? I think this would have been a simpler way of figuring out the length of DE.

[@nomekop777]

5:10 why are you so relatable

[@drorbenami]

no way, this is 9th grade math in the USA, possibly even tenth

[@samarth.patel21]

Why no way?We actually do and this the first level geometry

[@alexmisra6690]

How's life 9 years later

[@gjraymondd]

@@alexmisra6690 how's life 1 year later

[@godsprincess8975]

@@gjraymondd how's life 1 month later

[@gjraymondd]

@@godsprincess8975 lowk good af i’m graduated😭😭

[@JCTronia]

easy

[@jayianegiro2403]

how [square root of 3] became [3 square root of 3 over 3] ?

[@mathmagician155]

2018 anyone else

[@tagm5869]

How about 2021

[@ethanaarvig1174]

@@tagm5869 what abt 2022?

[@nocturnalvisionmusic]

@@ethanaarvig1174March 2022 :D

[@gjraymondd]

@@nocturnalvisionmusic April 2022 :P

[@nocturnalvisionmusic]

@@gjraymondd hey nice :D me too :)