3D Stress Transformation and Principal Stresses | Derivation & Example using Casio fx-115es plus

[@Avreyy]

Why do I pay an absurd amount of money for my ME courses when I'm not being taught by professors like this man. He truly understands the subject matter and can explain it (as I sit here watching because my professor did a piss-pot job at teaching it).

[@jaypark9826]

Your drawings are so easy to comprehend and visualize, I'm a postgraduate student and you are by far the best lecturer I've ever seen.

[@TheBomPE]

You are very kind! Thanks for the encouragement, and thanks for watching!

[@yohan1539]

The quality of this lecture is incredible. Before watching this lecture I was getting flattened by this module in Mechanics of Materials because it was so difficult for me to wrap my head around what was going on spatially/geometrically. You will be my primary out-of-class reference going forward.

[@Potentflowconsult]

You are a teacher of teachers. Thank you so very much!

[@TheBomPE]

I'm glad you found it helpful! Thanks for watching!

[@mimiemculu8449]

I wish I coukd like this 1000 times. THANK YOU

[@TheBomPE]

I'm glad you liked it! Thanks for watching!

[@osmanjantalipjan5608]

thank you professor . after I saw you tutorials i got the in advenced mechenical design exam 28/30. thank you a lot .

[@harshitrajput6865]

This is so good. You're so humble to your students

[@zarintasnim4406]

You're awesome! Explaining complex topics in a much easier way

[@TheBomPE]

Thanks! I'm glad you like the videos!

[@adnanahmed7385]

Haven't seen such a complex topic been explained in such a easy way .. Thankyou prof.♥️

[@TheBomPE]

I'm glad you liked it! Thanks for watching!

[@juancarloscubisino7411]

No doubt, best teacher in net. Congratulations and thanks a lot for sharing it!!!!

[@TheBomPE]

Thanks, you are very kind! I'm glad you liked it!

[@miyelanimculu3147]

Literally logged into my second account so that I could like this again (Crying graduation tears)

[@TheBomPE]

Hahaha, much appreciated! All the best in your career!

[@vilivont4436]

Wow, thanks so much, i couldnt find anywhere 3d stress transformation.

[@TheBomPE]

If you found this video useful, consider helping me upgrade the old tablet PC I use to create these videos! Thanks! www.gofundme.com/help-replace-my-2011-tablet-pc

[@메롱메롱-z1h]

Thankyou so much!! i got so confused from my professor's lesson but now i could fully understand!

[@TheBomPE]

Thanks! I'm glad it helped! In case you haven't seen them yet and might be interested, here are some of my playlists: ENGR122 (Statics & Engr Econ Intros): kzbin.info/aero/PL1IHA35xY5H52IKu6TVfFW-BDqAt_aZyg ENGR220 (Statics & Mech of Mat): kzbin.info/aero/PL1IHA35xY5H5sjfjibqn_XFFxk3-pFiaX MEMT203 (Dynamics): kzbin.info/aero/PL1IHA35xY5H6G64khh8fcNkjVJDGMqrHo MEEN361 (Adv. Mech of Mat): kzbin.info/aero/PL1IHA35xY5H5AJpRrM2lkF7Qu2WnbQLvS MEEN462 (Machine Design): kzbin.info/aero/PL1IHA35xY5H5KqySx6n09jaJLUukbvJvB (MEEN 361 & 462 are taught from Shigley's Mechanical Engineering Design) Thanks for watching!

[@pandeykabacha]

This was very lucidly explained. Thank you!

[@TheBomPE]

I'm glad it made sense! Thanks for watching!

[@richardsewell5159]

Thanks for putting this up, got it all now.

[@TheBomPE]

I'm glad you found it helpful! Here are some of my other playlists in case you haven't seen them yet and might be interested: ENGR122 (Statics & Engr Econ Intros): kzbin.info/aero/PL1IHA35xY5H52IKu6TVfFW-BDqAt_aZyg ENGR220 (Statics & Mech of Mat): kzbin.info/aero/PL1IHA35xY5H5sjfjibqn_XFFxk3-pFiaX MEMT203 (Dynamics): kzbin.info/aero/PL1IHA35xY5H6G64khh8fcNkjVJDGMqrHo MEEN361 (Adv. Mech of Mat): kzbin.info/aero/PL1IHA35xY5H5AJpRrM2lkF7Qu2WnbQLvS MEEN462 (Machine Design): kzbin.info/aero/PL1IHA35xY5H5KqySx6n09jaJLUukbvJvB (MEEN 361 & 462 are taught from Shigley's Mechanical Engineering Design) Thanks for watching!

[@garrettcrosby5846]

Man, stress tensors bring back some memories!

[@TheBomPE]

can you believe it has been a year since the launch of the channel?

[@garrettcrosby5846]

@@TheBomPE Dang, no I can't, it seems like just last month I was recording videos in University Hall!

[@tahermsherghi1911]

bad ones i hope or it is just me

[@QurbanAli-jd8bt]

your teaching skill is awesome.

[@TheBomPE]

Thank you! I'm glad it works well for you! Thanks for watching!

[@shvanmohammad4772]

Thanks so much, now I got it perfectly, I was confused with my text book. God bless you 🌹

[@abdullahelsherbiny8982]

I always say you are the best

[@TheBomPE]

Thank you! You are very kind!

[@zachrunner4490]

Really a good quality lesson I got it now, thank you so much.

[@TheBomPE]

I'm glad I could help! Thanks for watching!

[@MoviesMagicClip]

Wow 😮😮😮😮😮 amazing lecture ever🍻

[@md.zahidulsarkar8810]

Ow. What a lecture! Thank you.

[@cgrn181]

Firstly, thank you very much for the videos, I didn't give enough attention to these topics in time and now I realize that I need to study more and your videos are very helpful. One point I am confused is that at 18:26 you said that as theta_y goes to zero, normal vector will point towards y. However, this also implies that y component goes to zero. As we have F_y = F.cos(theta_y), actually theta has to go ninety degrees so that we will eventually have no F_y component. Am I thinking wrong?

[@behzaddastjerdy]

Thank you Dr. Swanbom for this amazing lecture. I was struggling to find the answer for this question : If we have only principal stress (magnitudes and orientation), how can we find the components of stress tensor?

[@siddharthjain4814]

Thanks a lot, prof. ❤️

[@TheBomPE]

Glad you liked it! Thanks for watching!

[@perdehurcu]

Hello. Sir, how can I find the complete solution of the determinant of the stress tensor? Can you recommend a book or video? Thanks.

[@nicolasscheggia5017]

Great lecture! I really enjoied it! I am looking for some information related to this topic and perhaps you could help me. My question is, is there any physical interpretation for the thrid invariant of the stress tensor? I have found physical interpretations for I1 and I2 and for the strain tensor determinant, but none for the stress tensor determinant. Thanks in advance!

[@arahhal61]

Amazing! Thank you

[@TheBomPE]

I'm glad you liked it! Thanks for watching!

[@oneofyk]

great lecture - thank you

[@TheBomPE]

You are very welcome, I'm glad you enjoyed it! Check out the playlists where I collect my course content if you are interested! Thanks for watching! ENGR220- Statics & Mechanics of Materials - kzbin.info/aero/PL1IHA35xY5H5sjfjibqn_XFFxk3-pFiaX MEMT203- Dynamics - kzbin.info/aero/PL1IHA35xY5H6G64khh8fcNkjVJDGMqrHo MEEN361- First 6 chapters of Shigley's Mech Engr design - kzbin.info/aero/PL1IHA35xY5H5AJpRrM2lkF7Qu2WnbQLvS MEEN462- chapters 7+ in Shigley - kzbin.info/aero/PL1IHA35xY5H5KqySx6n09jaJLUukbvJvB

[@magedqasem7403]

Thank you for your great explanation , but i was wondering if you have done a lecture on deviatoric stress topic .

[@TheBomPE]

I'm glad you liked it! Here is the lecture where I explain distortion energy failure theory... maybe it will help? kzbin.info/www/bejne/eZCyc3yEbNSdlZY

[@magedqasem7403]

@@TheBomPE Thank you

[@ukulelejim1]

Hi great video -thanks. When solving the cubic equation, why is the first co-ef, σp³, equal to 1? Thanks

[@TheBomPE]

I begin the derivation of the cubic equation to find principal stresses at 31:08 if you want to follow all of the reasoning. If you want to see where the cubic equation actually emerges, you can cut to 38:50. The coefficient of the cubic term is 1 because that is what emerges from expanding that determinant.

[@ukulelejim1]

@@TheBomPE Thanks for your response - I understand now. You're a great teacher! Thanks again

[@TheBomPE]

thanks for the positive review! I'm glad I could help.

[@genetichawk7419]

What is in-plane and out of plane stresses and how do we identify them?

[@azarangasadi1185]

how do you find the angles of the stresses?

[@TheBomPE]

I think what you want are direction cosines. They are the eigen vectors, so any tool you have at your disposal that finds eigen vectors is fine. I show how to do it with a Casio fx-115 es plus in this video: kzbin.info/www/bejne/pJ7NgaOYjthqnZY and I show how to do it in Mathcad 15 in this video: kzbin.info/www/bejne/bJnZfHZ4icuWbKM . I hope this helps!

[@amoko1992]

Where can I get more lectures by this professor??

[@TheBomPE]

I am that professor :) I am publishing my lectures on this channel as quickly as I can, balancing it with my other responsibilities. So far, I have most of my lectures posted from 3 of my upper level courses, as well as a good number of example problems from some freshman courses. I encourage you to check out my playlists where the content is organized: Dynamics: kzbin.info/aero/PL1IHA35xY5H6G64khh8fcNkjVJDGMqrHo Advanced Mechanics of Materials (first 6 chapters of Shigley): kzbin.info/aero/PL1IHA35xY5H5AJpRrM2lkF7Qu2WnbQLvS Machine Element Design (later part of Shigley): kzbin.info/aero/PL1IHA35xY5H5KqySx6n09jaJLUukbvJvB Is there a particular topic you are specifically seeking? Thanks for watching!

[@Huy21493]

if you can do an other video for the shear stress it would be much thanks

[@feedyourhead2661]

at 9:22 you said cosine is opposite over hypotenuse. remember SOHCAHTOA? cosine, adjacent, hypotenuse.

[@TheBomPE]

You caught me misspeaking, I'll admit. But in the very following sentence I move forward speaking of the adjacent side in conjunction with the cosine function. I'm not sure if you have ever tried to talk for an hour at a time on technical matters, but if you have, you know how easy it is to accidentally say the wrong word occasionally!

[@feedyourhead2661]

@@TheBomPE ya it happens.

[@mtyeniceri]

Thank you first for clear explanations in such a difficult and complex topic (at least for me). I wonder why you substituted Tzx = Txz, Tyz=Tzy and Tyx=Txy?

[@vimalvs291]

Complimentary stress values- which has same value in magnitude

[@miyelanimculu3147]

Can you do if its part of your scope yield and failure theory criteria

[@miyelanimculu3147]

Please

[@TheBomPE]

Have you looked through the playlist for this course? kzbin.info/aero/PL1IHA35xY5H5AJpRrM2lkF7Qu2WnbQLvS

[@Mr_Drones]

Sir I want to find the shear stress in the plane perpendicular to F and also it's direction. If anyone else can figure out kindly do response

[@himesenpai3980]

sir, did you state Tau xy means that a shear stress work in a plane Y- faces with X direction? or Tau xy means a shear stress work in a plane X-faces with X direction like the other peolple ? pls anyone can help ?

[@bober4279]

TAUxy is acting on the face perpendicular to X, in the Y direction

[@thomaskaszuba]

your z-axis isn't following the right hand rule. Top right of screen at about 4 minutes in.

[@thomaskaszuba]

ohh i see it now, you've drawn it from the back side.. onward

[@alandraalexandria6526]

31:33

[@아이쿠야-d6k]

헐 한국어 번역 있어ㅜㅜㅜ 영어로 보고있었는데

[@TheBomPE]

번역 했습니까?

[@아이쿠야-d6k]

@@TheBomPE I mistook. not translation of someone's but KZbin automatic translation system ㅋㅋ