4.4 Drawing Structural Isomers | Organic Chemistry

[@henrynwosu1]

Thank you so much I wish I started with you at=the beginning of the semester

[@ChadsPrep]

Glad you found us!

[@Meganisherelol]

THANK YOU SO MUCH! I have my first orgo exam tomorrow and you just saved me!

[@ChadsPrep]

You're welcome - I hope you do well!

[@bleouchieleazarsisso6158]

Truly grateful for your work!

[@ChadsPrep]

Thanks for saying so.

[@itsjaydajay]

Do you have a video on enantiomers? If not can you do one please!

[@ChadsPrep]

Ask and ye shall receive! This was set to be released later today but I just released it early just for you! 5.1 Overview of Isomers | Constitutional Isomers and Stereoisomers kzbin.info/www/bejne/p2TChnWIgN-efrM I'll be releasing the remaining lessons in this chapter throughout the week which include the following: 5.2 Absolute Configurations - Assigning R and S 5.3 Molecules with Multiple Chiral Centers 5.4 Fischer Projections 5.5 Isomeric Relationships Between Molecules 5.6 Amine Inversion and Chirality without Chiral Centers 5.7 Optical Activity Happy Studying!

[@itsjaydajay]

@@ChadsPrep Omg! Thank you so much! we're covering this topic now and I needed this

[@samantha.907]

What a Chad!

[@ChadsPrep]

Welcome to the channel.

[@bd7636]

I was wondering if I could get further explanation on the last example with the 3 carbon chain. Why would attaching the O at either end with the carbon in the middle be the same? I don't know if that made sense but thank you so much for these videos they help a lot

[@ramunasstulga8264]

You would get the same structure above the 3 carbon chain.

[@3456heyheyhey]

Well my professor gave us C5H11Br and that is not saturated and now I'm confused on how to do this

[@ChadsPrep]

I'd have to see the question, as this seems to be bromopentane

[@vladimyrhilaire1023]

Couldn't another example include cyclic carbon chains?

[@ChadsPrep]

Hi Vladimyr! A ring incorporates a degree of unsaturation having 2 fewer hydrogen atoms. The last two examples were both saturated hydocarbons so cyclic carbon chains would not have worked. If you draw one out you'll see that it must have 2 fewer hydrogen atoms. Hope this helps!

[@vladimyrhilaire1023]

@@ChadsPrep thank you

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Thank you

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THAAAAAAAAAAAAAAANK U

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