love the channel! but I want to confirm that at 20:39 the answer is 4m/s not 16m/s, since you need to take the square root. thanks again for all the help, I really love the channel
@killab5952 Жыл бұрын
Thank U Sir, U are really taking the stress outta learning science, all the way from South Africa
@ChadsPrep Жыл бұрын
Excellent and Welcome to the channel.
@brendam4159Ай бұрын
fr tho. like why can’t my teacher be like this. thank you teacher
@munoss-u19 күн бұрын
mr superhero you rock! you really made it clear in 27 mins while my prof cant in 15 weeks!! thanks a lot
@ChadsPrep18 күн бұрын
You're welcome - glad the channel helped you!
@tuckerlanoue956010 ай бұрын
Thank you so much! Super helpful for my exam. I do have one question: Should V1 (written down at 19:29) be squared, as in (V1)^2? And if so, would 16m/s be square rooted, providing a final answer of V1=4m/s?
@Joshua_mwale10 ай бұрын
I also think so.
@killab5952 Жыл бұрын
Thank you a lot sir, you are really taking stress outta learning science, Big ups! all the way from South Africa
@ChadsPrep Жыл бұрын
You're welcome - thanks from USA.
@kileyadams3831 Жыл бұрын
Should the answer for the first example problem be 4? What happed to the v^2, we didn't square root either side. Thanks for the help Chaddy Daddy, you always help me bounce back!
@qaisar.sulaiman Жыл бұрын
Yeah it should be sqrt
@ChadsPrep Жыл бұрын
Hey Kiley! That first question @16:30 aswer is x = 0.5. Were you talking about a different problem? if so let me know the time stamp
@nadermunye4879 Жыл бұрын
20:33 the answer should have been 4 instead of 16? I think you forgot to square velocity@@ChadsPrep
@nadermunye4879 Жыл бұрын
also I would personally like to thank you for being a godsend in my physics and organic chemistry classes. You single handedly got me through ochem now you're getting me through physics.
@ChadsPrep Жыл бұрын
@@nadermunye4879 Glad to hear it - Happy Studying!
@terryrodgers956018 сағат бұрын
For problem 2, I used work and got 4m/s, why is that incorrect? Xf = 0, x0 = .1
@alibilginler Жыл бұрын
13:30 always applied force=− restoring force and applied force=kx , right? 🙂😊 thank you teacher chad
@ChadsPrep Жыл бұрын
Correct!
@NahAtoh Жыл бұрын
Thanks for the great work sir
@ChadsPrep Жыл бұрын
You are welcome.
@nikotmt17399 күн бұрын
very good
@ChadsPrep9 күн бұрын
Thank you
@sirenofamphitrite46129 ай бұрын
26:16, why is the PE gravity final not a negative force, since gravity is pulling it downward?
@JenanAlfar2 ай бұрын
The gravitational field points downward, but we define the gravitational potential energy relative to a reference height. If you are calculating how much energy is stored at a height ℎ above some reference (say, the ground), then h is positive when the object is above the reference point, and so is the potential energy.
@trexclan84053 ай бұрын
I love u bro. Thx for your help
@ChadsPrep3 ай бұрын
You're welcome!
@xinyansheng80282 ай бұрын
why does the elastic potential energy equal to the work..?