5... (A Level)

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[@mrextremelycute6679]

We use the cosine rule so... BC^2 = r^2 + (2r)^2 - 2*r*2r*cos π/6 = 5r^2 - 4r^2 * √3 /2 = √5r - 2√3 r therefore BC = r√5 -2√3

[@GingerMathematician]

Really well answered, your understanding is clear and concise 😀👍

[@hoel9327]

Solve with cosinerule and in the end we have to underoot R and take it common

[@GingerMathematician]

Exactly

[@ibrah1m_sent1ent]

OMG MY FAVORITE KZbinR IS SMART TOOOO??

[@thefallen1383]

Is it allowed to do something like - let line CL perpendicular on OB, forming two right angled triangles, and then work from there or not?

[@GingerMathematician]

This is also a good way to start the question 😊👍

[@clapzylol]

Sir can we use logs for this type of question in the igcse exam: 3 power x = 729 solve for x?

[@GingerMathematician]

Yes you can but not taught on 0580, just 0607

[@clapzylol]

@@GingerMathematician So we just use the indices rule right?

[@ajfcrew2858]

5 Days remain :(

[@GingerMathematician]

Not long!

[@hummus2275]

cute pfp