5 CHEMICAL STOICHIOMETRY | MOLE CONCEPT | Chemistry By ALK Sir |IT JEE Main and Advanced

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CHEMICAL STOICHIOMETRY | MOLE CONCEPT | Chemistry By ALK Sir | IIT JEE Main and Advanced
#Admission_Online_Offline_Batch_7410900901 #Competishun
This is the 5th lecture of mole concept on Chemical Stoichiometry by ALK sir .The detailed explanation of the lecture with time stamp is :
00:00 -03:51 Chemical stoichiometry - It involves calculations of amount of reactants products involved in a chemical reaction
A+2B -------------C+D (balanced)
In general aA+bB--------cC+dD (balanced)
a,b,c,d are the stoichiometric coefficients
03:52 - 06:24 Example 1- Al+ 3HCl (aq) ---------AlCl2(aq) + 3/2 H2(g) (ratio 1:15)
(1:3)
or
2Al+6HCl------------------2AlCl3+3H2(g) (ratio 2:3)
(1:3)
06:25 - 08:36 Example 2- KClO3(s)-----------KCl(s)+1.5O2(g).5 moles of KClO3 is given calculate number of moles of O2
Calculate the according to stoichiometry.1 mole of KClO3 gives 1.5 mole O2 .So, 5 mole KClO3 gives 1.5*5 mole =7.5 mol O2
08:37 - 14:42 Problem 1 : Combustion of methane ,8 g of methane undergoes combustion in excess of O2.Find mass of products formed .Also calculate mass of O2 needed to do complete combustion.
Solution: CH4+O2------- CO2+2H2O (balanced).There is 0.5 moles of CH4 so we need 2*0.5 moles of O2 i.e. 32 g of O2 .0.5 mole of CO2 will be formed so there will be 0.5*44 g of CO2 formed and 22.4*5 litres of CO2.In case of solods and liquids use Volume=mass/density .Volume of H2O =mass/density =18/1=18ml.
14:43 - 18:47 Problem 2 : Find volume of gases evolved if 0.5 mol of lead nitrate is strongly heated to give NO2 and O2 gases.
Solution: 2Pb(NO2)3 (s) ----------------- 2PbO(s)+4NO2(g)+O2(g) (balanced)
0.5 mol 1 mol 0.25 mol
Total moles of gases=1.25 So total volume of gases at STP is 1.25*22.4 litres
18:48 - 21:10 Problem 3 -13.5 gram of metal is dissolved in excess of H2SO4 solution find volume of H2 gas evolved at STP.
Solution: Al(s)+3H2SO4(aq)--------------- Al2(SO4)3(aq)+3H2(g)
0.5 mol of Al so 0.75 mol of H2.So volume of H2 at STP is 0.75*22.4 litres
21:11 - 21:27 Formation of chemical formula of compounds
21:28 - 24:58 Simple stoichiometry Problem 4 - Find mass of oxygen needed in kg for complete combustion of butane (1 kg)
Solution :C4H10 +6.5O2------------- 4CO2 +5 H2O (balanced).1000/58 moles of C4H10 will need 6.5*1000/58*32/1000 kg.
24:59 - 26:56 Note- Nitrogen in organic compund does not form nitrogen oxide during combustion
This is the 5th lecture of mole concept in which ALK sir taught about chemical stoichiometry with the help of 2 examples and 4 problems.These topics require more problem practise than theoretical understanding.This lecture covers all aspects of calculation of weight of different compounds in a chemical equation with the help of stoichiometry .Many small concepts and key points are also explained by ALK sir in this lecture.
This lecture is a must watch for students of class 11 ,12 or dropper of science steam preparing for IIT Jee, Mains and Advanced .This lecture is very important from Jee point of view and will help students solve Jee mains and Advanced Stoichiometry problems effectively.
CHEMICAL STOICHIOMETRY,
MOLE CONCEPT,
CHEMICAL STOICHIOMETRY ALK Sir,
MOLE CONCEPT ALK Sir,
Chemistry By ALK Sir,
IIT JEE Main and Advanced,

[@rishabhjoshi3142]

if any 11 grader is watching this now and you feel a little confusing, it's not a problem just see what sir is doing, and whenever you'll get in 12th if you see these lectures for revision you'll realise how much has jee preparation evovled you..

[@satyaraj1005]

Thanks a lot

[@pranjalthapa542]

Thanks. Iam feeling the same

[@bobbyanand5608]

i am in 11th but not feel confusing

[@avinashkashyap9316]

Yes i agree.....

[@priyanshu7090]

wish someone told me this when i was in 11th rather than discouraging me

[@frontierhazarika4941]

Finaly found the gem of Chemistry. Thank you sir.

[@anant-strong]

5:52 Most important concept of the video 😆🙏🏼 26:04 aree sir me hamesha yahi galti krta hu NO² nikal deta hu

[@Vipinkumar-co6zp]

Excellent explanation

[@warisbashir8272]

Thanks for your support ❤️🙏

[@vedantmishra5773]

Waiting for your class 12th videos sir

[@alokrichhariya_]

Thanks a ton

[@vipul4571]

thanks sir

[@amitsingh2782]

Thanks sir

[@manikumar8873]

🙏 Thanks 🙏🙏

[@dream_alone]

thank you sir ❤❤❤❤❤❤

[@user-zc2hr6dc6d]

AWsM

[@user-zz3hk4rq9g]

How to do calculation fast Please give tips

[@udhamsingh6922]

good

[@ajeetadwell8124]

sir you deleted the 6th video from playlist...then how can i see the stoichometry video on mixing problem

[@fxeditors]

Thanks

[@unknown-tw6zz]

Give the rules given by fajans in order to explain partial covalent character of ionic bond sir please give answer

[@Jee_anthem]

It's in chemical bonding

[@nopainnogain5625]

Sir in 2 questions you have taken out the volume of the gases using the formula "moles × 22.4 L" but sir isn't this formula applicable at STP condition only. Whereas no where in question it was mentioned that reaction is taking place at stp conditions. So by default we'll assume room conditions. So in that we should not use that formula. Please clear my doubt sir. Edit: For eg: at 18:20

[@muhammed5667]

rarely sometimes lecturers miss out on explaining very minute details, in those cases you have to assume information and proceed w/o questioning unless it's a doubt

[@aryanmehra7159]

@@muhammed5667 ok muhammed

[@stranger1111]

24/01/22-3:30 pm

[@siddharth1451]

Sir last mai aapne oxygen ka mass likha hai 32 g O2 hai to 64 g likhna tha n?

[@shreyaranisuri5669]

Sir in the question, find the mass of oxygen needed in kg for complete combustion of butane(1kg) ? Can we balance the equation like this :- 2C4H10 + 13O2---> 8CO2 + 10H2O? Please reply sir.

[@kajaljaipuria8387]

Ha bro kar sakta hai

[@ashwani9032]

Sir your 6th video on mole concept is missing cuz KZbin is saying that it's deleted, please review sir!

[@yatinshekhar787]

Its in the last of the playlist

[@ayushsarangi4095]

Sbse last me h playlist k

[@stranger1111]

jan 2

[@ChandraPrakash-dq9bh]

8:09 sir na kcl ka molar mass 3+35.5 kyu likha hai......39+35.5 hona chaiye na?

[@punnu13141]

Galti se likha gya h

[@RonakAnand-ot8yu]

Bhai vo 39 hi likha 3 ke sath g nahi hai dhyan se dekh

[@diyasharma1143]

Volume of CO_2 =11.2 litre

[@shook3487]

5 Done

[@AshishKundu-un7yz]

Bhai for fast balancing of combustion CxHy +( x+y/4)O2....…............... XCO2 + y/2H2O

[@missioniitian7942]

Sir when early bird sale ends

[@MohitTyagi]

Different for different batches. To join or for any information you can visit our website: competishun.com OR visit our app competishun on playstore All the best

[@ashutoshgupta5193]

There is error in last question moles of O2 will be 1.5 not 6.5 please check it

[@pratibhakabra688]

No its 6.5

[@bobbyanand5608]

it must be 6.5

[@bjha4295]

Normality ke bare me sir ne kis lecture part me bataye hai .someone pls tell me

[@shashwatchaitanya9956]

Redox reaction and Equivalent concept wale playlist mein bataya hai

[@Hrs15.....]

How to know that H20 is in liquid form 12:40 Anybody explain me that why sir divided with 1000 to 32 at 25:01

[@aimvsdream]

To convert it to KG ..we have to divide by 1000

[@HARSHVARDHANSINGH-yr3ds]

Sir i can't afford praveen 2. Can i get good marks in jee mains in jan session only from ur KZbin and hc verma, past years arihant maths, n awasthi p chem, ms chauhan organic? I will try to do it multiple times. And join some test series and also revise again and again whatever I hv done so far once a week. Can I get NIT wid this strategy?

[@migompegu4618]

Aree bro sir bohot baar keh suka hai.. video is for jee advanced not only mains....

[@samarthsahu2893]

The books you have mentioned are good enough for Jee Advanced too . I have seen people do well in mains by preparing really well from NCERT( Text and exemplar) along with pyq. About ms chauhan for organic, even its level 1 exercises often get beyond the scope of mains, but always worth the effort if u aim big in the long run! Good luck

[@HARSHVARDHANSINGH-yr3ds]

@@samarthsahu2893 thank you

[@sankararaotoorubilli8756]

@Harsh Kumar Singh how much bro

[@ShivamJee-vd3mk]

Sir apke lecture kai baad practise kis book Sai kare ?

[@aadit1624]

Sir always suggests using Competishun (or his digital book whenever he releases it) or any other modules. Competishun has pretty much copied Resonance modules, which are easily available as pdf

[@iitjeeaspirant3328]

Sir..plz tell me... kya aap koi schedule follow kr rhe ho lecture upload krne ka ya fir randomly upload kr rhe ho...plz tell me.🙏🙏

[@missioniitian7942]

Ramdomly

[@nikhilraj84677]

NCERT mein chapter ka jo sequence diya hua hai, usko follow karke lecture dekhiye, chahe sir sequence mein lecture upload kare ya randomly

[@fakhraafrin7659]

16 March 2023

[@vacoder]

Sir laws of chemical combustion hai na questions hai kuch v nhi hai ye sirf jinhone padh rakha hai unke liye revision hai... freshers ke liye it is not good

[@vaibhavsahu916]

What you have written please tell Law of chemical combination sir n cover nhe kea h kya

[@shibuprabhan]

sir i have seen in many reactions sir puts "arrow" in side of compound . sir pls say what it mean sir pls sir......

[@user-zc2hr6dc6d]

Gas...or effervescence

[@ajaygoyal5592]

Upper arrow means that the product formed is a gas while the downward arrow indicates the formation of a precipitate

[@_d_ghosh_]

Any 2026 aspirant here?

[@PheonixGaming-ys2pb]

Yeah yeah yeah😂

[@sajwanadityaa]

lecture se zaada toh ads dekh liye bhai

[@MohitTyagi]

You can study from our free batch PAARAS, which is available on the TEAM COMPETISHUN app. We have created this batch specifically for KZbin students who face difficulties due to ads and distractions while watching videos on KZbin.

[@sonukumar-xb1hk]

at 15:38 🐕 dog barks 😂

[@yashyadav1765]

Important 12:50 !!

[@vishal.saxsux]

Lagta hai sir k ghar mei Rajma pakk rahe hai😀

[@mukeshsuman9306]

jee 2023 or jee 2024 bhai ??

[@rambharose_yatra_company99]

Re babu jawan situation ko blame krta hai n u pagla h uska koi bewhar nhi rh gya h isiliye east or west MT the brand

[@shaileshsinghxiscience6626]

Sir itna ad kyu dal rha hu

[@wolfiscrazy3179]

Terko ye sab ye teachers free m de rhe hai aur terse ad dekhi nhi jaati . Mtlb koi kitna selfish ho skta hai 😑.

[@mukeshsuman9306]

@@wolfiscrazy3179 exactly bhai , same thoughts .........

[@dibyajyotimohanty180]

14:32 why 18ml Why not 18lit

[@vatsal512]

Density kisme diya h woh dekho pehle ussi hisaab se volume ki unit hogi

[@laxmanaaglave3952]

Density is in g/ml so volume is in ml only

[@RanbirSingh-bl9fb]

Thank you sir