54 - Solved Problems on Magnetic Circuits

54 - Solved Problems on Magnetic Circuits
In this video, we are going to solve simple problems on magnetic circuits, before we consider the more complex examples in the subsequent videos.
A magnetic circuit is made up of a closed path where a magnetic field represented as lines of magnetic flux are confined.
Given a magnetic circuit composed of iron core and an air gap, lets assume that a coil of N turns is wound around the iron core. The current in the coil produced by the voltage generates magnetic field around the core which in turn sets up magnetic flux within the circuit. This flux is same throughout the iron and air gap.
the source of the magnetic circuit is called - mmf -magnetomotive force
Resistance - Reluctance and
Current - Magnetic flux
F = IN, I = current in the coil, N = number of turns pf the coil
H = F/l - magnetic field intensity
B = flux/A, magnetic flux density
F = flux (Ra+Rc)
F = Fa + Fc .

[@saifromearth]

For the first example you could've just found the reluctance and multiplied it with the the flux to get the mmf right? Its so much easier

[@willbeehbardaniell]

Definitely I was like oh no why long dry 😂😂😂

[@willbeehbardaniell]

Good video ❤

[@SkanCityAcademy_SirJohn]

Thanks so so much

[@clivemwanza5719]

When calculating the area since its squared the value of the area should be raised to the power -9 since we are squaring the 3 or maybe there is something i aint getting

[@SkanCityAcademy_SirJohn]

mm² to m² is 10^6

[@elizabethdonkor3016]

If i don't know the famula how can i solve them

[@bentha5667]

In the last question, why did you use the value of permeability of air instead using the permiabilty of wood? They are asking about the wood, and you used the equation for air. Permiability of wood hasn't given in the question, still, if you have made an assumption, you should have mentioned in the video. Could you please help me with that?

[@SkanCityAcademy_SirJohn]

The reason is that non-magnetic materials such as wood, plastic and the rest have permeability almost equal to free space. So we just use the value for free space.

[@ngunedevine-ks5hf]

@@SkanCityAcademy_SirJohn 👍

[@SkanCityAcademy_SirJohn]

Thanks

[@elyboyfernandez1219]

How did u get the 10^-3 m and 10^-4m?

[@SkanCityAcademy_SirJohn]

for 10^-4, 1cm = 1/100m = 10^-2m, hence 1cm * 1cm = (10^-2)*(10^-2) = 10^-4m