Earliest Deadline First (EDF) Part-2 Explained With Example in Hindi l ERTOS Course

[@mtariquegauri]

Length of gantt chart is determined by calculating the hyper period which is the LCM of periods of Task 1 and Task 2 => (2,5)

[@aryan00008]

Boht boht boht jyada achhi explanation 👏👏👏👏👏

[@Anime_Edits_TN]

At the last 8 to 10 instant, T1 takes 0.9 seconds that takes more time than the remaining 0.2 seconds of the T2. Therefore, the task that is more prone to failure of execution (larger task - T1 is executed 1st)

[@AadeshingaleOfficial-zl5fd]

Nice Sir 😊

[@siddhantmeru8863]

Good job sir ✌

[@shakilahmad2282]

Very creative method. Kindly share implemented code for this in any language like java, c or Matlab. Will be thank full too you dear.

[@AB-np6qu]

Thanks for this video 👍👍

[@_S_khan_]

T2 will not execute after 4 unit because at 4 stage T1 will get ready after T1 4.0 to 4.9 T2 will execute. One thing Note Closest deadline and priority both are equal in this question but *always it will execute according to closest deadling in EDF.

[@pranaybatta9998]

No it will not because t2 deadline is 5 and t1 deadline is 6 and the name of the algo is earliest deadline first

[@siddhantmeru8863]

Upload more video's 🎥

[@charchitmangal]

Thank you sir

[@omprakashswami1230]

I want to send the soft notes of network security and wireless security

[@rishabhsharma9630]

ok

[@shubhankkulshreshtha2195]

Grttt

[@mariatariq6843]

Hmny 10 tak q lia

[@rishabhsharma9630]

Lcm of 5,2