A body of mass `6kg` is under a force which causes displacement in it given by `S= (t^(2))/(4)` maters where `t` is time . The work done by the force in `2` sec is
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@AfifaJavidАй бұрын
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@Shahid1262313 күн бұрын
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@shivamkaparwan79763 ай бұрын
Work done is force × displacement why did you use velocity in place of displacement??
@Ankit-gf4zg27 күн бұрын
Actually s=(t^2)/4 is given ds/dt = (2t/4) Therefore, ds = (2t/4)dt Now put the value of ds in workdone formula and put the limits You will get the answer
@s.s.kgamer68994 жыл бұрын
Please tell that v=2t/4 kasa hua muj ko samaj nahi aaya
@orggordenofdreams17793 жыл бұрын
By differentiation. Consider t² as xⁿ ,use nxⁿ-¹ u will get it