A Closed and Bounded subset of a Metric Space need not be Compact |L30| Compactness @ Ranjan Khatu

[@mathstoall]

Nice sir

[@mathsrelated]

Nice explaination which I had never seen before

[@ankitasangwan4396]

Nice explanation.

[@sayanchatterjee8936]

Very nice explanation sir thank you 😊

[@SRajagopalrajagopal]

Your all videos are tremendous nice

[@mamathematicsyahyamoayad1312]

Thanks 🙏🏻 ❤

[@shashank_kishore_]

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤

[@SRajagopalrajagopal]

My doubt is suppose we wish to prove any set is compact X contained in union on finite sub cover but you written as [0,1] union of open sets i.e [0,1] = U{xi}

[@dyj2968]

Sar Aapko Hindi nahin aati kya please Hindi mein video bnao

[@sumairah_80]

no, i think he is from south india specially from (KL or TN or AP/TG) so can't speak hindi properly