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This is Part 2 of my talks on Atmospheric Pressure near the Surface. The key basic issue is: does air pressure near the surface change with the surface temperature? Another seemly irrelevant issue is why the tropospheric height decreases from the equator to the two poles? It turned out that both issues are correlated and dependent of local surface temperature. Enjoy watching this new discovery!
It is often argued that the air pressure at near the surface can be calculated by adding the weight of all air molecules in a vertical column with cross-section 1 square meter.
6.It sounds plausible as, after all, each air molecule does have its weight due to the gravity, first formulated by Issac Newton. But the more you contemplate it, the more odd it would appear, as least it happened to me.
7.For liquids or other condensed matters, in which all molecules are closely packed one-by-one, or shoulder by shoulder. By way of contrast, air molecules are in random movements all the time, and, hence, can hardly have chance to exert an downward force together. So, it seems not very convincing that the total weight of spatially separated molecules be weighted, say, by an electronic balance like this.
8.Another question. If you look at this diagram for the global circulation, you will notice that the troposphere is getting thinner from the equator to poles. Why?
9.For quantify this phenomenon, I googled the relevant numbers. Here it is. “The height of the troposphere varies from the equator to the poles. At the equator it is around 11-12 miles (18-20 km) high, at 50 °N and 50 °S , 5½ miles and at the poles just under four miles high.” That’s to say, the thickness at poles is only one-third of that at the equator. So, this diagram is roughly accurate.
10.So the two questions were my concern last night. When I had my coffee this morning, it occurred to me that the two questions can be answered together by using an extrapolation method, similar to how Lord Kelvin deduced the absolute temperature scale in 1848 from systematic gas experiments.
11.Here are the details. First, imagine the surface temperature could be reduced near the absolute zero, zero K, similar to to the Bose-Einstein condensation, of course, it’s conceptually different, all thermal motions would stop and all air molecule would become condensed matter. And hence could be weighed. In this imagined scenario, everyone will be convinced that that the surface air pressure is the total weight of air molecules above the surface, due to mass conservation.
12.Second. We know the surface temperatures at the equator and a pole are about 300K and 200K, respectively. If I assume the dependence of the tropospheri height on the surface temperature is linear, and hence would be close to zero when the surface temperature is absolute zero, as shown by this blue line.
13.Unfortunately, the slop is too small compared with the trend line in green. By extrapolating the trend line toward lower temperature, as shown by this dashed green line, we can see the intercept is well above zero K. What does this mean?
14.Then I realized why. We know nearly 80% air is made by nitrogen. And liquid nitrogen is 77K, I knew this quite well as I often used liquid nitrogen and liquid helium to do magnetic resonance spectroscopic experiments in the 90s. This implies air would almost become liquid around 77K.
15.Indeed, the intercept is close to 77K! What at So I replaced the first straight line by this linear equation by assuming the thickness of troposphere near the equator is 16 km.
17.Where H represents altitude in km and T is temperature in Kelvin. Notice the slop simply means if the surface temperature increases 1K, the thickness of the troposphere would increase about 70 meter.
18.If so, can this number be explained by basic law in physics? Before my coffee getting cold, I used this pen to work out this explanation.
19.The linear dependence of the height, or the thickness, of troposphere on temperature in Kelvin implies both sides of the equation may represent energies of different types, because kT is how much energy each degree of freedom in an air molecule can have in thermodynamics, where k is Boltzmann constant.
20.Obviously, the constraint for the atmospheric height is caused by gravity, Newton’s gravity, not Einstein’s geometric curvatures. Therefore, it is reasonable to make the left-hand side as gravitational potential energy.
21.Consider one mole air with its mass 29 g in an imagined thin layer at height H. How could the air molecule move that high from the surface? By directly transforming its kinetic energy gained near the surface into gravitational potential energy, or through multiple relay processes.