By inspection I would say that x=50i, so x and -x lie on opposite sides of a circle centered on the origin of the complex plane. Then √x=(5√2)(√2/2)(1+i) and √(-x)=(5√2)(√2/2)(1-i) and √x+√(-x)=(5√2)(√2/2)+(5√2)(√2/2)=10.
@Geendle13 күн бұрын
Hi, thanks for sharing!
@didles12317 күн бұрын
My thinking is that √x+√(-x) = √x ± i√x = (1±i)√x => √x = 10/(1±i). No substitutions here, just brute forcing it.