One quick correction that does not affect the analysis or result. 4^5 = 2^10 =1024, NOT 1025. So the rejected result would be x = -768, NOT -769. It is very obvious. 4 is an even number, so any power of 4 will also be even. 1025 is odd and must have a root of 5 in it somewhere, and all roots must be odd.
@UKPEINDANIELU.4 ай бұрын
Fantastic
@geralynpinto59714 ай бұрын
Thanks so much. I enjoyed this problem and your clear explanation.
@user-gr5tx6rd4h4 ай бұрын
I saw in about 5 seconds that, since 32^(1/5) = 2, x = 256 is an answer, since sqrt(256) = 16, so that the second root will be 0 and the first wil be 2. (This doesn't tell if there may be other solutions, though)
@anatolykatyshev93884 ай бұрын
Easy solution. Function define on 0
@indiaxyz4 ай бұрын
Could x be 225? So eqn would be 5√(16+ (-15) ) + 5√(16- (15) ). As sq root of a number can be + or -
@21065224 ай бұрын
Cannot be. Only +.
@Hrishi020054 ай бұрын
X=256
@himadrikhanra74634 ай бұрын
X= 16^2 .?...
@IMAN_IIT_PATNA4 ай бұрын
Ye to oraly ho gaya 😅
@мехралиахмедов4 ай бұрын
4х4х4х4х4=1024, а не 2025
@tejpalsingh3664 ай бұрын
Need 2 out from nest... So , √ x= 16
@supriyomondal69004 ай бұрын
Sir ji 4^5 = 1024 hota hai aap ko 1025 kaha se mila ? Vedio banane se phele thik se home work kijiye.
@tanuahuja11023 ай бұрын
Video ki spelling to aati nhi hai, tu pehle apna homework karle