A nice weekend integral

[@yurfwendforju]

5:12 "Math is much easier than talking." Words to live by

[@الْمَذْهَبُالْحَنْبَلِيُّ-ت9ذ]

It's funny how we delude ourselves into thinking "digamma(1-1/a)" is any more informative than the initial integral LOL

[@gchu_]

Incredibly cool!

[@Anonymous-Indian..2003]

It's also equal to summation(k= 2 to ∞), ζ(k)/αᵏ means, ζ(2)/α² + ζ(3)/α³ + ζ(4)/α⁴ +..... α > 1

[@CM63_France]

Hi, "ok, cool" : 0:17 , 4:12 , 8:07 , "terribly sorry about that" : 2:11 , 2:31 , 5:42 , 7:45 , 7:59 , 9:24 .

[@aravindakannank.s.]

6:10 Something never gets old 😂 Either way a good way to start making contents again 😊

[@cdkw2]

some things never get old

[@alfredcognoet]

Have you done int(-1,1) e^x/sqrt(1-x^2) dx? I was doing a similar integral and found out its part of the Bessel function, id like to see the connection (or if youve already done a video on it)

[@MrWael1970]

Thanks for your innovative video.

[@SuperSilver316]

So it’s also just a harmonic number then? Digamma(z) + gamma = HarmonicNumber(z-1) So the final expression would be -1/a*HarmonicNumber(-1/a)

[@sundaresanabishek5127]

Broo it's so nice to here "OK cool "😂❤

[@Akhulud]

Did you ever do integral from 0 to infinity of sin(u)sinc^3(u)du ? Wolfram Alpha says it's ln(2) but I wasn't able to prove it

[@rakib_hoque]

lim (ln(x)-W(x)) ,x→♾️ W(x) is the Lambert W function please do this limit 🙏

[@giuseppemalaguti435]

A me risulta I=(1/a)(ψ(1)-ψ(1-1/a))=(1/a)(-γ-ψ(-1/a)+a)...ma è tutto da verificare ah ah...per a=2,a=3 è corretta

[@orionspur]

𝛙-op!