A tricky Stanford Exam Question | Nice Algebra Math Simplification

[@RealQinnMalloryu4]

60/30=1 (x ➖ 1x+1).

[@veijolalli326]

(10^x+10^x+10^x)/(5^x+5^x+5^x)=100 3*10^x/3/5^x=100 10^x/5^x=100 (10/5)^x=100 2^x=100 ln(2^x)=ln(100) x*ln(2)=ln(100) x=ln(100)/ln(2)

[@serjonunes181]

(10^x + 10^x + 10^x)/(5^x + 5^x + 5^x) = 100 10^x/5^x=100 (10/5)^x=100 x log2 =2 x= 2/log2