A Very Exponential Equation

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[@bobbyheffley4955]

I took the natural logarithm of both sides and got x-1=1. From here, the solution is x=2.

[@Viki13]

Turns out x^(1/lnx) is a constant

[@josepherhardt164]

OMG, I got one! And I didn't even have to invoke Lambert's W function. Nor his X, Y, or Z functions, either!

[@devondevon4366]

x=2 e^x- 1 = x^ 1/log e x e^x/e = x^ log x e = e e^x = e* e e^x = e^2 x = 2 Answer

[@TejasDhuri-p8z]

Answer is 2 just by looking at it

[@MD-kv9zo]

2? Before vid

[@px3.Zr0]

Fr it's pretty easy

[@scottleung9587]

Cool!

[@pjb.1775]

(e^(x-1)) - x^(1/lnx)în grafiği hakkında desmos graphla 12 dakikalık tartışmamızdan sonra 0^0 = 1 olduğunu öğrendim. Desmos kazandı

[@SyberMath]

Desmos candır! 😍 What is 0⁰ (0 To The Power 0): kzbin.info/www/bejne/oaeYh4xmh6qVg8k

[@px3.Zr0]

Ans 2