Yes, this is A particular solution. However the more interesting question is what is THE general solution what we don't know (it might be not equal to this particular solution). For instance we can see that the equation is not defined for x=0. An important question should be asked whether f is a function from C to C or if it can be from R to R (probably not). We can also see that the limit of f' at infinity is f^(-1)(0). One can then discuss what is the behaviour of f depending on the number of solutions of f(x)=0. If there are none, f' would not be defined at infinity. One can also differentiate the equation and get information about the convexity depending on the sign of f''(x) if f(x) is real. Etc.
@GeraldPreston13 ай бұрын
0:11 a very elegant way of putting it
@maths_5053 ай бұрын
Mathematical bars😂
@ayushrudra86003 ай бұрын
@@maths_505 lol you should make a math rap it would be so funny
@natepolidoro45653 ай бұрын
When writing out beta and doing calculations involving raising it to its own power, I think it is nicer to write beta in exponential/polar form in the base, and rectangular form in the exponent so that some stuff will cancel out and separate nicely.
@maths_5053 ай бұрын
Oh yeah that would've been cool...I think Euler would write it that way😂
@CM63_France3 ай бұрын
Hi, I give you the stupid thought that I probably adopted when young to remember that sin 30° = 1/2 : the number thirty : thirty minutes is .... half an hour. I say "probably", I am not sure, but I guess it's that, as you know, mnemonic processes have these secrets. I love your videos. "ok, cool" : 0:19 , "terribly sorry about that" : 3:30 , 5:10 .
@kingzenoiii3 ай бұрын
YES MIDDLE EARTH IS BACK
@maths_5053 ай бұрын
@@kingzenoiii FOR GONDOR!!!!
@kingzenoiii3 ай бұрын
@@maths_505 lmaoo
@РайанКупер-э4о3 ай бұрын
Are those all solutions?
@maths_5053 ай бұрын
The alpha parameter is defined as a complex power function so we have to be careful that this the principle value we're talking about. In that case, indeed these are the only 2 solutions (or maybe just the only ones I've found 😂).
@Jalina693 ай бұрын
Sin(pi/6) =1/2. Also second beta maybe beta = -exp(-ipi/6), but it should be complex conj so i dont understand then
@maths_5053 ай бұрын
Oh yeah but that only means I'm off by a factor of 1/2😂 and yes the other beta is the conjugate of the first one.
@Jalina693 ай бұрын
@@maths_505 oh no you are right nvmnd
@mattyg24943 ай бұрын
how do you just assume that the function f(x) = ax^b and that you can just take away the x's and set a^(-1/b) = ab?
@renyin_13 ай бұрын
I had the same confusion, didn't see how ab=a^(-1/b) was obtained
@txikitofandango3 ай бұрын
Holy crap. I did this problem before watching the video and thought, no way, I'm overthinking it. But apparently not!
@qdphi3 ай бұрын
Hi. Should I spell your name as Kamal, Kemal or Camal?
@maths_5053 ай бұрын
Kamaal
@redroach4013 ай бұрын
Next video: solve the basel problem and aprey's constant PLEASE.
@maths_5053 ай бұрын
Search Basel problem maths 505 and you'll get my video
@redroach4013 ай бұрын
@@maths_505 I see but do you think you could solve it like a similar way to Apostol's method, ie: using multivariable calculus since that feels more intuitive (I have no idea what residue theorem is). Also, I think then you could expand it to solving the zeta function of 3 and perhaps some complex inputs as well.
@maths_5053 ай бұрын
Yes it can be generalised to an integral in N space for ζ(N).
@davidrojas50873 ай бұрын
Why you supose that y=a x ^b?????
@maths_5053 ай бұрын
I explained that in the video
@xxxx0153 ай бұрын
Dr. Michael penn a similar one before
@RandomBurfness3 ай бұрын
Didn't Michael Penn make a video on this exact problem? :O
@maths_5053 ай бұрын
Nah this one's a different case
@maths_5053 ай бұрын
And even the case he discuss was solved by Dr Peyam 5 years before Penn's video.
@alexandermorozov22483 ай бұрын
Почему решение ищется сразу в виде степенной функции?
@maths_5053 ай бұрын
I explained why at the beginning of the solution.
@Jalina693 ай бұрын
Типа производные и интегралы полиномиалов тоже полиномиалы. Я таки думаю есть и другие функции которые подходят.
@alexandermorozov22483 ай бұрын
@Jalina69 вот я тоже думаю, что есть и другие функции. Например, можно продифференцировать обе части уравнения, и воспользоваться тем, что производная обратной функции равна обычной производной этой же функции в минус первой степени. Или попробовать взять интеграл от обеих частей уравнения. Или поменять переменную.
@dang-x3n0t1ct2 ай бұрын
Michael Penn also did this one I think
@maths_5052 ай бұрын
@@dang-x3n0t1ct nope
@dang-x3n0t1ct2 ай бұрын
@@maths_505 https:/ /kzbin.info/www/bejne/qICbq2OtismolaM it's this one
@dang-x3n0t1ct2 ай бұрын
@@maths_505 it's from the "A beautiful differential equation" video
@maths_5052 ай бұрын
@@dang-x3n0t1ct still nope. I searched the video and the RHS is f(1/x) whereas my solution pertains to f^{-1}(1/x)
@dang-x3n0t1ct2 ай бұрын
@@maths_505 i must have gotten confused, apologies
@debblez3 ай бұрын
sure but what if f(1) = 1
@debblez3 ай бұрын
f’(1) = f^-1(1/1) = 1 f’’(1) = 1/f’(f^-1(1/1))*-1/1^2 = -1 dunno the solution but it seems like you get a nicer result
@debblez3 ай бұрын
f'''(1) = 3 f''''(1) = -12 f'''''(1) = 57
@debblez3 ай бұрын
-303, 1761
@lakshay-musicalscientist21443 ай бұрын
I think I remember something like this uploaded earlier if im not wrong
@maths_5053 ай бұрын
Nah that was for just the inverse
@GeraldPreston13 ай бұрын
is it possible to solve these equations from the ground up (without assuming the form of f(x)) by integrating the inverse? i'm sure i've seen some sort of formula for the integral of an inverse function
@maths_5053 ай бұрын
That would give us the function in terms of an integral which is much less clear of a solution.
@maxvangulik19883 ай бұрын
it's hard to integrate either function at 1/x
@worldnotworld3 ай бұрын
@@maths_505 Might other basic forms be plausible candidates for alternative solutions, for example exponentials of x? Could there be, in principle, classes of solutions that differ in such a profound way? I should just try it, I guess...
@khengari773 ай бұрын
Me: My world isn't real anymore. Him: what's your problem? Me: it's complex.
@jakybel8843 ай бұрын
Could you tell me the app used for note handwriting?
@maths_5053 ай бұрын
@@jakybel884 Samsung notes
@jakybel8843 ай бұрын
@@maths_505 ❤️❤️ thanks
@ericthegreat78053 ай бұрын
Yo dawg I heard you like inverse functions so I chose an inverse function at an inverse argument
@pyrite20603 ай бұрын
3rd
@natepolidoro45653 ай бұрын
👍
@bikash_Chandra_debnath3 ай бұрын
I was a commerce student, why the heck I'm watching this 😂
@aravindakannank.s.3 ай бұрын
u started this , u can't go back to simple math now , u will feel bored 😂
bro I think I need to have an appointment with an ophthalmologist as soon as possible. if u can't see and enjoy the beauty in results like this simple one's ,one day u won't be able to enjoy the beauty of elegant results. one more thing kaamal might have had a busy day . so he just didn't want to take more strain today .
@Tosi314153 ай бұрын
what if i smash my laptop? will you buy me a new one?
@maths_5053 ай бұрын
Don't worry bro them $1 patrons be floodin' in all we need is a few more😭😭😭
@aravindakannank.s.3 ай бұрын
bro we ourselves are poor bro we just don't talk about it publicly so please don't smash ur laptop and if u bought new also don't smash it just recycle it or if it's working condition donate it to someone who u know is in need of it .
@maths_5053 ай бұрын
@@aravindakannank.s. but make sure to subscribe before donating so that the new owners have cool math they can watch 😂