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@noobymaster69808 ай бұрын
I love when he said ”it’s integral time” and integraled all over the integral. Truly one of the integral moments of 2024.
damn this video was so beautiful that i lost my edging streak.I love math.
@maths_5058 ай бұрын
Yup KZbin is definitely recommending my videos to the right audience.
@BenDover698318 ай бұрын
bro
@NavyaMenon257 ай бұрын
guys i think he likes likes math
@josephlorizzo89978 ай бұрын
WOW, what a cute ODE, i loved how you used the feyman trick there, i couldn't wait for you to mention the gaussian integral for that -u² on the e ahahahaha
@askandpushpaltiwary85378 ай бұрын
you should try the book of almost impossible integrals. Its a joy to solve those!
@ieee123458 ай бұрын
It feels like it'd be a ton easier writing cos(x) = Re(exp(ix)), packing the exponentials, completing the square and then invoking some mild holomorphic property to make the imaginary shift in the integration variable. After that it's just gaussian integrating. You could even do that at the step before, changing the sin into a complex exp. Still, watching Feynman's trick at work is always nice, keep it up.
@lakshay37458 ай бұрын
Or you could just use the complex definition of cosx and then complete the square in both Integrals and create two erf functions which solves the integral in like 2-3 lines
@aryaghahremani93048 ай бұрын
can you explain the holomorphic shift? what i get when completing the square is Re(exp(-(x^2-i/2)), how do you turn this back into a normal guassian without invoking complex integrals
@ieee123458 ай бұрын
@@aryaghahremani9304you should get something like exp(-(x-k*i)^2) inside the integral, for some k I can't tell right now. Then you'd want to do the change of variables u = x - k*i, to get back to the normal gaussian integral, but to do so you must note that the 2 "line pieces at real infinity" integrate to 0 and that the integrand is holomorphic. You can also just do the change, replace the limits and hope it works, but to justify it you need this very mild complex analysis, which is what I was referring to.
@djconnel8 ай бұрын
@@lakshay3745 I agree: I felt as if the use of Fenyman's trick was strained. My first reaction was to express the cosine in complex exponentials, as you suggest. But maybe because I never learned it in school so I find it non-intuitive.
@Sugarman967 ай бұрын
And at that point it's just the Fourier transform of the Gaussian evaluated at 1
@lolcollol2128 ай бұрын
Free okay cool buttons: 1:05 5:27 6:36 7:37 8:11
@utuberaj605 ай бұрын
Hi Kamal I've been watching your amazing 'integral' videos, and the more I watch, the more I love them, and I see you using that amazing Feynman's trick that's really cool. Indeed you make my 'integral moment' today at sunrise here in India
@acelm84374 ай бұрын
I liked how the e^(-u^2) term kept absorbing the u's
@MrWael19708 ай бұрын
Very impressive integral. Thanks for featured solution.
@holyshit9228 ай бұрын
Integration by parts Change of variable u=sqrt(-ln(x)) Series expansion for cosine Change order of integration and summation Change of variable v = u^2 , to get Γ function (Γ function can be also expanded)
@dukenukem97708 ай бұрын
Both the solution and the technique are beautiful.
@aryaghahremani93048 ай бұрын
ODE is smart, i love how feynman's technique is becoming an actual method of solving integrals rather than just a cool trick these days i solved the cosx e^(-x^2) integral by letting cosx=Re(e^ix) though which is pretty cool as well i guess
@cameronspalding97928 ай бұрын
@ 4:49 for this part I would have used the complex expression for cos(u) and then used contour integration to get the rest of the answer
@trelosyiaellinika3 ай бұрын
Really cool! 😊
@zealot43254 ай бұрын
Thank you!
@Jalina698 ай бұрын
Counting how many times bro said "cool".
@lucasbeaumont57628 ай бұрын
people say im weird cause to me this is fun, i think their werid for not understanding that this was fun
@SamLindskougMBGY8 ай бұрын
First time i accually manage to solve one of your monster integrals, lets go
@maths_5058 ай бұрын
I'm proud of ya bro
@emilien255522 күн бұрын
I got it alone ! it was nice and actually easy
@leonmancaj36908 ай бұрын
Great thank you Sir
@YassFuentes8 ай бұрын
Beautiful one!
@HighlyEntropicMind8 ай бұрын
I liked how we never needed to go back to the original
@nickyhekster29748 ай бұрын
Very cool.
@sasukeuchiha13207 ай бұрын
Ok cool!
@illumexhisoka61818 ай бұрын
I have read about norms the other day (barely understood anything) But I got wondering how to find a general formula for the integral from 0 to 1 of The nth root of (1-x^n)
@GiornoYoshikage8 ай бұрын
Substitute `x^n = u` and notice that you get a kind of beta-function
@federicoformaro8 ай бұрын
one of the few times i could've solved it by myself
@giuseppemalaguti4358 ай бұрын
Io ho fatto così...t=√(-lnx)..risulta e^(-t^2)cost integrata da 0--->inf...poi feyman I(a)=..cosat...risulta,in sintesi I=√π/2e^(-1/4)
@BadrBoutara6 ай бұрын
hi please why did you plug in ln c rather than c
@sciencelover-c2j8 ай бұрын
When you get in the next step, please put some explanation between steps. Because we need to get the clearance solution. we are not all proficient .thank you
@maths_5058 ай бұрын
So you weren't listening to the audio???
@sciencelover-c2j8 ай бұрын
@maths_505 Absolutely, because mathematics is a language in itself, so l asked you, we need more steps before you get in another step,
@maths_5058 ай бұрын
@@sciencelover-c2j to waste more time??
@sciencelover-c2j8 ай бұрын
@maths_505 Why do you think that 20 minutes is not enough ??
@maths_5058 ай бұрын
@user-zg8ny5tp4g I just think that rambling on about basic algebra is gonna be extremely boring. The level of math here is something that my target audience is sufficiently familiar with.
@yoav6138 ай бұрын
Nice😊
@toufikakkak84598 ай бұрын
Hi bro, can you do the intégrale from 0 to 1 for "ln(1-ln x)"
@maths_5058 ай бұрын
Aight
@edmundwoolliams12408 ай бұрын
Beautiful aesthetically pleasing result, use of differentiation under the integral sign which led to a lovely first order ODE 😍 Exactly what I needed on my Friday morning. Could you find and do a beasty integral that evaluates to Digamma(G/sqrt(phi))?
@maths_5058 ай бұрын
Wow that is some request! I'll try my best.
@edmundwoolliams12408 ай бұрын
@@maths_505 I know that's a very tough request. 😂 I don't expect you to get very far with it; as far as I'm aware crafting a (non-trivial) integral to yield a specific result is some near-impossible guesswork. I suppose that's why it's extra-special when beautiful results DO come out 😊
@igorbatkovich38568 ай бұрын
Без Фейнмана не обошлось))
@Ivan-mp6ff8 ай бұрын
Why not complement it with a graph? In most math calculations, a graph speaks a thousand words and can be very intuitive. Thank you all the same.