A Very Quartic Equation | Can You Solve?

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SyberMath

SyberMath

Күн бұрын

Пікірлер: 21
@SyberMath
@SyberMath 5 ай бұрын
Proving a quartic inequality (Sum of Fourth Powers): kzbin.info/www/bejne/pHTFpqWgqZaInbc
@davidseed2939
@davidseed2939 5 ай бұрын
4:50 if z=1, then xy=1 gives x=y= 1 OR x=y=-1. ie a fourth solution. This corresponds with the fact that the equation is symmetric in x,y,z and so the solution must be symmetric. ie the solution set is x=y=z=1 and all permutations of (x,y,z)=(1,1,-1)
@snejpu2508
@snejpu2508 5 ай бұрын
I used AM>=GM formula: (x^4 + y^4 + z^4 + 1)/4 = 4throot(x^4 * y^4 * z^4 * 1). It works, as x^4, y^4 and z^4 are always nonnegative. After a few steps, you get x^4 + y^4 + z^4 >= 4xyz - 1. So, the relation becomes an equation, if x^4 = y^4 =z^4. It is still a little tricky, as you have to be careful with the signs. It's not the same as x=y=z apparently, as it only gives the solution (1,1,1)... I'm not sure how you could find the rest of solutions in an universal way from there. Or you could just try out all 3 possibilities with +/- 1 and see, what happens.
@SyberMath
@SyberMath 5 ай бұрын
Good to see you! ☺️
@snejpu2508
@snejpu2508 5 ай бұрын
@@SyberMath Hi! I often follow your content, but only comment on problems not too obvious and not too difficult for me. ;-)
@ayushrudra8600
@ayushrudra8600 5 ай бұрын
4:50 you missed (-1, -1, 1)
@SyberMath
@SyberMath 5 ай бұрын
😄😄
@mr.d8747
@mr.d8747 2 ай бұрын
*Yeah, a quartic is supposed to have four solutions*
@Hobbitangle
@Hobbitangle 5 ай бұрын
The equation is symmteric over x,y,z So if there is a solution {1,-1,-1} there should be the solutions {-1,1,-1} and {-1,-1,1}. You did miss one. And definitely the complex solutions should be considered as well.
@Hobbitangle
@Hobbitangle 5 ай бұрын
Complex solutions examples: {-1,i,i},{1,i,-i} because i⁴=1 -1•i•i=1 1•i•(-i)=1
@SyberMath
@SyberMath 5 ай бұрын
😄😄
@NadiehFan
@NadiehFan 5 ай бұрын
I wonder how at 4:48 you could have missed the solution (−1, −1, 1) of your equation in x, y, z when at the end you show the result from WA which clearly finds _four_ integer solutions.
@SyberMath
@SyberMath 5 ай бұрын
😮😄 that's me!
@tixanthrope
@tixanthrope 5 ай бұрын
arithmetic mean >= geometric mean yields (1, 1, 1) other solutions are (1, -1, -1) etc.
@jurem2978
@jurem2978 5 ай бұрын
Me seeing the problem, be like: "it's AM GM, it's AM GM"
@ayushrudra8600
@ayushrudra8600 5 ай бұрын
Bro why are some people hating so hard in the comments when he accidentally missed a solution
@NadiehFan
@NadiehFan 5 ай бұрын
I found two videos where you already did both problems from this video, but KZbin won't let me post the links because if I do my message gets removed immediately. But anyway, here are the video IDs: ogfNGLyL7NA pFUVGjMUHMY
@SyberMath
@SyberMath 5 ай бұрын
Thanks for the heads up! 😍 One of them is a generalization or a version with four variables. The other one is the same problem done slightly differently, maybe! 😜 Here's the links: kzbin.info/www/bejne/pZjJf3qCrrFqhKM kzbin.info/www/bejne/pne4h3qggrp7g7s
@MochooCheung-pu8js
@MochooCheung-pu8js 5 ай бұрын
Giving this kind of question is Cheating, because the question maker already knows the answer.
@SyberMath
@SyberMath 5 ай бұрын
ehehehehehe 😄😜
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