Can we reach 1000 likes on this video. Share this video among your friends and Give your suggestions on which topic I should make videos. Thanks
@VijayKumar-qw1wn3 жыл бұрын
you are awsome, u reach 100000 likes , god bless u
@riyazbasha79827 жыл бұрын
I am working in mvc and angular,shocked to see ur videos,these all are real time videos...good work ashish keeepp it up...and i am willing the angular2
@sachingreat2225 жыл бұрын
Very nice explanation. Thank you for sharing this video and your efforts
@mocococo28777 жыл бұрын
Hello great video and great series of videos. Thank you. I think the reason you can not delete a row in Employees table is not that you have foreign key from Departments table. Employees is a child in this case and you can delete a child without deleting a parent. In your video N 13 you showed that EmployeeID is a foreign key in Sites table. That makes Sites a child. If you have enforced those relations with primary - foreign key then you can not delete Employee without deleting the corresponding Sites row or rows. I.e. you can not delete a parent row only, as children rows will become orphaned and nothing will point to them and they will become a redundant baggage.
@aapkanigam7 жыл бұрын
+Moco Coco yeah you are absolutely right ..thanks for the explanation.My perspective was to deliver simple overview of sql without going in detail, In this way audience can focus on MVC only. May be I will be having sql tutorial also in which I would go in detail.
@sambaskw4 жыл бұрын
explaining super...
@sunpreetsingh51436 жыл бұрын
very very very awsm tutorial ....BIG THANKS ASHISH JI
@duncanmcdonald52506 жыл бұрын
I would have liked an explanation as to WHY using JQuery/AJAX to trigger the save action in the controller is a better method than the one used in the previous tutorials.
@kirankumari-nz8lr8 жыл бұрын
I loved this video .Very easy explanation keep doing good work .Thanks
@aapkanigam8 жыл бұрын
+kiran kumari Thanks for your valuable feedback
@tayyabjatoi86444 жыл бұрын
Very Wonderful...!!
@sagorfox70425 жыл бұрын
Thanks a Lot Sir
@aniljain507 жыл бұрын
Its simple and awesome. Kee up the good work.
@aapkanigam7 жыл бұрын
+Anil Jain thanks ..keep learning and sharing
@ayoforyou4484 жыл бұрын
many thak's
@ramreddy44417 жыл бұрын
Good Work.....Very Nice (but in Identity field after 5 th record it show 1002 like dis,y it is coming ?)
@aapkanigam7 жыл бұрын
+ram reddy thanku .. this is due to when you re -start your Sql server instance then .. the auto increment value will jump to 1000 if column is of int type . For bigint type it will jump to 10000. ITS Microsoft sql server feature which is horrible..
@veeramuthudotnetveera7 жыл бұрын
Nice Video sir.But i need to post html textbox data to xml file node using jquery ajax? please help me.. Thank you.
@redodht7 жыл бұрын
Very clearly. Thanks for the video
@aapkanigam7 жыл бұрын
+Nguyen Truong thanks!
@aliraza66-h1b8 жыл бұрын
awesome waiting of these kind of videos with JQ
@aapkanigam8 жыл бұрын
Thanks for ur valuable feedback.Sure we'll try to give you best.keep learning and sharing..
@giftatte40527 жыл бұрын
You are good man!, Love your videos... Keep it up
@aapkanigam7 жыл бұрын
+Gift Atte thanks ..keep learning and sharing
@yogeshgangwar83075 жыл бұрын
is it works only with razor view ? in my case ,it's not working.
@neflinkyle85405 жыл бұрын
You are Amazing!
@sachingreat2226 жыл бұрын
Nice Explanation
@MuhammadMustafa-kc3ep6 жыл бұрын
Ashish in your Program Form Validation is not working without Input type sumit kindly help me to fix this problem please
@betalaprasanth24207 жыл бұрын
thanks sir for this easy and good tutorial .... i am having a problem ..my $.ajax () code is not working .. simple jquery is working but not ajax code
@mohsen57327 жыл бұрын
Wonderful tutorial.
@navzme6 жыл бұрын
Thanks for awesome video
@tomyang77887 жыл бұрын
so once the ajax post request fires, will the newly entered data be added to the existing database ?
@aapkanigam7 жыл бұрын
+Tom Yang yes
@dmcnamee20106 жыл бұрын
Hi great video, I am trying to populate a dropdown in the modal from another table, can you help me ? Thanks Daryl
@aapkanigam6 жыл бұрын
part 36 will help you thanks!
@dmcnamee20106 жыл бұрын
Got it sorted thanks
@maihassan36027 жыл бұрын
Thank you so much for the help. This is amazing
@aapkanigam7 жыл бұрын
Thanks Mai
@aapkanigam7 жыл бұрын
+Mai Hassan Thanks for your feedback..keep learning and sharing to those who love to learn mvc
@saurabhmishra36414 жыл бұрын
Thx Sir
@MuhammadMustafa-kc3ep6 жыл бұрын
i am using bootstrap validator with ajax asp.net mvc pop modal form
@tomyang77887 жыл бұрын
so what does the controller associated with the url Test/Index actually do ?
@aapkanigam7 жыл бұрын
+Tom Yang it will load index page by hitting index method of Test controller
@RahulMishra-qq8yy7 жыл бұрын
Hi Ashish, Thanks a lot for your videos. these are realy needfull. i have an issue while submitting my form in controller model "EmployeeViewModel model" is showing blank not showing the data that i fill in form.
@CemreTurgut4 жыл бұрын
Hi. Can you fix that problem?
@nadezdajanjetovic93107 жыл бұрын
Hi Ashish, can you make video tutorial when user click on button to fill text field with value (in my case textbox have to contain number when users click on button) on form of website? I am trying to pass result of method from my Controller to View using jquery when users click on button. Thanks for help!
@aapkanigam7 жыл бұрын
+Nadezda Janjetovic you want to set value to textbox ? .. you can use $("#textboxId").val ("write any text here") .
@nadezdajanjetovic93107 жыл бұрын
Yes. This is my method in Controller: public int returnLastIDFromDatabase() { fpisEntities db = new fpisEntities(); Listlista = db.Supplier.ToList(); int lastID = 0; foreach (Supplier s in lista) { lastID= s.SupplierID; lastID++; } return lastID; } So i want when user click on button "Make new supplier" , website texbox have to fill with new id from my method in Controller. Method in Controller return last unique id from database of object Supplier, so system generate automatic new primary key.
@aapkanigam7 жыл бұрын
+Nadezda Janjetovic return JsonResult instead of int .example - Return Json (yourlastId, jsonRequestBehavior.AllowGet) In ajax response you will get this id. For getting last Id why have you done looping.. its one line code .please watch part 13 insert data into multiple table . There I have shown how to get latest Id then insert that into other table .
@nadezdajanjetovic93107 жыл бұрын
I will try that,Thanks a lot for help!
@annuverma9366 жыл бұрын
what about validation on this page u removed validation code
@aaronaaronaaron59227 жыл бұрын
you really, really Rock!!!!!!! Thanks man.
@dumindar5 жыл бұрын
Thank you!
@musabuthelezi7 жыл бұрын
Hi! i hope I will get a reply sooner. I was following your video, and i am also trying to insert into the database. I am not sure why it is not taking the values. so when i put the debugger and data="" is always like that. help! how do i solve this
@aapkanigam7 жыл бұрын
+Nhlakanipho Musa Buthelezi Have you tried the shared code . Please find the link in description
@musabuthelezi7 жыл бұрын
Thankns Let me try that
@tauhidulislam61636 жыл бұрын
Hi, thanks for tutorial, how to find loader image under content folder??
@aapkanigam6 жыл бұрын
+Tauhidul Islam you can download it from google and place into that folder
@JP-pb6kn6 жыл бұрын
"Okah" Ashish .... "Okah"
@narendarsingh46726 жыл бұрын
Great
@dgtal29267 жыл бұрын
Is there a way to download the source without installing all that spam in my computer?
@dgtal29267 жыл бұрын
Never mind, I found the way. Good tutorial. Thanks
@kiranrao45537 жыл бұрын
What is the way? Can help me ?
@saurabhmishra36414 жыл бұрын
why i am facing 500 internal server error
@samzviews63157 жыл бұрын
hii ashish why validation is not working if am calling action using ajax hit pls anser as soon as fast
@aapkanigam7 жыл бұрын
+Sheshmani Pandey Sam you can find the code from blog. Get link from description
@samzviews63157 жыл бұрын
ashish understand what i am asking u just run your code of this video only and left any fields blank and submit u will see validation error is not showing ........that is what i am saying
@aapkanigam7 жыл бұрын
+Sheshmani Pandey Sam 1.Have you given the reference of unobtrusive.js and jQuery.js file. They should be in correct order. 2. Make sure to use Required validator above model property 3. For displaying error use validationMessageFor in view 4. Make sure to not use two jquery file reference . 5. Inspect your code using fire bug of your browser and find if you are getting and console error. Hope this would work . If you still get error then tell me that.
@aapkanigam7 жыл бұрын
+Sheshmani Pandey Sam watch part 29 for validation using jquery.
@samzviews63157 жыл бұрын
Technotips - Ashish can u pls tell me the correct sequence of jquery references
@anjalysivan1756 жыл бұрын
Its not working...i have a problem while submitting my form in controller model is showing blank data that i fill in the form.. why??? this problem is only getting for using ajax ..
@aapkanigam6 жыл бұрын
Are you getting any error in browser console?
@prashantsingh-lt4rc5 жыл бұрын
@@aapkanigam no error in console in data it is passing null
@gipek6 жыл бұрын
venkat is det yu?
@bilalyousuf68147 жыл бұрын
validation is not working in this way
@aapkanigam7 жыл бұрын
+Bilal Yousuf part 11 and 29 may be helpful for you
@adeelzahid96225 жыл бұрын
OK
@Game-vi6if5 жыл бұрын
Ashish you have so much knowledge but you need to improve your speaking skills.
@sagorfox70425 жыл бұрын
i think its not important and its enough to us for learn... though its needed for him later....