Abstract Algebra | Irreducibles and Primes in Integral Domains

  Рет қаралды 12,768

Michael Penn

4 жыл бұрын

We define the notion of an irreducible element and a prime element in the context of an arbitrary integral domain. Further, we give examples of irreducible elements that are not prime.
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Пікірлер: 22
@xahiru
@xahiru 4 жыл бұрын
yeah, a video about rings of invariants would be great. thanks :-)
@mushroomsteve
@mushroomsteve 4 жыл бұрын
In the ring Z[√-5], 2 is irreducible but not prime. We have 2*3 = 6 = (1 + √-5)(1 - √-5), so 2 divides 6. However, 2 does not divide (1 + √-5) and 2 does not divide (1 - √-5).
@timurpryadilin8830
@timurpryadilin8830 4 жыл бұрын
I comment because I want to see a video about rings of invariants :)
@crossgibson6986
@crossgibson6986 4 жыл бұрын
your videos make me feel big brain lol. Great job btw.
@user-pk2qc5yq3c
@user-pk2qc5yq3c 9 ай бұрын
Would love to see a video about ring of invariants
@markbeukeboom7815
@markbeukeboom7815 6 ай бұрын
you are a very good teacher thank you
@pinklady7184
@pinklady7184 4 жыл бұрын
Do you ever think of doing book reviews? I love to see your library of maths books.
@Ferolii
@Ferolii 4 жыл бұрын
Nice video! One about Galois Theory // Topology would be so nice! ❤️
@music_lyrics-ni7ks
@music_lyrics-ni7ks 2 ай бұрын
Yes please, a video about rings of invariants would be wonderful 🎉
@mrparam918
@mrparam918 2 жыл бұрын
Video on rings of invariant would be highly appreciated Prof Penn
@TheOneThreeSeven
@TheOneThreeSeven 4 жыл бұрын
I would like to see a video about rings of invariants please =)
@joymenezes3959
@joymenezes3959 3 жыл бұрын
Rings of invariants please:)
@ezequielangelucci1263
@ezequielangelucci1263 2 жыл бұрын
This means that the fundamental theorem of aritmetic doenst function properly when talking about other sets?
@hrishabhayush4631
@hrishabhayush4631 4 жыл бұрын
Try out inmo(indian national maths Olympiad(
@lexinwonderland5741
@lexinwonderland5741 2 жыл бұрын
I realize this video is ancient, but nonetheless i noticed how your example references your work on orbifolds; as per the video request, commenting to see more!
@michaelempeigne3519
@michaelempeigne3519 4 жыл бұрын
a^2 > or = 0 is called the trivial inequality
@mehdifachel2057
@mehdifachel2057 4 жыл бұрын
Tres interessant svp pouvez vous sous titres en francais
@Monolith-yb6yl
@Monolith-yb6yl 4 жыл бұрын
I want this video :)
@benjamimapancake6429
@benjamimapancake6429 4 жыл бұрын
you're gonna have a good time
@rajneshyadav9654
@rajneshyadav9654 2 ай бұрын
waiting for rings of invariants
@depressedguy9467
@depressedguy9467 Жыл бұрын
After years still no ring invariant
@BeattapeFactory
@BeattapeFactory 4 жыл бұрын
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