Acceleration due to Gravity? Physics

[@pankajgurgila8823]

What a superb explanation if you are looking to understand gravitational acceleration then here it is.

[@manishbhatia5302]

Great, many thanks for sharing this video.

[@BhargaviIrra]

Thank you for your nice explanation

[@shinkamiya3276]

At the time of 1 second the velocity is 9.8m/s so why displacement is 4.9m ?

[@janieli]

That's what I was wondering as well. Since, velocity = displacement / time, and we know that time = 1 sec. So, why would velocity be 9.8 m/s^2 if the displacement is 4.9 m

[@shinkamiya3276]

@@janieli Yeah there is mistake in the video.

[@willoughbykrenzteinburg]

This is just how acceleration works. There is no mistake in the video. The video is correct. An object that is dropped does not just immediately jump to 9.8 m/s. It *_accelerates_* up to that speed. In other words, it started at ZERO. After one second, it was traveling 9.8 m/s. This acceleration is constant, so you can easily calculate the average velocity during that first second by adding the initial velocity (0.0 m/s) and ending velocity (9.8 m/s) and taking the average (divide by 2), so 9.8/2 = 4.9 m/s. Then you apply this average velocity over that one second, and you see that something accelerating at 9.8 m/s² from a dead stop will travel 4.9 meters in the first second. Also, the 'd' in v=d/t is *distance;* not displacement. When we talk about velocity being 9.8 m/s after 1 second, we are talking about INSTANTANEOUS velocity. Your velocity at that moment in time. Displacement over time will tell you what your *average* velocity was over that span, and in this case, it is 4.9 m/s.

[@fondofsocialstudies5744]

This is because the velocity is increasing from 0 to 9.8m/s in first time interval.. It is not 9.8m/s for whole time interval.. For example it may be 4.9m/s at 0.5 second and increases to 9.8m/s at the time of 1 sec

[@manishbhatia5302]

We have to calculate the distance by using formula V2 (2 is square) - U2 = 2as where V is final velocity and u is intial velocity ; a is acceration which is 9.8 and s is distance.

[@fasihullisan3066]

if we through a ball downward with a velocity of 15m/s ,then as the ball moves downward,then its velocity increases or decreases as the ball moves downward.

[@NAJAMACADEMY]

Well, when the ball move s downward, its velocity increases. But th chang in velocity is always constant and that is 9.8 m/s2. We call this change in velocity as acceleration due to gravity.

[@fasihullisan3066]

it means that after one second the ball velocity will be 24.8m/s.

[@fasihullisan3066]

we know that gravitatioal acceleration decreases below the surface of earth till it becomes zero at the centre of earth,and as we go below the centre of earth,its value increases,but when we cross the diameter of earth,what wil happen to the value of "g",and where we will fall below?

[@avidrationalist7281]

You didn't get the right answer, didn't you? He just skipped your point; THROW A BALL DOWNWARD AT A VELOCITY OF 15m/s. In other words, the STARTING velocity of the ball is not ZERO, it is 15m/s.

[@zislencerlee5583]

Wow sir! How easily u explaib thank u so much

[@nishanisha233]

Wow...great and clear explanation...thank you so much

[@NAJAMACADEMY]

Your welcome...!!!

[@paromitamoshi2233]

lol...

[@maazkhan9867]

Great

[@saiyanguy2433]

1:38 here the t= 3 D= 44.1 so velocity should be 14.7 coz velocity=d/t 😢

[@sujathamurugadas1856]

Same doubt...

[@InduSingh-m3q]

It is the velocity at any instant

[@InduSingh-m3q]

9.8 is the average velocity

[@kingdomofknowledge5960]

What is the total distance it covered?

[@VanshSpeaks]

44.1 m

[@ezra2370]

help full bro

[@zafarqureshi8908]

Excellent

[@nawlaiwangsu6410]

It's really helpful

[@avinashautade0369]

Nicee video

[@learnnewconcept_everyday932]

hey,i don't understand why the direction of acceleration will be downwards in both cases?!

[@anilkumarmalothu1846]

How displacement changed

[@sama-vx3zb]

Tysm

[@RobaB.-zh4ee]

What is difference between gravity acceleration?

[@Antz_411]

I'm not the first to ask this here, but how is the DISPLACEMENT calculated??

[@willoughbykrenzteinburg]

It accelerated at 9.8 m/s². This means that for every second it falls, it is traveling 9.8 m/s faster than that moment the second before. If you drop a ball, it's initial instantaneous velocity is zero. After exactly one second, it is traveling 9.8 m/s. Obviously, the actual distance it traveled is not 9.8m because it wasn't traveling 9.8 m/s the entire time. It started at zero and accelerated up to 9.8 m/s. So, to calculate the displacement, you simply calculate the average velocity over time. Starting velocity was zero. Ending velocity was 9.8. This makes the average velocity 4.6 m/s ((0+9.8)/2). It traveled at an average speed of 4.6 m/s for one second, ergo the displacement is 4.6 m.

[@Antz_411]

@@willoughbykrenzteinburg Perfection, thank you! It's has been nearly 15 years since I covered that one back in school.

[@voiceofsj3026]

A small mistake in video

[@Geet_Bhakti_Vibes]

Sir the direction of acceleration due to gravity is towards the centre of the earth not in downward direction

[@nomank8274]

At t=1 d=4.9 m but v=9.8 m/s kindly guide how ? Shouldn't velocity also be 4.9 m/s

[@irshadbughio5944]

Exactly

[@kiranraj3609]

Same my question

[@mahnoor225]

What would happen with the value of"g"when an object is falling freely?

[@ezra2370]

noting happens it is +9.8m/s^2 since the starting velocity is zero we take the value of the gravity for the acceleration

[@ashashah2939]

Now after watching the whole video everything is green

[@ashashah2939]

I cant even see in the pink back ground . My eyes hurt

[@ZeeshanHaider-ze4mq]

Why 🤔

[@YamoNatung]

Same 😭

[@pushpadungdung1473]

thank you sir

[@Peehoo123]

Last me samajh nhi aaya