Accenture Coding Assessment Questions and Answers 2024

[@onoonoonoO]

everyone who is confident to crack Accenture placement like this ❤

[@ridhamsharma7778]

*Well Explained JAVA Code* import java.util.Scanner; public class Vehicles { public static void main(String[] args) { // Creating Scanner object for taking input from user. Scanner sc = new Scanner(System.in); // Input no. of vehicles int v = sc.nextInt(); // Input no. of wheels int w = sc.nextInt(); // Checking given constraints if(v>w || w%2!=0 || w < 2) System.out.println("INVALID INPUT"); int tw = ((v*4)-w)/2; // v*4 gives us the no. of wheels reqd to create v no. of 4 wheelers. // (v*4)-w gives us the no. of wheels that we are short of. // Finally we use these remaining wheels to create Two Wheelers so ,((v*4)-w)/2. int fw = v-tw; System.out.println("TW = "+tw); System.out.println("FW = "+fw); } }

[@Techno_lengend]

Bro help me for code Accenture exam

[@vaibhavihambire4828]

Bring more videos related to ACCENTURE..! Much Needed. Good to understand

[@dakshjain273]

Bring more videos related to ACCENTURE..! Much Needed..❤

[@pallavigupta4408]

First we will take input for 'v' and 'w'. And initializing tw=0 and fw=0 If (w>=2 && w%2==0 && v

[@ShrutiBansode-cd4pl]

@@pallavigupta4408 Why you copied my answer....😑

[@CodeWithMeInJava-1]

It's solving two equations

[@bindulayam-hv1op]

Accenture is upcoming to our campus placement soon Need more videos to to Crack all the 3 rounds

[@Ritikakhaire]

How are you preparing for coding rounds?

[@nobikiduniya]

Same here

[@thecodingrookie]

Which College ?

[@mdsarfraz-2132]

​@@thecodingrookieFor us also Accenture is coming soon for recruitment and the clg name: Avanthi Institute of engineering and technology

[@bgmilovers5931]

Nice to clear my accenture test in my campus placement

[@swagboltey102]

Kise Kiya apne muje bhi kuch tips do next month hai

[@unknownseries8011]

bhai kitane ka ctc diya h aap ke collage m

[@swagboltey102]

@@unknownseries8011 abhi ni bola

[@swagboltey102]

​@@unknownseries8011tips do na

[@siddharthsid1540]

hey did you also clear the interview? And did they ask anything about project in the interview round?

[@GKFactsAdda]

13:04 v = int(input("Enter the total number of vehicles: ")) w = int(input("enter total wheels: ")) tw=(4*v-w)//2 fw=v-tw print(tw) print(fw) ''' Time Complexity: O(1) Space Complexity: O(1) "'

[@GKFactsAdda]

Keep uploading more videos on Accenture coding questions so that it will be helpful for students like me a lot.......

[@user-kv9pv4vs4m]

This code showing error

[@ranjitvyavahare7135]

v = int(input("Enter the total number of vehicles: ")). w = int(input("enter total wheels: ")) tw=(4*v-w)//2 print(tw) print(fw) fw=v-tw

[@noxgaming4954]

(4*v-w)//2 why are you multiplying vehicles with 4??

[@infinitecodes]

In Accenture coding round which type of editor we get, like leetcode wherevjust have to complete the function or codechef like we have to write code from scratch?

[@mrmohan7246]

v=int(input("vehicle:")) w=int(input("wheels:")) if w%2==0 and 2

[@yashjoshi-j6c]

Accenture will be in my college soon these videos are must needed

[@yashwani8155]

in the first question, they have asked minimum, so should we not sort the array first?

[@soothingminds8866]

Sorting the array is not necessary in this case because the problem asks for the minimum number of houses required in the order they are given to provide enough food for the rats. The idea is to accumulate food house by house and stop as soon as you reach or exceed the required amount. This approach respects the original order of the houses, which is important because the question implies sequential distribution rather than an optimal selection from unordered data.

[@underrated0806]

I think this can be understood based on sample cases

[@binduk3669]

vehicles=int(input("enter no of vehicles: ")) wheels=int(input("enter no of wheels: ")) if wheels % 2 ==1 or wheels < 2 or wheels

[@creativeminds9329]

To solve the problem of finding the number of two-wheelers and four-wheelers given the total number of vehicles and wheels, you can use a system of linear equations. Let's denote: x as the number of two-wheelers (each having 2 wheels). y as the number of four-wheelers (each having 4 wheels). Given: v as the total number of vehicles. w as the total number of wheels. The equations are: 𝑥 + 𝑦 = 𝑣 x+y=v (Total number of vehicles) 2 𝑥 + 4 𝑦 = 𝑤 2x+4y=w (Total number of wheels) From equation 1, you can express y as: 𝑦 = 𝑣 − 𝑥 y=v−x Substitute this into equation 2: 2 𝑥 + 4 ( 𝑣 − 𝑥 ) = 𝑤 2x+4(v−x)=w This simplifies to: 2 𝑥 + 4 𝑣 − 4 𝑥 = 𝑤 2x+4v−4x=w 2 𝑣 − 2 𝑥 = 𝑤 − 4 𝑣 2v−2x=w−4v 𝑥 = 4 𝑣 − 𝑤 2 x= 2 4v−w ​ After calculating x, you can find y using: 𝑦 = 𝑣 − 𝑥 y=v−x

[@sourabhvishwakarma6274]

Hello sir @PrepInsta this question is saying to minimum number of house to feed all the rats so the ans should be 2 (8,7) because in this, there is no any classification that the no. of house should be in a sequence. or ager sequence me bhi rakhna hota to bhi and 3 hi data (8,3,5) then why 4?

[@jaanvirathore1850]

waah bhai aaj array input lene ka ek naya tareeka sikha mene.

[@priyanshumandal733]

In the first question greedy approach should have been followed.

[@saimanikantakaja3607]

V = int(input("Enter the total number of vehicles: ")) W = int(input("Enter total wheels: ")) if V >= W or W < 2 or W % 2 != 0: print("INVALID INPUT") TW = (4*V - W) // 2 FW = V - TW print("TW =",TW) print("FW =",FW)

[@ajaykadi1140]

import numpy as np # Coefficients of the equations A = np.array([[1, 1], [2, 4]]) B = np.array([200, 540]) # Solving the system of equations solution = np.linalg.solve(A, B) # Extracting the number of two-wheelers and four-wheelers two_wheelers = int(solution[0]) four_wheelers = int(solution[1]) print(f"Two wheelers = {two_wheelers}") print(f"Four wheelers = {four_wheelers}")

[@sathyaa4447]

In my clg next month Accenture will come for on campus placement....i need prepinsta prime

[@cybersolution-uv2xo]

Which college are you studying?

[@Anuusshaahhhh]

v = 200 w = 540 if w

[@vishalmonitor1]

Such a great Full video for us 💗 thank you sir 🙏

[@yashjoshi-j6c]

pls explain in java or c++

[@-Rajashekar-ot6sw]

Your people are doing a great thing

[@kunjmaheshwari9819]

in this question we can use Kadans Algorithm.

[@shrutimore23]

Java program to calculate vehicle manufacture : import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner x = new Scanner(System.in); System.out.print("enter total number of vehicles : "); int v = x.nextInt(); System.out.print("enter total number of wheels : "); int w = x.nextInt(); if(2 0) { System.out.println("total four wheeler needed : "+fw); System.out.println("total two wheeler needed : "+tw); } else { System.out.println("INVALID INPUT"); } } }

[@RajniLamkane]

Excellent 👍

[@challengemania4447]

I have a doubt.. Only 2nd house (8 unit of food) and 5the house (7 unit of food) is more than enough for all rats... Then why output is 4 houses ?

[@rohanchawla9955]

exactly i was thinking the same

[@rohanchawla9955]

why are we not applying greedy approach here

[@vineetgoswami9954]

Exactly, first I saw the question I though it should be done with sorting ​@@rohanchawla9955

[@vineetgoswami9954]

​@@rohanchawla9955i think we don't have to change the order of houses. If you found out this question reply

[@soumyakantisadhu4676]

when is accenture conducting their online assessments

[@ayushrathore887]

this question demand the min no of house then why its output is 4. the correct ans would be 8,3,5 (3)....using greeedy or dp something...how you can solve this by starting at index 0.??can someone please correct me if im wrong with it ...

[@shivanpatil1761]

It is more easily exaplained in prepinsta about the test

[@MANNEMROHITHKUMAR]

complect video on accenture sylabus and test pattern

[@shas495]

Can i use and inbuilt fuctions of STL in C++?

[@sayanbhattacherjee9829]

we are told to define a function which accpets 3 parameters. you have taken a function which accept 4 parameters?

[@indiansologamedeveloper]

for better performance do leetcode easy and mid lvl questions

[@JerryHolland-f9m]

v = int(input("How many vehicles: ")) w = int(input("How many wheels: ")) fw = int((w/2) - v) tw = int(v - fw) print("4 w", fw) print("2 w", tw)

[@manojkumarchandora9800]

In first question (8+7) > 14 minimum number is 2

[@Hackthic]

for this type of question develop the formula , it take hardly 10 min. and all the test cases will easily passed

[@21M206BALAMURUGAN]

v=int(input("vehicle:")) w=int(input("wheels:")) if w%2==0 and 2

[@nitheeshk9923]

The answer for last question V=int(input("Enter the no of vehicle")) W=int(input("Enter the no of Wheels")) if 2

[@shairamayalvarez7753]

Help.can someone explain to me about the constraints? 🥺 And how to conclude in that equation? 🙏🏻 Thanks in advance 💖

[@lleviuchiha5565]

Sir can I solve Accenture coding assessment exam in javascript..... ?because in their company page they only mentioned c,c++,java, python languages....

[@shairamayalvarez7753]

Help.can someone explain to me about the constraints? 🥺 And how to conclude in that equation? 🙏🏻 Thanks in advance 💖

[@meghanagarre]

How many of you Got the mail that test will be between 5-16 of july...But didnt get the mail update

[@akashreddy7860]

let x denote 2 wheelers and y denote 4 wheelers vehicles x+y=v 2x+4y=w y=v-x 2x+4(v-x)=w 4v-w=2x x=(4v-w)/2 y=v-x=v-(4v-w)/2=(w-2v)/2 Now once we get v and w inputs , we can easily calculate x and y using above problems in program.

[@aashu0904]

Thank you sir

[@sahilkarnahake4517]

I will complete my graduation in 2026..but i want to prep now kuch bhi ho jaye but job apne ko chahiye mtlab mtlab chahiye

[@Ravi-tt6xw]

Hi bro, i have one doubt that my graduation aggregate is 60% exactly, can i able to attend this role or not , please reply me if anyone knows about this, please ! recently i got a mail from accenture regarding to the upcoming assessments, so if anyone knows about cutoff of a percentage please reply me !

[@ChandanKumar-uy5fv]

V = int(input("Number of vehicles: ")) W = int(input("Total number of wheels: ")) if V >= W or W < 2 or W % 2 == 1: print("INVALID INPUT") else: TW = 2*V - W // 2 FW = V - TW print("TW =",TW) print("FW =",FW)

[@Freshvideos123]

Can I get prime please??

[@soumyakantisadhu4676]

nhi

[@SeeIt03]

I joined in today's live in insta but there is no possibility of getting prime. For my career

[@ShrutiBansode-cd4pl]

First we will take input for 'v' and 'w'. And initializing tw=0 and fw=0 If (w>=2 && w%2==0 && v

[@ShrutiBansode-cd4pl]

One more thing in else part we will print('INVALID STATEMENT ')

[@sakshijain2813]

import java.util.*; public class MyClass { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int v= sc.nextInt(); int w= sc.nextInt(); int x=0; if(w w){ System.out.println("INVALID INPUT"); } else { x = (4*v -w)/2; System.out.println("TW =" + x +" FW = "+ (v-x) ); } } }

[@Kumar954-s9d]

v=int(input("no of vehicles:")); w=int(input("no of wheels:")); if(2

[@VenkateswarluJettiboina]

v=int(input("Enter number of vechiles : ")) w=int(input("Enter number of wheels : ")) if(w

[@biswajitdey2674]

Sir group is full please make a another group please sir

[@manhakkhan8666]

Is it online or offline?

[@kiranpawar8798]

//java code static void count(int v, int w) { int temp =(w-(2*v)); if(temp==0){ System.out.println("only twoWheeler are there : "+ v); }else if(temp

[@akshatkumar9879]

last question is binary search

[@hm-lq1ls]

class No_of_Vehicles { public static void main(String[] args) { int v=200; int w=540; no_of_vehicles(v,w); } public static void no_of_vehicles(int v,int w){ int two_wheel,four_wheel; four_wheel=(w-2*v)/2; two_wheel=v-four_wheel; System.out.println("Number of 2 wheel vehicles:"+two_wheel); System.out.println("Number of 4 wheel vehicles:"+four_wheel); } }

[@user-qp7rt4nk9u]

done !

[@conceptin15mins96]

ur voice is very slow pleas use mic

[@djdholan]

Total Wheels = 540 Total Vehicle = 200 (2 wheels + 4 wheels ) so x+y = 200 ----- total vehicle 2x + 4y = 540 -------- total Wheels from equation y = 200-x ------(put in equation ) 2x + 4*(200-x) = 540 2x + 800 - 4x = 540 800 - 2x = 540 -2x = -260 x = 130 --------(put in equation 1); 130 + y = 200 y = 70; so x =130 y = 70 now you get the solution code : public class sol{ main{ findNoOfVehical(200,540) } public static void findNoOfVehical(int v , int w){ int x; // 2 wheeler int y; // 4 wheeler x = (4 * totalVehicles - totalWheels) / 2; y = 200 - x sout(x); sout(y) } }

[@shivanpatil1761]

Next month we have campus placement for Accenture plz provide prepinsta prime

[@NZxNIKHIL]

from which college?

[@shwetagurav5341]

From which college?

[@vinayborate2006]

Sir please correct the question first , minimum number of houses visited we have to find !!😁😁😄😄

[@user-dh9gq9uo7z]

import java.util.*; public class MyClass { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int a= sc.nextInt(); int b= sc.nextInt(); int c=0; if(c c){ System.out.println("INVALID INPUT"); } else { c = (4*b -c)/2; System.out.println("two wheeler =" + c +" four wheeler = "+ (b-c) ); } } } Time complexity is O(1) for calculating number of tyres

[@harish9479]

24 hrs working aggreement in Accenture 😢

[@pavithrar6358]

Really??

[@harish9479]

Yes, one of my friend rejected the offer letter to this agreement

[@ayushthaku.r]

Accenture is coming next month in my college please provide me subscription 🙏

[@surajvarma5504]

public class No_of_vehiciles { public static void main(String[] args) { Scanner obj = new Scanner(System.in); numOfVh(obj.nextInt(),obj.nextInt()); } public static void numOfVh(int v, int w){ int x=0; // two wheelers int y =0; // four wheelers int r = w-(2*v); y=r/2; x=v-y; System.out.println("Number of Two wheelers is " + x); System.out.println("Number of four wheelers is " + y); } }

[@Shivambagade]

Java Code import java.util.Scanner; public class TwoWhellerFourWhellerProduction { public static void isValidProduction(){ Scanner s = new Scanner(System.in); System.out.print("Accept value of V."); int V = s.nextInt(); System.out.print("Accept value of W."); int W = s.nextInt(); if(W % 2 != 0 || V>W || 2>W){ System.out.println("INVALID INPUT"); } int TW, FW; TW = (4*V - W)/2; FW = V-TW; System.out.println("TW:"+TW+ " and FW:"+FW); } public static void main(String[] args) { isValidProduction(); } }

[@bgmilovers5931]

v = 200 2 w = 540 if ( w < 2 or W

[@varun1017]

OA dates?

[@sandy24_sunshine09]

v=int(input("Enter v:")) w=int(input("Enter w:")) if v>=w or w

[@boopathi121]

It is python code?

[@Lm-mu1up]

Give c++ code too

[@PrinceKumar-ig5oc]

jai javan jai kisan

[@CodeWithMeInJava-1]

Tw=(2*V)-(W/2) FW=V-TW

[@Techno_lengend]

Please any one help me ..for coding.round

[@justforfun2043]

v=int(input()) w=int(input()) x=0 y=0 if w>=2 and w%2==0 and w>v: y = int((w-2*v)/2) x = int(v-y) print("Two wheelers:"+str(x)) print("Four wheelers:"+str(y))

[@Ruthvik_20]

Prepinsta❤

[@user-vk5ko9pi6f]

Hello, I rent accounts on freelance exchanges

[@navaprasadgoud9530]

fw=(w-2*v)/2; tw=v-w; print("%d %d", &tw, &fw); I hope this two equ can be enough to solve the problem

[@vaddineni5182]

in java import java.util.*; public class sai { public static void main(String[] args) { Scanner s = new Scanner(System.in); int v =s.nextInt(); int w =s.nextInt(); int x=0,y=0; for(int i=1;i

[@Aa-cm1eo]

SOLUTION FOR FREE PRIME

[@AnuBiju-y7e]

v=int(input("enter vechiles number")) w=int(input("enteer the wheels no")) for i in range(0,200): for j in range(0,200): if(i+j==v): two=i four=j if(i*2+j*4==w): print("2wheell 4wheeler",i,j) break

[@rjshakti54]

Bhai nahi hua😢😢

[@anamtaxxxkhan]

On-campus start hogaya?

[@arghyadeepsarkar5759]

Need prime badly 😢

[@ammulu6150]

Bhai tumney leliya prime

[@darjiabdulmouize4302]

import java.util.*; public class Main { public static void main(String[] args) { System.out.println("Hello World"); Scanner sc=new Scanner(System.in); int v=sc.nextInt(); int w=sc.nextInt(); int z=w/2; int cars=z-v; int bikes=v-cars; System.out.println(bikes+" "+cars); } }

[@sayanbhattacherjee9829]

#include #include int main() { int i, vehicle, wheel, twCount=0, fwCount=0; printf("Enter vehicle that should be manufactured : "); scanf("%d",&vehicle); printf(" Enter wheel number : "); scanf("%d",&wheel); if(wheel>2 && wheel%2==0 && vehicle*2

[@MonaKumari-h4i]

import java.util.Scanner; public class VehicleManufacture { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); int V = scanner.nextInt(); int W = scanner.nextInt(); // Constraints check if (W < 2 || W % 2 != 0 || V >= W) { System.out.println("INVALID INPUT"); } else { // Calculating the number of two-wheelers int TW = (4 * V - W) / 2; // Calculating the number of four-wheelers int FW = V - TW; if (TW < 0 || FW < 0) { System.out.println("INVALID INPUT"); } else { System.out.println("TW = " + TW + ", FW = " + FW); } } scanner.close(); } }

[@anilkumarvagicharala8258]

import java.util.Scanner; public class Vehcile{ public static void main(String[] args){ Scanner sc = new Scanner(System.in); System.out.println("enter the no of vechiles"); int v = sc.nextInt(); System.out.println("enter the no of wheels"); int w = sc.nextInt(); int tw = (4*v - w)/2; int fw = v-tw; if( tw>=0 && fw>=0 && (2*tw + 4*fw == w)){ System.out.println("no.of tw:" +tw); System.out.println("no.of.fw:" +fw); }else{ System.out.println("no vaild"); } } }

[@balasubramanie5354]

// Online Java Compiler // Use this editor to write, compile and run your Java code online import java.util.Scanner; class HelloWorld { public static void vehiclesProduced(int v, int w) { //x -> 2 wheelers y -> 4 wheelers //x + y = v //2x + 4y = w //y = (w - 2v)/2 //x = v - y int y = (w - 2*v)/2; int x = v - y; System.out.println("Two wheelers: "+x+" Four Wheelers: "+y); } public static void main(String[] args) { Scanner in = new Scanner(System.in); int v = in.nextInt(); int w = in.nextInt(); if (w < 2 || w % 2 != 0 || v >= w) { System.out.println("INVALID INPUT"); } else { vehiclesProduced(v, w); } } }

[@149-cse-sumandhar3]

import java.util.Scanner; public class VehicleProduction { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print("Enter the total number of vehicles (V): "); int V = scanner.nextInt(); System.out.print("Enter the total number of wheels (W): "); int W = scanner.nextInt(); if (W >= 2 * V && W % 2 == 0 && V < W) { int FW = (W - 2 * V) / 2; int TW = V - FW; System.out.println("Number of two-wheelers (TW): " + TW); System.out.println("Number of four-wheelers (FW): " + FW); } else { System.out.println("INVALID INPUT"); } scanner.close(); } }

[@BhavishMK-h8g]

v = 200 w = 540 if w

[@ankushbokade6085]

def wheels(Tw,Fw): Sum=(Tw*2)+(Fw*4) print(Sum) Tw=int(input("enter the no. of TW = ")) Fw=int(input("enter the no. of FW = ")) wheels(Tw,Fw)

[@SathishSathish-qn3ol]

v = int(input("Enter the total number of vehicles: ")) w = int(input("enter total wheels: ")) tw=(4*v-w)//2 fw=v-tw print(tw) print(fw)