Accenture Previous Year Coding Questions & Answers | Live Coding Class - 3 | Accenture Coding Exam

[@LokeshBagora]

drive.google.com/drive/folders/1DGtldtHELjxe1D__L2dE9QypD_B-Tm72?usp=sharing

[@saishiny6684]

Please provide the answers in java for all the questions

[@LokeshBagora]

drive.google.com/drive/folders/1DGtldtHELjxe1D__L2dE9QypD_B-Tm72?usp=sharing

[@FutureGuide999]

Hi lokesh bro I got mock test mail it is mandatory to qualify for next steps and what type of questions they ask in mock test how many questions are there is there any cut they mentioned it will active till 1 wed 10pm

[@nayan7624]

Hi, I even got a mock test mail, I have attended today and there will be 2 rounds, in the first round there will be 6 MCQ questions and after that there will be 2nd round in this round there will be one coding question( I got Write a program to reverse an integer value 54321) u can type the code in C,C++, java and python. That's it bro.. And this evening around 6:30pm I got an Assessment link which is on Saturday and also got an admit card, hope this helps you.

[@FutureGuide999]

@@nayan7624 Thanks bro for your response what type of questions they ask if you don't tell about that

[@nayan7624]

@@FutureGuide999 I can't remember the exact questions which they asked in 1st round as MCQ's but those are very basic questions, in 2nd round I got that question which I have mentioned in previous comment. And did you get Assessment mail this evening??

[@LokeshBagora]

Hi its just normal test

[@ayanbhattacherjee9089]

About The 1st problem... Is it only applicable for Real roots? Because otherwise I am getting NAN as root values in java.

[@ushasreeroyal1955]

Use Math.floor() method in root two

[@chandanikumari3778]

import math def roots_of_equation(a, b, c): discriminant = b**2 - 4*a*c if discriminant < 0: return "Roots are complex numbers" else: root1 = (-b + math.sqrt(discriminant)) / (2*a) root2 = (-b - math.sqrt(discriminant)) / (2*a) return root1, root2

[@user-qp7rt4nk9u]

d = dict() letter = 'bbadbbababb' j=0 for i in range(1,12): if i not in d: d[i]= letter[j] j +=1 print("input string: ",end="") for i in range(1,12): print(d[i],end="") print() for i in range(1,12): if (d[i] == 'b'): d[i] = 't' print(" updated string: ",end="") for i in range(1,12): print(d[i],end="") is this ok ?

[@dhivyadhiya9369]

Is there any numerical aptitude in Accenture assessment?

[@LokeshBagora]

reasoning verbal and critical thinking

[@Swapna-ey2ui]

Is there any chances of repeated questions in coding section

[@motheadilakshmi]

Hi anna everytime I am receiving the update from Accenture.You are not eligible.upto now i didn't take any test.What's the reason anna

[@dgjsbdbk]

same happened to me.Apply with another mail👍

[@FutureGuide999]

I am waiting for your reply

[@rittikasarkar8318]

Pls send the code in java sir

[@LokeshBagora]

drive.google.com/drive/folders/1DGtldtHELjxe1D__L2dE9QypD_B-Tm72?usp=sharing

[@FutureGuide999]

Reply reply my query i have no idea about it

[@Swapna-ey2ui]

Getting errors while excuting