Acid/Base Dissociation Constant

[@jasongulizia737]

its crazy how this 8 minute video did so much more to teach me this concept then a whole semester long biochemesty class ever could

[@TheScienceClassroom]

I'm so glad it helped!

[@brianwong3971]

HAHAHAHA idk what's so funny, but the acids are laughing at me

[@solaimanwahab5286]

bro you on some acid stuff and i dont mean the chemicals haha

[@hannah6133]

yall's comments are so underrated lmao

[@solaimanwahab5286]

God bless you man. Chem final 14hours(tomorrow) and here i am pulling off an all nighter. Wish i had saw this video before hand because i spent 3 days on this topic with our notes and it didnt make any sense. Your videos with practice taught me in 30minutes

[@srilaxmipb]

I was feeling extremely disassociated and was trying to watch videos about it, even though I know I shouldn't. I am glad I ended up here. This made my day. I miss studying chemistry!

[@Hyerayuna]

Omg u cleared my years of doubts so easily.. our professor take weeks to finish one topic still it's hard understand the concept properly.. im glad i found this video ❤❤

[@TheScienceClassroom]

😃 this can be a tough concept, great work!🎉

[@Loser-it2wg]

​@TheScienceClassroom im glad you're still active almost a decade later

[@mealswithbarakah4032]

This was EXTREMELY helpful.Thank you for taking your time to make this video.👍🏽

[@TheFG177]

Very helpful 8 hours before my P. Chem Final

[@studyharder8360]

did you pass?

[@migster8570]

did you pass?

[@TheFG177]

@@migster8570 I did! I've since graduated and started my career

[@TheFG177]

@@studyharder8360 I did!

[@celeste2221]

@@TheFG177 ayeee congrats!!

[@alyssabesser1099]

I've watched half a dozen videos trying to understand Ka/pKa and this is the first one I get. good vid.

[@damolabadmos5093]

so marvellous.... lecturers don't go to this extent 🌹🌹

[@PeaceLove645]

amazing, very helpful in me brushing up on a bit of gen chem for my biochem class! clear and to the point, thank you

[@angelicac.pacheco5551]

By far the best explanation out there!!

[@Redpanda.1403]

I love your video so much!!!!

[@TheScienceClassroom]

Thanks! 🤗

[@hindalhammadi27]

Thank you for your excellent explanation, it was very helpful.

[@BlessUpDiHerbs]

Where did the .09898M value come from for the reactants part in the Ka equation??

[@faithakoth7391]

0.10_1.32*10^-3

[@karelycantu]

Thank you so much! Now it makes perfect sense

[@sanketkhajuria9542]

Thanks ,you are really a good teacher 👍👍👍👍👍

[@DavidAbomah]

Keep up the good work.

[@TheScienceClassroom]

Thanks, will do!😀

[@Redpanda.1403]

I have a question. The concentration of HCl you mention in the video is the one remaining after the reaction completing or it is the total one of the initial HCl when the reaction has not happened yet? May your guys explain it for me? thanks a lot

[@aydis1s-li9dt]

We calculate the ka when the reaction is in equilibrium [HCL]final

[@Redpanda.1403]

@@aydis1s-li9dt I understand now. Thanks!

[@TheScienceClassroom]

aydis1s-li9dt already answered, but just wanted to say that they are correct!💯

[@yowhatsup-x3b]

Genuinely useful and cute at the same time..no bluff..

[@astha_yadav]

Thanks! Great Explanation

[@ferdrewflores3612]

Please: where did 0.09868M came from. Thank you ! )))

[@bobeggplant8901]

What would the Ka be of a buffer solution? Would it still follow the same process or is it always going to be some value?

[@charliemagdics6980]

poo

[@zack150]

great video but you said a hydroxide ion makes a base but really you should use the bronstead-lowry definition for this level chemistry

[@qud_ratol]

since HCl is a strong acid so we can't write HCl in the denominator. And so we can't calculate Ka for strong acids like HCl. Its Ka is infinite. Is not it?

[@TheScienceClassroom]

+Qudratol Wazir You are correct. HCl is a strong acid and essentially dissociates completely. We would never actually calculate the Ka for HCl because our answer would be nonsensical. We can still write the equilibrium expression for the dissociation for HCl because theoretically, nothing dissociates completely. It is reported that the Ka for HCl is 1.3 x 10^6 depts.washington.edu/eooptic/links/acidstrength.html. I'm not entirely sure how this value was determined (for a Ka, it is essentially infinite since it is greater than 1).

[@myatminsoe9282]

Thz Sir,however I have a question, for example if the dissociation constant of water is 1M`2 , it means 1 mole of hydrogen and hydroxide ions are present in 1 litre of water at 25°C.(btw I knew the number is incorrect).So, my question is if the dissociation constant of a certain acid is 1M, which stands for mol and which stands for 1 dm3 of solution?

[@bxglizzo8]

I was good until you lost me at 0.09868 M. How did you get that number? Can you please show me step by step on the calculator. Please! thank you

[@_loci1_avoidkv28]

He subtracted 0,00132 from 0,1.

[@bxglizzo8]

thank you so much!!!

[@_loci1_avoidkv28]

Amy Loc You're welcome!

[@sharadapalangappa5450]

Hhghbh

[@benjaminyellin5095]

at 3:18 you say that the biggest value Ka could be is 1...but wouldn't that mean that only half the acid is dissociated (same number in denominator and numerator)? Thanks!

[@MatthewLaberge-po2cz]

That means 1/1, which is 100%, not 1/2

[@tomcruise9317]

Bro what is the use of ka ...what dose it telll you you find it what dose it imply

[@lesleytan6791]

thank you! this helped a lot

[@avastaunton1258]

This was so helpful.

[@moceasar671]

what about the volume? i thought to use that Ka equation we needed concentration and concentration=moles/volume. i dont know just want help. thank you

[@kadyr8935]

0:18 The Joker was here.

[@Loser-it2wg]

Ha ha ha

[@tabithalewis5942]

How do you get the 0.09868M ?

[@danielburke6534]

why didn't you add the 1.32x10^-3 before subtracting them from the .1M? The H+ and CH3COO- are both 1.32x10^-3. If they ended up with a 2:1 instead of 1:1 ratio, wouldn't that change the answer?

[@rebecca421]

thnq u sir . keep on uploading !!

[@Umairahmad1989]

great video!

[@melodylanee]

Cant we use pka=-logka or something instead of the ice table?

[@vuyolwethunkosi6536]

Am saving this video for my mates😂👌🤲

[@jvyokubjonov3259]

Bruh, it was asked to find the dissociation constant instead association one. But it does not matter/ Thank you man)

[@elenawinchester9377]

i dont get how the [H+] of 1.32x10^-3 became a change in concentration

[@alexandery8508]

Are you confused of how c.H+ went from 0M to 1.32x10^-3M? The professor took the fact that the concentration would be the same for the products according the same coefficient. You need to understand what more about the coefficients.

[@alexandery8508]

Or are you confused of how this could be a change? It is a change from 0 (which u didn't think) and it is not a change from 1.32 x 10^-3, yes.

[@alexandery8508]

The professor meant the change between 0 and 1.32x10^-3.

[@alexandery8508]

0 is a substitute for x

[@BrotherKyle22]

Nice

[@AvaneeshYadavkingoftheworld]

Great video

[@BreyonnaMorgan18]

Then, what do I do with it.

[@Chel12354]

Where did you get 10^-5? in the final answer of Ka = 1.77×10^-5 hope this will be answer 😞

[@itzjowii]

Could you explain what you don’t get so I can try to help

[@marialyn5212]

Why didn't you do double arrows this reaction is not one way smh

[@qud_ratol]

Great Chart

[@monarcque]

where'd he get E=0.09868 M?

[@innosense6873]

What is pka

[@Tudi500]

pka is the value of a substance where half of the substance is in loaded form and half is uncharged form.

[@TheElectrozoid]

it is the -log(Ka). the smaller the pKa of something, the stronger an acid it is.

[@ryantheviolin3983]

whos here in 2024 😂

[@APC-t8h]

I got 1.77x10-6

[@sameershahab1940]

Who is from India here

[@sameershahab1940]

But I am Indian

[@celeste2221]

Not me✌️

[@louisehumphreys9500]

Lis t strong acids

[@swindler1570]

HA HA HA HA HA HA

[@jewswrld9732]

Sam is a chungus

[@jewswrld9732]

Samuel Goldberg shut up concert band material

[@jewswrld9732]

Samuel Goldberg really? Last time I checked people play you like you play the tuba

[@kathleenglazeblancia4889]

Send help. HA HA HA

[@frenchmannhfgw4412]

wow that was completely useless