Acids and Bases - Buffers

[@alisonramirez5314]

At 7:00, can you explain why the [A-] equals 2.99? What do you mean by 0.01 mol gets consumed by the hydrogen ion concentration?

[@MedSchoolCoachMCATPrep]

You initially have 3 moles of CH3COOH (HA) and 3 moles CH3COO- (A-). When you add 0.01 mol of HCl, that will dissociate to give you 0.01 mol of H+ ions. That 0.01 mol of H+ ions will react with 0.01 mol of CH3COO- to form 0.01 mol of CH3COOH. You now have 3.01 mol CH3COOH and 2.99 mol CH3CHOO-

[@Nna_anne]

Wow. This lesson made headache. I am still confused and tomorrow is my exam. This acid and bases and buffer were the only who I didn’t get it but trying my best to understand it.

[@gardlesskaira8984]

Wow thank you very much 🔥🔥

[@MedSchoolCoachMCATPrep]

You're welcome 😊

[@fariborzaf3159]

Hi, why don't we use 3 for molarity of the conjugate base? Doesn't the acid also dissociate into H+ and A-?

[@sabanorouzifar8805]

🙌 Thank you!

[@ryyannie]

Sorry, just to clarify - for the second example, does [A-] refer to NaCH3COO and [HA] refer to CH3COOH?

[@MedSchoolCoachMCATPrep]

Yes, [A-] is for CH3COO- and [HA] is for CH3COOH!

[@wakamanrashid]

brain explosionnnnnn