Address Translation Mechanism of Microprocessor 80386, Memory Segmentation

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[@madanmohanpachouly6135]

Very good explanation. Thanks

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[@01.abhishekkumar33]

sir mu doubt is ,in 8086 we have seen we have 20 bit address ,so total memory size was 2^20 means 1 mb and it was divided into 16 segments,each segment of 64k but sir here inj 80386 we have 32 bit adrress ,so total 2^32 means 4 gb total size of memory would be there ,but here 4 gb is size of one segment,how sir please explain sir

[@EngineeringFunda]

In 80386 we use virtual memory concept. See the concept of GDT and LDT and you will be able understand it.