Advanced Linear Algebra, Lecture 3.4: The determinant of a linear map

[@fsaldan1]

On 18' I don't see that l(x5)=0. But you don't need it. If x4=x5 then the two remaining terms equal f(x1,x2,x3,z)l(z) except for the sign, with z=x4=x5, and are negatives of each other.

[@cascave5756]

i was thinking the same thing