BCD Codes (Binary Coded Decimal Codes) Explained

[@ALLABOUTELECTRONICS]

Timestamps: 0:00 Introduction 0:40 8421 BCD code 1:53 Decimal to BCD (8421) Conversion 3:11 Hexadecimal to BCD (8421) Conversion 4:43 Octal to BCD Conversion 6:08 Binary to BCD Conversion 7:20 Other BCD Codes (2421, 5421, 84-2-1) 10:24 XS-3 Code 11:52 Decimal to XS-3 conversion

[@DuyênHoàngThị-q2w]

Find BCD8421 code of the decimal numbers: - 35 , help me please

[@shaianrahman1785]

Great video! I have learned so much and so easily in such a short time. Very informative and thanks for making a segment for each topic.

[@lalruotlien2755]

I'm very new to binary numbers and I learnt alot👍

[@PP4633]

Just one word: EXCELLENT

[@yogeshpatel9353]

Explained in very good way.Nice👌❤️

[@mayurshah9131]

VERY WELL EXPLAINED VERY GOOD 👍👍

[@poojashah6183]

Best explanation👌🏻👌🏻👍🏻

[@harshwaghela8221]

How do you teach so perfectly ❤️

[@kishangaur6683]

Thanks sir for your support .you really explained well.

[@ParamitaDey-bi1mg]

Ans: 13:20 is 011110101001. Is it correct ?

[@TechnoYT06]

no

[@Problem_Solut1ons]

(734)8 = Excess - 3 code = 0111_1010_1001. -- correct

[@hanifah6466]

@@Problem_Solut1ons i think first we're gonna change 738 into decimal, that's 144. and then to bcd that's 000101000100, and last into XS-3 = 010001110111

[@davadoff]

@@hanifah6466 734 base8 in decimal = 476 4 in binary, 7 in binary, 6 in binary, in XS-3 coding = 011110101001

[@davadoff]

734 base8 in decimal = 476 4 in binary, 7 in binary, 6 in binary… in XS-3 coding = 011110101001

[@raghavdubey9138]

Octal to binary conversion at 6:03 is not correct it should be 110010001... ; please check it once

[@ALLABOUTELECTRONICS]

Its not octal to binary, its octal to BCD conversion. What you are saying is octal to binary conversion.

[@akhilajay1864]

Thankyou. Very much helpful. 👍

[@subhendupal2541]

Helpful video 👌👍

[@syedm.hussnainraza8798]

Nice Explanation ❣.

[@ДимаГерасимов-р4э]

Thanks for the explanation

[@PELİNÖZDEMİR-k1n]

thank you you are the best

[@sohammahure6672]

Very nicely explained

[@nikhilkashyap2411]

Hi, are there any lecture slides/handouts available for the content you are teaching ? Please let me know. Thanks

[@ALLABOUTELECTRONICS]

Some of the notes are updated on the website. Please check there. I am planning to update the remaining notes there very soon. Here is the link: www.allaboutelectronics.org

[@ankitmehta6875]

Thank you for sharing this video

[@gurujeetyadav4273]

9f = 000110111111 101101 = 01001011 Is it correct?

[@Shiva671]

Hello Here in 2421 BCD , BCD of 5 is 1011 but it is also 0101 so which one is right ?🤔

[@ALLABOUTELECTRONICS]

The code is assigned such that, the number 5 to 9 are mirror image of 0 to 4. (Replace 1s by 0s and 0s by 1) Also, it is a self complementing code. Meaning that, you can find the 9s complement of the number by replacing 0s by 1s and 1s by 0s. I hope, it will clear your doubt.

[@Shiva671]

@@ALLABOUTELECTRONICS understood.. Thanks 👍🏻

[@ashutosh1513]

But sir like code of 1 is 0001 and according to 9's complement code of 8 should be 1000 but if we multiply by weights to digits we aren't getting 8 we are getting 2

[@meghana9478]

So useful❤

[@ambatisivaji1807]

Bro plz tell me.... " ITI - ELECTRONICS " Trade basic caliculations based on all farmuls

[@rahula9008]

How to find BCD code of letter "BASE"

[@isharajput9991]

Sir how to implement table.for 5421 code

[@fggj6349]

Thanks great job

[@imAman001]

13:17 011110101001 this is right

[@Morgen_Maxwell]

GOOD TEACH

[@arkodasgupta0412]

in 8 4 -2 -1 and 2 4 2 1 BCD codes, I noticed that some decimal numbers can be represented in more than 1 way. So, can I represent them in any way ? or the way as shown in the video ?

[@ALLABOUTELECTRONICS]

2421 and 84-2-1 are self-complementing codes. That means you can find the 9s complement of the number just by replacing the 1s by 0s and 0s by 1s. For example, the 9s complement of the number 4 is 5 (9-5). So, in these codes, if you see the code of digit 5, then you can find that code by replacing 1s by 0s and 0s by 1s in the code of 4. And the weights are assigned accordingly. That means although it is possible to represent the number in multiple ways, we should use only that code, where the above condition (self-complementing) condition gets satisfied. I have also covered one example based on that recently on the second channel. Please go through it, you will get it. Here is the link: kzbin.info/www/bejne/h6iXgn6Mq5mCi9Usi=b_AZA1WLvnYXCVub

[@arkodasgupta0412]

@@ALLABOUTELECTRONICS ok sir understood. Thank you

[@KandhanM-n1o]

do we need to put base 2 to BCD code like we do for binary numbers or to write BCD code without base value

[@ALLABOUTELECTRONICS]

No just write without base.

[@shivlidimri151]

in 4221 bcd, how do we know which 2 we'll have to use to represent say decimal 2 and decimal 5

[@ALLABOUTELECTRONICS]

The code is assigned such that, the number 5 to 9 are mirror image of 0 to 4. (Replace 1s by 0s and 0s by 1) Also, it is a self complementing code. Meaning that, you can find the 9s complement of the number by replacing 0s by 1s and 1s by 0s. I hope, it will clear your doubt.

[@VanishreeNm]

What is the value of F here? generally how we can find the alphabets values?

[@ALLABOUTELECTRONICS]

F is typically used in Hexadecimal number system. I assume you are asking, the corresponding BCD code for F. So, F in decimal is equivalent to 15. So, in BCD format, we will have two digits (1 and 5). so, we need to represent each digit in 4-bit BCD form. Therefore, F in hexadecimal is equivalent to 0001 0101 in BCD. Similarly, if one wants to represent A (which is 10 in decimal), then it is equivalent to 0001 0000. I hope, it will clear your doubt.

[@ParamitaDey-bi1mg]

Sir in 6:03 why you took 4 bits for octal it supposed to be 3?

[@ALLABOUTELECTRONICS]

4 bits are for BCD. Here, first octal number is converted into decimal. And then each decimal digital is represented into equivalent BCD representation using 4 bits. Please watch that portion once again, it will get clear to you.

[@ParamitaDey-bi1mg]

@@ALLABOUTELECTRONICS Ooo... Okay I understood now .. I thought no.of bit of BCD is same as no.of bit of binary . Thanks sir now my doubt is cleared because of you Thanks

[@tanishsharma5400]

Last ques of converting 5c to xs3, 5c must be 81, you wrote it 92, how so?

[@ALLABOUTELECTRONICS]

5C is in hexadecimal. If you convert it into decimal then it is 92. (5*16 + 12*1 = 92). Please check it once again, you will get it.

[@isuisu557]

Thank u so much

[@Kondalu.810]

Why we cant use 4+1=5 Why you use 2+2+1=5

[@Kondalu.810]

in 2421 code

[@ALLABOUTELECTRONICS]

The code is assigned such that, the number 5 to 9 are mirror image of 0 to 4. (Replace 1s by 0s and 0s by 1) Also, it is a self complementing code. Meaning that, you can find the 9s complement of the number by replacing 0s by 1s and 1s by 0s. I hope, it will clear your doubt.

[@puneethvm]

👌

[@sahithiprasuna-eq3oj]

13.39 ans Bcd to ex-3code :011110101001

[@Maheshyt6686]

Hii bhai mujhe ITI all formulas

[@Maheshyt6686]

Please help me

[@uzmashireen3405]

[@Kav.yeahhh]

9F= 000101011111 101101= 01001011

[@catailen69]

00110010001000001 that’s the bcd code 1:11

[@tatsuyasan4101]

011110101001 is the answer

[@vijayasreedhulipalla1295]

Ans 000110111111 n 01001011

[@ananymous7595]

Wrong.

[@janees809]

@@ananymous7595 what is the correct answer then?

[@tasnimhaider-d1g]

thank you so much