Analysis of 3 Span Beam by Moment Distribution Problem | 1 End Fixed and another End Hinged Beam

[@shreyawaghmare6389]

Thank You Sir. It helps very well in my Endsem

[@wish.289]

why at joint B u make it negative and point C u make it positive for balancing? I need clarification

[@thephenom9137]

Sir in my exam a question came in which I had to analyse a frame using moment distribution method. But I got confused as, in question it was written that all members have equal flexural rigidity but in diagram one member had different moment of inertia . So what should be done in such situation.

[@frankastudillo2296]

How about if one of the spans has a combination of uniform load and a concentrated load not located at the mid-span. How is the FEM calculated in this scenario?

[@ROYTANYI]

thanks the video is useful

[@structuralanalysisanddesign]

Glad it was helpful! All the best

[@dinushirathnayaka409]

thank you, nice lesson

[@PanchamiGowda-ci8mo]

Sir is this method can be done in 18schem also?.....gotta clear this backlog subject...plz do reply

[@kashifshakeel3022]

Sir can we take stiffness for fixed and intermediate support as I/L and for roller ,SS and hinged support as 3I/4l. Is these values are correct

[@acereg4382]

did u get answer for this question

[@BRane-mo9wx]

Sir why the I is different for all three span?

[@Rwngswkang]

Sir in Distribution factor table why we take D in last video u don't take D

[@mohithkumar6108]

Sir can we get classes for DSMS

[@structuralanalysisanddesign]

From march i will be uploading steel structure videos, keep watching

[@Ammuhvr07]

@@structuralanalysisanddesign i am also very excited to see 🙈 waiting for your DSMS videos ..

[@akgamingmafia1031]

Sir kani s method start kab karr rahe hoo sir ?

[@structuralanalysisanddesign]

Next set of videos will be on Kani's method, keep watching and sharing

[@jamiuabdulrahman4392]

Thanks very much sir

[@onlinepg4066]

How comes 4EI/ L ???? ANY DERIVATION ??

[@NataNata-ur5bf]

It is the rotational stiffness(k) for fixed far end in a propped cantilever beam , from M=kθ, where M is the moment, θ is the slope and k is rotational stiffness which is equal to 4EI/L.

[@NataNata-ur5bf]

Although u could simply find k with I/L for fixed far ends And 3/4×I/L for any other conditions

[@adeelhassan2145]

4:25

[@As-Sõfiyah8443]

Thanks

[@MR.Volog96]

Slop and deflection method sir es topick ka video banaye sir

[@MR.Volog96]

Or dam

[@structuralanalysisanddesign]

Hello Slope deflection method is already uploaded

[@atharvapatil2453]

4:24 should be -9

[@rameshtiu2506]

Plz help me with this problem a type 3 post tensioned prestressed concrete beam of 10 M span The Beam is post tension is in 3 high tensile bar of 40mm diameter located at an effective depth of 700mm.The effective prestressing force in each bar after all losses is 600 kN. Given f=40 N/mm².f,= 1035 N/mm². E,= 200 kN/mm², E=28 kN/mm², com- pute the width of cracks in the tension zone if the service load moment at mid span is 1040 KN m,

[@structuralanalysisanddesign]

Sorry Ramesh, currently I am not in touch with prestressed concrete subject, in future i will definitely try, thanks for watching

[@pallanithin300]

Thank you so much sir

[@lamuyeayobami1862]

Thanks