Python Programs - Armstrong Numbers

[@sportslover8396]

Daily night before sleep one tutorial , just for your voice, so soothing... Get good sleep. By the way ur tutorials are great

[@AmulsAcademy]

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[@exploringnaturalbeauty2102]

Tharki lol 😂

[@channelrex5238]

😂

[@thirumala_reddy]

I feel lot happy after watching this video ...I watched lot of videos about how to write armstrong number ...I feel lot of confusion...then I watched this vdio...ur explaining very clearly ...really osmmm to the way of explaining ...Thank you so much for clarifing my doubt...

[@AmulsAcademy]

My Pleasure:)

[@gujaratiincanada2464]

I have seen many video related to python program logic, but no one is like this channel

[@AmulsAcademy]

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[@KokilRaj16YT]

Alternative method: num=int(input("Enter number range from 1 to :")) arm=[] for i in range(1,num+1): l=len(str(i)) s=0 for j in str(i): s += int(j)**l if i==s: arm.append(s) print(f"The Armstrong numbers from 1 to {num} are: ") for k in arm: print(k)

[@harisankarpanigrahi167]

Madam no word is coming to my mind to explain your knowledge...and most importantly way of teaching..I am your big fans mam...

[@AmulsAcademy]

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[@learnwithsonu708]

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[@AmulsAcademy]

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[@deepakNeetiVlog]

I was looking for this type of concept finally i got this thanx for your precious efforts ❤️🙏

[@AmulsAcademy]

Most welcome 😊

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[@AmulsAcademy]

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[@sricool394]

U r the best python teacher I’ve ever met ur way of teaching is the best 👌👌👌👌

[@AmulsAcademy]

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[@akanshasabre5352]

you are the best ma'am seriously

[@AmulsAcademy]

Thank you :)

[@bendiindhu4616]

I don't know how to write a program in easy way now I am watching this video it's very easy and simple tq very much sister😊

[@techsbooster44]

I like the way of explanation,this is very useful ,who wants to learn python, 👍

[@Dreamer_music1366]

Easily explained. I searching for a great video to understand amstrong numbers program. Finally i found it. Thanks for the video mam

[@AmulsAcademy]

Glad it was helpful!

[@ahmadnadeem870]

To make it more easy, i just typecast the number to get each part separately. Means apply for loop on str(153)

[@sumitjha3033]

mam your explanations are just accurate that any beginner can understand them without any doubt

[@AmulsAcademy]

Glad to hear that 😊

[@ustaad9220]

the 20 minutes were worth the video. thank you :)

[@AmulsAcademy]

Thank you :)

[@RohitVaghasia23]

Best explanation by you madam , i check many websites and video but u explain so deeply and slowly and each of point...WOW (JUST 4 U)

[@AmulsAcademy]

Thank you so much :)

[@vikasni95]

One of the best tutorial which ihve saw in my life... U r just amazing sister... Uhve taken time and explained smoothly... Wow sis keep Going.. God bless u sis

[@AmulsAcademy]

Thank you:)

[@tubakhalid5222]

I wish i had a teacher like you in my college....thank you so much

[@AmulsAcademy]

Pleasure 😊❤️

[@SJ-wr3le]

I am so thankful that you're videos are in english and because of that I have subscribed😊

[@AmulsAcademy]

Welcome!! :)

[@aswinvignesh3985]

Really fascinating to see you teach like this ! . missed your channel during my early days . great teaching by looping the process step by step till the end . Keep exploring new stuff and Thank you This is my comment by just viewing ur 1st video . Hope I will finish this playlist

[@renugadevi611]

wonderfull explanation mam, Guys don't waste your money for joining courses in python just watch all videos in Amul's academy

[@AmulsAcademy]

Thank you :)

[@Nothingtosaymore]

I am very much thankful for you because I was looking for this type of concept finally I got in your videos from that day I searching for your video to clear my doubt and improve problem solving skills . And I have become your permanent subscriber 😊

[@amolnagrale9628]

Best explanation by you madam , i check many websites and video but u explain so deeply and slowly and each of point...WOW (JUST 4 U) & kudos 👏👏

[@suhailshahkhan6858]

I am yet to decide how many thanks i still owe for the solution approach.. Outstanding explanation ! Thanks a lot

[@sefali0566]

Man u r doing a great job by making these videos and helping millions. Thanks man keep up the good work.

[@hometv4061]

dude she is a woman!!!!!

[@MINATO-tl6yt]

dude wat r u doing rn......

[@sunildalawai6600]

i watched many video's on this concept none of them as cleared as this, excellently done

[@AmulsAcademy]

Thank you : )

[@ankitjain6288]

I have got so benifit for this toturial this is very helpful for learning program and also logic

[@AmulsAcademy]

Thank you :)

[@vivekkulkarni5081]

One of the best and finest explanation mam .hats off to your effort

[@AmulsAcademy]

Thank you 😊

[@maker4986]

You are really amazing Guru.Thank you very much mam.I dont like math.But since iam preparing for interview I need to learn.Your logic,way of explaining the concepts were just like Thirunel veli alwah.Flows smoothly into the memory of my brain.Thank you verrrrry much and have a great year.

[@SDE_FACT]

Your teaching skills are awesome Loved your videos and believe me this is a very helpful playlist of python programs❤️ Thanks

[@AmulsAcademy]

Glad you like them! :)

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[@ruturajjadhav8905]

I am in love with your teaching skills. Very nicely explained. Thank you for doing this free. 😍😍😍

[@AmulsAcademy]

It's my pleasure :)

[@sameulkumar7182]

wow ! what a explanation mam it went straight into my head>

[@AmulsAcademy]

Thank you:)

[@chanducam4433]

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[@lohithv5060]

One of the finest explanation 💯💯

[@AmulsAcademy]

Thank you 😊

[@anubhavsingh2916]

TO FIND ARMSTONG NUMBER IN A RANGE class armstrong: def __init__(self): self.n = int(input("Enter Number to check Armstrong : ")) def check(self): for i in range(1,self.n+1): total = 0 d = str(i) for j in d: total += int(j)**len(d) if total == int(d): print(total) ar = armstrong() print(ar.check())

[@AnkishAgrawal-g9w]

mame your teaching style is osm i am waiting all videos of python practice set

[@syedamaanhasan7340]

Your explanation is really superb and its helping me a lot to understand Logics and code.

[@AmulsAcademy]

Glad to hear that :)

[@nareshm858]

Mam your explanation is so good mam. I am understanding the topics very clearly

[@AmulsAcademy]

Glad to hear that 😊

[@nishanths2486]

i fell in love with the voice and the way of explanation. Great tutor i have come across.

[@AmulsAcademy]

Happy to hear that!

[@ganeshmirisker4173]

You deserve many more subscribers All the best 👍 you have wonderful voice 👌

[@anilmacharla6939]

Thanks Amulya..Love the way you teach!

[@AmulsAcademy]

Thank you 😊

[@halonarikadapa7971]

Wow...., great👏👏 explanation is super good!! Tysm

[@AmulsAcademy]

Thank you 😊

[@bigbro5089]

This girl is a genius !!

[@AmulsAcademy]

Thank you :)

[@anindyakarak198]

Finally cleared my doubts with all concepts

[@shaileshsarda5694]

Another alternative method to calculate the Armstrong Number: ### Get the number n = int(input("Enter the number: ")) ### Convert to string n1 = str(n) ### String Count count = len(n1) ### add a string to list n1 = [int(i) for i in n1] ### find the power of each number by its count and store in D list D = [ ] for i in n1: j = i ** count D.append(j) ### Initiate the dummy variable for the addition of list sums = 0 for num in D: sums += num ### Driver function to check the number is Armstrong or not. if n == sums: print("Its Armstrong Number.") else: print("Not an Armstrong number.")

[@sree4721]

💖

[@abhishek007123]

Legendary explanation..!! 👏👏👏👏👏

[@AmulsAcademy]

Thank you :)

[@AishusAura]

very efficient and deep explaination .Thanku so much for sharing this......

[@AmulsAcademy]

Glad to hear that :)

[@srikrithibhat1999]

Great explanation. Keep rocking.

[@fuckukkfuckukk9859]

Really your voice is amazing ❤️❤️. For easily understand

[@sairamadaboina]

Thank you Ma'am, you're explaination was very good

[@webcreationstudio7088]

value=str(154) count=len(value) re=0 for x in value: temp=pow(int(x),count) re=re+temp ans=re if(ans ==int(value)): print("yes") else: print("not")

[@JawTheory]

Thanks Keep Up The Good Work 👍👍👍

[@AmulsAcademy]

Thank you 😊

[@yt_user685]

num=input() l=len(num) sum=0 for i in num: sum=sum+int(i)**l if (sum==int(num)): print(num,"is a armstrong number") else: print(num,"is not a armstrong number")

[@seokmin2624]

Wrong bro

[@yt_user685]

@@seokmin2624 can u point out that mistake

[@seokmin2624]

Nvm it's correct bro thanks!! WB magic number?

[@yt_user685]

@@seokmin2624 right !

[@nakshatrarahane846]

Absolute the best....loved your teaching method

[@AmulsAcademy]

Thanks so much!

[@dash_food9699]

Explanation is very good easily anyone can understand thank u.........

[@AmulsAcademy]

Thank you :)

[@pranishn4649]

Really really great explanation. I'm becaming pro, thanks for video ❤️

[@jesusrojas3750]

def armstrong(n): for x in range(1,n): number_str=str(x) _pow=len(number_str) number_sum=sum([int(i)**_pow for i in number_str]) if number_sum== x: print(x)

[@saunakpaul365]

Very nicely explained...thanks for making my doubts clear.

[@AmulsAcademy]

Pleasure :)

[@nikheeljoshi3524]

Ur tutorial is too good thank you

[@anishachoudhury_]

Thankyou so much Ma'am. It was so easy to understand.

[@vishnuvardhanreddy1967]

Thanks a lot ❤️ I am new to this you helped me a lot 😊 god bless you

[@AmulsAcademy]

You’re welcome 😊

[@jaatabcd5130]

really helpfull python practice question & answers.

[@AmulsAcademy]

Thank you :)

[@jaatabcd5130]

@@AmulsAcademymam we are waiting for more programs.that time will com more complex program mam!!!!Thnaku :)

[@samarthgupta3704]

thanks for this and other important videos

[@AmulsAcademy]

My Pleasure :)

[@subbu653]

Explanation super 👌

[@AmulsAcademy]

Thank you :)

[@madhuhadas15370]

You are a great teacher, thanks a million.

[@Akash-nl3oz]

thanks alot of my doubts are cleared.

[@syedsabeer1027]

really it is true, oops till now i have been remember every given value suppurated and cubed then add, if the result is equal to input that no. is an Armstrong number. every time googling its shows like that.

[@praveenchandra340]

Wowww..! Thank you so much mam.

[@AmulsAcademy]

Most welcome 😊

[@bhashkarrawat1829]

Mam you are best and ur speaking is most best

[@AmulsAcademy]

Thank you:)

[@pritam_rout]

def armstrong(value): series = [] for num in range(value): power = len(str(num)) result = 0 for i in [int(i) for i in str(num)]: result += i**power if num == result: series.append(num) return series print(armstrong(1001))

[@rahulpahuja4554]

Hello miss. I loved the way you explained every step of the logic. Keep on making such great videos. Thank you very much.

[@AmulsAcademy]

Thank you :)

[@Banzaraaa]

Great explanation mam!! Thank you so much

[@AmulsAcademy]

Pleasure 😊

[@aladdindorado3608]

Very clear tutorials. Thank you!

[@AmulsAcademy]

Glad it was helpful! :)

[@HarshitaChattopadhyay]

Thanks for helping me...! ❤️ ❤️ ❤️

[@AmulsAcademy]

Pleasure :)

[@pauljacobus1066]

This is the solution I "wrote". It works and the logic makes sense to me, but I'm wondering if my solution is primitive or amateurish since it differs so much from yours. def armstrong(num): sum = 0 exponent = len(str(num)) for digit in str(num): sum += int(digit) ** exponent if int(sum) == int(num): print (sum) for num in range (100000): (armstrong(num))

[@anubhavsingh9049]

Try this n =input() for i in range(1,int(n)+1): sum=0 for j in str(i): sum+=int(j)**len(str(i)) if sum==i: print(i)

[@chellaboinanarsimha8223]

Very nice! Good explanation. Thanks for uploading this video.

[@AmulsAcademy]

Pleasure :)

[@abdullah-al-mamun4111]

I'm impressed!

[@AmulsAcademy]

Thank you :)

[@raghukulsingh548]

Your voice is so nice I'll enjoy all session

[@AmulsAcademy]

Thank you :)

[@CS-sb2yj]

Nice detailed explanation 💯 Armstrong number👍

[@deepanshuchaudhary8966]

An Armstrong number of is an integer such that the sum of the cubes of its digits is equal to the number itself. The Armstrong numbers between 1 to 500 are : 1, 153, 370, 371, and 407. Please provide the correct program to us. 2, 3, 4, 5, 6, 7, 8, 9 is not the Armstrong number madam. try this lower = int(input("Enter lower range: ")) upper = int(input("Enter upper range: ")) for num in range(lower, upper + 1): sum = 0 temp = num while temp > 0: digit = temp % 10 sum = sum + digit ** 3 temp = temp // 10 if num == sum: print(sum)

[@AmulsAcademy]

I am sorry but your definition of Armstrong number is wrong :)

[@cer_oz]

This is easier to read. for y in range(1000): if sum(int(x)**len(str(y)) for x in str(y)) == y: print(y)

[@manashmahanta4984]

Hi really nice video.....Please, provide a tutorial how to print armstrong number in a certain range without using while loop. I got this question in an interview. Please, explain the approach without using while loop..

[@AmulsAcademy]

Noted :)

[@manjultripathi8309]

Superb Playlist.Much Thanx :)

[@balasaravananalavandhar1639]

it was mind blowing tutorial. thank you

[@AmulsAcademy]

Pleasure :)

[@nehajha190]

outstanding explanation. grt!!!!

[@shubhamdhole5160]

Thank you for this playlist, it is really helpful for placements

[@johnstabbyman5704]

I came up with the following solution on my own. It seems to work def is_armstrong(num): tally = 0 n = len(str(num)) for i in str(num): tally = (int(i)**n) + tally if tally == num: return True else: return False for i in range(1001): if is_armstrong(i) == True: print(i)

[@aruninfotechche9174]

some simplified def is_armstrong(num): tally = 0 n = len(str(num)) for i in str(num): tally = (int(i)**n) + tally return tally == num for i in range(1001): if is_armstrong(i) print(i)

[@vigneshs4520]

wow, nice explanation mam.

[@AmulsAcademy]

Thanks a lot :)

[@123thedarkness]

I love this channel and thank you so much for making this explanation really easy to follow!

[@hopegaming3628]

Perfectly explained ❤️🙏

[@AmulsAcademy]

Thank you :)

[@saranyav5244]

Mam,where did u learn from ??about python ...wow u r very intelligent

[@AmulsAcademy]

Books, KZbin videos 😊

[@vaibhavtembhekar1296]

yo this is perfectly explained.

[@AmulsAcademy]

Thank you :)

[@shaiknayeem3277]

really supper explanaation after i have watched this video i am thinking why i paid lakhs of fee in my btech college

[@shantanuwanare5486]

if user want to give the number to check armstrong or not :- user = int(input("enter the number")) num = user result = 0 n = len(str(i)) while(user>0): digit = user %10 result = result + digit ** n user = user // 10 if num == result: print("The number is Armstrong Number") else: print("The number is not Armstrong Number")

[@nareshreddy8251]

U r explanation is very fantastic.. u can upload more videos about CRT classes mam ...

[@AmulsAcademy]

Thank you :)

[@satyasidda9626]

Very well explained

[@AmulsAcademy]

Thank you :)

[@madhursikarwar8531]

I suggest you to bring more numbers program and pls may you post a video on bubble sort in python and if already there pls provide me with the link

[@AmulsAcademy]

Yes bubble sort videos are uploaded, search for that you will get it easily😊

[@anilkumarreddy9349]

These explanation is never seen in my college also

[@AmulsAcademy]

😀😊❤️

[@souradipbiswas6623]

tnks misssy, and know what i kinda like your voice, reminds me of a certain someone