An Outstanding Algebra Simplification Challenge | Can You Outsmart?

  Рет қаралды 1,667

infyGyan

infyGyan

Күн бұрын

An Outstanding Algebra Simplification Challenge | Can You Outsmart?
Welcome to another exciting Math Olympiad challenge! 🎉 In this video, we tackle an outstanding algebra simplification problem that will test your skills and push your limits. Can you outsmart this tricky algebraic expression and simplify it correctly?
Join us as we break down the steps, provide insightful tips, and reveal the solution to this special algebra problem. Whether you're preparing for a math competition or just love a good challenge, this video is perfect for you!
🔔 Don't forget to subscribe for more math hacks, tips, and challenging problems to sharpen your skills!
🔢 What You'll Learn:
Key techniques for simplifying algebraic expressions (substitution)
Common pitfalls and how to avoid them
Tips and tricks to approach Math Olympiad questions with confidence
Time-stamps:
0:00 Introduction
0:30 Substitution
1:05 Algebraic manipulation
3:30 Algebraic identities
6:18 Simplifying expression
9:26 Answer
📚 Additional Resources:
• Challenging Algebra Si...
• Crack This IMO Challen...
• A Fascinating Radical ...
• Math Olympiad | An Alg...
🎯 This video is perfect for students, math enthusiasts, or anyone seeking to sharpen their problem-solving skills and gain confidence in dealing with radical expressions.
#matholympiad #radical #simplification #problemsolving #mathematics #challenge #mathskills #radicals #math #algebra #learnmaths
Don't forget to like, share, and subscribe for more Math Olympiad content!
Thank You for Watching!!

Пікірлер: 8
@UKPEINDANIELU.
@UKPEINDANIELU. 29 күн бұрын
Fantastic
@mohammedsaysrashid3587
@mohammedsaysrashid3587 29 күн бұрын
It was a wonderful explanation .thanks Sir 🙏 for sharing
@dorkmania
@dorkmania 28 күн бұрын
Another way would be to use the polynomial expansion for (a+b)⁵.
@user-kp2rd5qv8g
@user-kp2rd5qv8g 29 күн бұрын
A more direct way is to start from x^3= -x^2-1/3x +1/3 where x = 1/3[10^1/3-1]. Using this, x^4= 1/3[2x^2+2x-1] and N = x^5 = 1/9[2-5x] = 1/27[11 - 5. 10^1/3].
@user-kp2rd5qv8g
@user-kp2rd5qv8g 29 күн бұрын
N= 1/243[10(10^2/3) -50(10^1/3) +100 - 10(10^2/3) +5(10^1/3) -1] = [99-45. 10^1/3]/243 = 1/27[11 - 5. 10^1/3].
@user-ny6jf9is3t
@user-ny6jf9is3t 29 күн бұрын
[(-5×10^1/3)+11]/27
@RealQinnMalloryu4
@RealQinnMalloryu4 29 күн бұрын
59.048^10.000 ➖ 1/243),=590.048/243=2.204.048 2^1 10^20 2^2.0^0 6^8 1^1 2^5^5^4 1^1.3^2 2^3.1^1^12^2.3^1 2^1 1^1^1^1.3^1 2^1 32 (x ➖ 3x+2)
@RajeshKumar-wu7ox
@RajeshKumar-wu7ox 29 күн бұрын
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