Analysis of Complex Impedances in Parallel (Pt. 1)

[@Alyx_Muffinton]

Thank you so much for actually working out these examples, unlike my textbook.

[@irishchocolate3872]

It is always important to know the steps in solving these problems. To be able to actually do the math. Todays calculators that have complex number capability built into them basically do everything for you. Thank you for taking the time to show us how these problems are worked out.

[@EngineersAcademyLTD]

Glad you found it helpful

[@אוריהרשקוביץ-ע3ט]

Hello. You are doing a great job. Explains complex mathematics in a simple and clear manner. Well done, I'm practicing according to your videos, and it's becoming clearer to me. I wish you health and success, all the best.

[@bekiryufka]

Very straightforward. Thanks!

[@johnfernandez4985]

best vid on it so far

[@tailcatch4270]

This was incredibly helpful, thank you so much.

[@abdullahmoallim4486]

that was so helpful thanks

[@GaganaSindhu-d1d]

Thank you sooooo much

[@spelunkerd]

After doing a question I often ask myself if the result is reasonable. In the last example after 19:00, I am scratching my head to realize that when you add an inductor in parallel with a capacitor, you may effectively increase the capacitance! Are there any 'sniff test' rules for these kind of parallel questions to help decide if your answer is reasonable?

[@EngineersAcademyLTD]

Remember that the formula for the reactance of a capacitor is -1/(2 pi f C) So though you are right in that the magnitude of the "reactance" is increased (negative), this actually makes the effective "capacitance" smaller, because of the above inverse relationship.

[@shivampithadia]

Thank you.

[@dalenassar9152]

With these answers involving "j", how do we convert them into something that can have an actual answer to get a real value for the resistance that we can use to express an actual answer, even in terms of frequency (Hz).

[@EngineersAcademyLTD]

Remembering that a positive j component represents an inductive reactance (XL) and a negative j component represents a capacitive reactance (XC), these reactances could be converted into equivalent component values if the frequency is known. A purely real result is not possible, but it is sometimes acceptable to find the absolute value (or magnitude in polar form) of the complex number, using a resistor of this value as an "equivalent", since the absolute impedance would be the same.