Derive Triple Angle Formula sin3x

[@brandonbrandizzlemartin]

Greetings sir, the correct answer is 3sin x - 4sin^3 x

[@curiosity551]

Sir,please explain me how you proceded from 3rd to 4th step.i am not getting it.

[@MathematicsTutor]

This is the corrected Video on sin3x: kzbin.info/www/bejne/e3nOlJ-JeqyKm80&list=PLJ-ma5dJyAqqZW7lXwiBR1L_0jOqsW7zf

[@amitakhandelwal1435]

really good

[@curiosity551]

I think 3sinx.cos^2x-sin^3x is right.

[@MathematicsTutor]

Yes, here it is kzbin.info/www/bejne/e3nOlJ-JeqyKm80&list=PLJ-ma5dJyAqqZW7lXwiBR1L_0jOqsW7zf

[@mahisharthivellingiri5389]

There is a mistake in your derivation sir. 2sinx cos square x+cos square x sinx - sin cube x =3 sinx cos square x-sin cube x

[@MathematicsTutor]

Here is the Correct Derivations: kzbin.info/www/bejne/e3nOlJ-JeqyKm80&list=PLJ-ma5dJyAqqZW7lXwiBR1L_0jOqsW7zf Thanks

[@mahisharthivellingiri5389]

Thank you,sir

[@MathematicsTutor]

Thank you for pointing that out. I will soon delete this video.

[@hisride]

EOY gud

[@Visible_History]

sir please delete this video as it gives the wrong answer

[@MathematicsTutor]

cos2x can be written in 3 different ways and so we can get alternate formula. All are correct. Check: kzbin.info/www/bejne/e3nOlJ-JeqyKm80 Thanks

[@Visible_History]

@@MathematicsTutor im referring to your final answer of : 3sinΘcos³Θ- sin³Θ, the answer should be 3sinΘcos²Θ - sin³Θ. Where the exponent in the videos answer is 3 instead of 2, incase u missed the error

[@MathematicsTutor]

@@Visible_History Oh Yes, thanks

[@georgeferguson5773]

you are wrong

[@RYedukrishnan-cn5ft]

Everyone alert their is a mistake in step 4😂: cos²∅ not cos³∅