Finally someone explained it correctly! Thanks ma'am for your efforts.
@turing4991 Жыл бұрын
You explained so easily, even my teachers couldn't in 4 lectures
@mahmoudalkhatib1538 Жыл бұрын
thank you, but how do you know that u is always equals to a^n. it could be more and it although could be less?
@LovepreetLovepreet-vw1ce5 ай бұрын
everything seems normal until you hear n as yun, l as yul and x as yux 😏
@devanshsingh25 ай бұрын
Sale padhai pe dhyan dele 😂
@LovepreetLovepreet-vw1ce5 ай бұрын
@@devanshsingh2 and m as yum 😂
@purpleunicorn61610 ай бұрын
This video is super helpful! I finally understand the pumping lemma for cfl :)
@30benasabu65 Жыл бұрын
Madam I have a doubt like to take v^(i-1), i>0 is to given here i>=0 is taken . why is it so
@joaohenrique03 Жыл бұрын
obrigado pela lição abraços do brasil 🇧🇷
@arya_math39264 ай бұрын
This is wrong , you are not allowed to choose u , v , w , x ,y as you desire, but infact you should give a W(the string you choose to show the contradiction) as an example that works for every possible u,v... Basically what you can do to fix your solution is to brute force all possible ways to choose u,v... and show contradiction for all of them
@joshe34993 жыл бұрын
Mam how will prove { a^i b^i^2} is not CFL
@asma59722 жыл бұрын
it is CFL
@DoAnhNhat-v3g Жыл бұрын
I wish I knew your channel soonner
@jyothithota14693 ай бұрын
Good explanation mam
@SafalGupta2 жыл бұрын
Thank You mam! soo Help Full Lecture
@roshan_codes2 жыл бұрын
Awesome. Thank you.
@NikhilKumar-mz1jt3 жыл бұрын
Apply pumping lemma to following languages and understand why we cannot complete proof L = {anaba | = 0}