Anomaly detection with Isolation Forests

[@vikashdas1852]

Most probably the best explanation on internet related to Isolation Forest/Anomaly detection

[@brendensong8000]

Excellent Video with a short, clear explanation of the iForest algorithm! thank you for sharing!

[@gabrielacuna8530]

Best short explanation I've found on KZbin. Very straight to the point (pun intended) with clear explanation.

[@chanmad]

anomaly detected

[@nicoco5483]

Prolly the clearest explanation I've watched. Much appreciated!

[@insightIQ2023]

True , it is explained very nicely

[@mehdioueslati8713]

Extremely clear, thank you!

[@freydunthanos3155]

Got my subscription and bell - thank you so much for the in-depth yet totally understandable explanation!

[@Bleustar334]

Wow, this video was incredibly informative!

[@animeshshukla3534]

Ma'am it was very well explained with all the mathematical details.

[@jjbandit3355]

Thank you, this was fantastic!

[@jeromeeusebius]

Thank you for making this video and it's very succint and straight to the point

[@hsoley]

amazing, thank you from NYC

[@trrao835]

great explanation. Thanks

[@avunurishivakumar7972]

Thank you🤗

[@sheilaabukayo156]

Well explained..

[@tranquochung1995]

Thank you very much

[@andrea-mj9ce]

What's an isolation tree then ?

[@rabbymustafa3792]

This is a great tutorial

[@aakashdwivedi5096]

This was great. Thank you very much

[@mohammedsufyan6950]

mam what type of feature we are selecting here

[@Moonlight-uv7jo]

Thank you! Very nice explanation:)

[@Piyush4113]

Please can anybody explain what is the difference between E(h(x)) and c(m) because E(h(x)) is also the average values of h(x) over all iTrees and c(m) is also the average value of h(x)? Please i am really confused what is the difference between them!!

[@emamulmursalin9181]

E(h(x)) is the average values of h(x) over all iTrees but only for data point "x" c(m) is the same but it is calculated only from the "m" samples from the training dataset

[@InoHimeYa]

Very understandable

[@pennyzhang9139]

Thanks. Very clear.

[@anirbansen4059]

Short and crisp.

[@vcj3849]

Great work

[@machinelearning4611]