Another method to solve the challenging monster integral using a variety of special techniques

Mis-1782A
Integrate (ln(1 - x) ln^2(1 + x))/x dx from 0 to 1
#calculus #definite_integrals #maclaurinseries #riemann #zeta #function #cipher

[@cipherunity]

At 5:18 instead of 1/(v + 1)^2 it should be 2/(1 + v)^2. Sorry for this mistake.

[@krisbrandenberger544]

@ 6:55 Should be x^2, not x.

[@krisbrandenberger544]

@ 5:19 Should be 2, not 1.

[@cipherunity]

Right. I missed it only at this instant. Thanks for catching that.