AP Calculus: Rectilinear Motion with Derivatives

[@anamarie8160]

Really hope he’s doing well and realizes how good and helpful this was to me.

[@ScottKennedyMath]

Thank you for the kind words Ana Marie!

[@fionajaurigue9626]

Literally after a decade you're still saving a generation thank you so much mister!

[@A_Marcou]

absolutely goated video. dude explained in 10 min what my teacher couldn't clear up in 3 lessons

[@alexargueta7998]

9 year difference yet it's explained better than my teacher! thank you!

[@XoCortanaXo]

You don't know how many times I was thanking you while watching this video😆. You made this difficult concept simple for me to understand finally. No joke, God bless you! 😭😭

[@anshulgattani2561]

This was such a good explanation! Super easy to follow and learn, lifesaver!!

[@mn-yv2ur]

Oh my gosh. You are amazing. I've learned a lot in 10 minutes.

[@TomboiiLinkZ]

This is so helpful!! Sending best wishes thank you so much !!

[@goobertgolly]

hey i found a helpful video!!!

[@danndungu4737]

You nailed it bro. Thank you so much, you answered all the questions i had.

[@newt8139]

thank you scott

[@ia490]

Thank you so much! You made it so easy to understand.

[@alphashaun360]

fantastic work Scott keep it up!

[@prestoncederquist8552]

bros a savior fr

[@rain_yy]

Sir may i ask what did u do on the 3:59 ? the t-5 and t-2?

[@itscole546]

This is very helpful

[@ammaralsaied9728]

Thank you for this! Out of curiosity, which region from the U.S are you from? I'm guessing East Coast?

[@MattBriggsTV]

what a lad. great lesson but also a great personality.

[@zijunli9261]

excellent lesson!!

[@synergy1916]

At 5:05 where did you get 2 and 5? Is it just a random pick of numbers or you did something?

[@ScottKennedyMath]

Those are the values of t where v(t) = 0 (*see 4:14). These are the locations where the particle may change directions since it needs to come to rest in order to change direction.

[@ombida12]

thanks buddy, keep up the good work!!

[@jackyellow]

very helpful thank you :)

[@janettemendoza2419]

Nice video!!!!

[@skullmann1262]

When you added up the total distances, one of those numbers was a negative number. Why did you still add instead of subtract?

[@mississippichungo]

+Skull Mann because hes looking for distance not displacement

[@ryanscott260]

god damn that was a great lecture.

[@DinarAzat]

bless you

[@gostranger1]

why does a derivative of position become velocity and the derivative of velocity become acceleration? can any one explain i am not getting it!!

[@ScottKennedyMath]

Because derivative calculates rate of change at any defined point. The rate of change of position is velocity. Think change in position divided by change in time (dx/dt): distance divided by time is RATE (ft/sec for example)... The rate of change of velocity (how fast the velocity is changing) is acceleration.

[@editorsfile8218]

wowwwww thank youuuu

[@jempottv3179]

what if he is looking for displacement

[@VersedYT]

Then you wouldn't use absolute values, so you'd subtract the 27 (negative) from the 52.

[@tomatocats13]

thank u!

[@JessicaMartinezVlogs]

why it became (t-5)(t-2)=0 ? confused. sorry

[@maemanigsaca5008]

thankyou so much

[@lukes1832]

James Madison says hello

[@charees8685]

TY

[@teweone]

Yeah

[@alexrusso5067]

LOVE YOU

[@seralexis]

📌03/22/24