Application: Kinematical and dynamical symmetries - Lec 28 - Frederic Schuller

[@essadababneh5871]

you are an amazing teacher. I love how organized you are. I hope you keep uploading more videos. Your students are very fortunate to have you as a mentor.

[@shubhang-sharma]

If someone has attended the above lectures or somone has the problem sheets of this course please update here. Much needed!

[@englemanart]

I feel so fortunate to have watched these.

[@block3dwiz]

These lectures were quite inspiring. It would be great to have a QG course with the same clarity!

[@Achrononmaster]

Cannot be done today, QG is not well-defined yet. All good mathematicians should avoid QG. What some more contemporary physicists are finding (slowly) is that gravity probably is _already_ a quantum theory and should not be "quantized." The key is that orthodox QM really only has _one quantum postulate_ and it can be replaced using GR by an equivalent "quantum postulate"... namely that the spacetime topology is non-trivial, and "particles" are regions of non-trivial topology (thus containing CTCs) with surrounding asymptotically Minkowski spacetime.

[@kashu7691]

@@Achrononmaster would you mind pointing to some places where I could read more about these ideas?

[@Minus_1_form_symmetry]

The Dynamical Symmetries are labelled as Hidden Symmetries, they play a massive role in the integrability of Kerr solution.

[@bhavyaagrawalla6319]

The best teacher i have ever seen.His lectures are so wonderful.I am in class 11 and a math enthusiast.I wish he was my mentor

[@hyperduality2838]

Potential energy (dynamical) is dual to kinetic energy (kinematical) --- gravitational energy is dual. Symmetry is dual to conservation -- the duality of Noether's theorem. Apples fall to the ground because they are conserving duality (energy)! Energy is duality, duality is energy. Vectors are dual to co vectors (forms). Sine is dual to cosine or dual sine -- the word co means mutual and implies duality. "Always two there are" -- Yoda.

[@aymericgarnier9558]

Thank you for all these wonderful lectures

[@sanketthakkar4496]

Thank you very much sir you are so brilliant you organized whole lecture series which covers a most of application in physics point of view.🙏

[@albertoisaacdiazsaldana330]

awesome lectures by the way Dr Schuller

[@matasmackevicius5594]

Excellent set of lectures, very helpful and enjoyable!

[@AmandeepSingh-xk4yv]

Thank you very much Sir for making such resourceful videos and sharing them on youtube!! Very lucky to have found your content. :)

[@ekinkaan5959]

I spent the whole term with these lectures+GR. I was expecting at least "a good bye talk". It was a bit rude to finish the last lecture like this... :) Anyways, it`s been a fun and inspiring term for me thanks to the lectures. I just thank Schuller and the people contributing to these lectures and making it public.

[@samhuang2545]

very inspiring lectures!!!!

[@saadtail1891]

Hi, is there any way by which we can get the prblm sheets?

[@albertoisaacdiazsaldana330]

Where does he explain about the Lie Derivative? I did not find it in any of the previous videos, maybe he left it for the problem sheet?

[@rishabhkumar9587]

You can find it in Lecture 11 of the GR course!

[@rounak5106]

Any cue on how to define Levi Civita connection on a Riemannian and Lorentzian manifold and its relation with Ehresmann connection? Or some further references? Additionally suggest some good symplectic geometry book, if you know.

[@praveenxavier8143]

At 1:16:53 shouldn't there be two stopping conditions since the recurrence relation is second order?

[@rajatmond]

Yes. But if you calculate both, you'll see they are the same conditions for odd and even order.

[@florentdupont4153]

@@rajatmond Hi, I don't get it, could you explain what you mean ? I still don't get why we need only one condition

[@rajatmond]

@@florentdupont4153 that's not "one condition" those can be conditions for all values of n. Now you can write the same equation for odd and even n's and they become two conditions. You can write n=3j, 3j+1 and 3j+2 for all integers j and they become 3 conditions and so forth...

[@alanrapoport6784]

Where can I find his GR course?