arithmetic expressions in Java 🧮【4 minutes】

[@BroCodez]

public class Main { public static void main(String[] args) { // expression = operands & operators // operands = values, variables, numbers, quantity // operators = + - * / % } }

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[@WandererSociety]

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[@SilentDims]

if your friends are double you don't need to cast to double, because if one of your variables is double, result will be double.

[@notsaeed]

Exactly

[@thewewguy8t88]

i was thinking the same thing.

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[@BroCodez]

thanks for watching Theo!

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I very much needed this for our practical quiz in Programming.

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[@DeepakLalchandaniProfile]

I want to evaluate a mathematical expression from left to right only in Java Example : 16+10×500-3000/50 Output : 200

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[@servallou2514]

I don't understand how the new datatype thing works at 3:34, like we assign a new datatype, but for that we must have the same datatype than the "new" one

[@thephoenixsystem6765]

It doesn't appear to do anything in this example, but if you initialise a new variable like this: int friends = 10; float enemies = (float) friends/7; System.out.println(enemies); You get output: 1.4285715 But if you skip the (float) on that line, you get 1.0, because it treats it like integer division, then turns the 1 into a float.

[@nirajanmahara4048]

yes, otherwise even if after explicit type conversion in expression, it throws an error(as shown: red underline). so, need to change the main variables data type also.

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[@malli-qw1fd]

public class ArithmeticExp { public static void main(String[] args) { // expression = operands and operators // operands = values, variables, number, quantity etc.. // operators = + - * / % int myNum = 10; System.out.println("divide: "+(10/2)); System.out.println("Multiply: "+(10*2)); System.out.println(myNum); } }

[@cup_kids]

Thanks 😊

[@ranasaani]

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[@schoudhury1911]

You are truly a Bro ...

[@HsuMonMonThant]

Thank u so much for this understandable explanation video.

[@Rinku-ac]

Bro, i have a question at 4:06 double friends = 10; friends = (double)friends/3; what is the point of the (double)? cuz it works without it

[@who77754]

this guy is a legend

[@chaitydey8175]

hello, I have a question. why do we need to cast int to double here? cause without casting it still returns the correct result. Thanks :)

[@fabiolaromero8501]

Its a bit disturbing use the double variable to count friends hahahaha

[@anibender4822]

As I was executing the program I found out that it is possible not to add the variable double twice. The variable can be declared of type double once when it is assigned the value 10. So what is the point to add it twice here?

[@trailblazer4227]

I was just asking me the same.

[@Shanishani53267]

The best explanation

[@lavin3865]

you can just say 3.0 and do not write (double) in front of friends, it is easier. and thanks for your videos, it makes my life much easier, hope i can pass programming this semester ...

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did you?

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Thanks bro code, you make learning this stuff fun and easy

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absolute legend

[@iscottjones]

I'm only learning, but isn't this a mistake: 3:56? If you change "friends" from an int to a double, then there isn't any need to have a double here: friends = (double) friends / 3;. The code works the same way if you remove this double.

[@ЕвгенийКузнецов-ъ5з]

TY so much for your's lessons bro!

[@TOP10-j8h4o]

Really enjoyed and very good

[@Andy-fg7hm]

Not sure if you will answer this or not? But would it not be easier just changing the "int friends = 10;" statement just to "flat friends = 10; and keep the statement of "friends = friends / 3;" the same?

[@thewewguy8t88]

i was thinking the same thing.

[@lakshaydang2194]

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Awesome video!

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dropping a comment. Thanks for the video!

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i learnt this, thank you

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[@JustNeutral14.]

question - is there any easy way to do exponents in java other than variable = variable * variable?

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Another lesson that i understood

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[@livelyan2801]

You forgot about the operations +=, *=, etc. "variable += 1;" equivalent to "variable = variable + 1; Anyway thank you!

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[@oxeo]

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