Armstrong Number | To check if a given number is an Armstrong number or not | Java

[@Btechquastions-zh5cy]

class Ambstrong { public static void main(String[] args) { int n =153; int temp; int amb = 0; int original = n; while(n>0){ temp = n%10; temp = (int)Math.pow(temp,3); amb = amb+temp; n = n/10; } if(original==amb){ System.out.println("amb"); }else{ System.out.println("not amb"); } } } Thank you so munch... 👌

[@prakharsrivastava5130]

*Check Armstrong number for n digits* import java.lang.*; import java.util.Scanner; public class armstrongNum { public static void main(String[] args) { // Asking for INPUT from USER System.out.print("Enter a Number: "); Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int s = n; int m = n; double r,q = 1; int counter=0; double sum=0; // To count number of Digits entered by USER while (n > 0) { r = n % 10; n = n / 10; counter++; } // Logic here while (m > 0) { q = m % 10; q=Math.pow(q,counter); sum+=q; m = m / 10; } // Checking if (sum==s) { System.out.println("Yes it is a Armstrong Number"); } else { System.out.println("Not a Armstrong Number"); } } }

[@sarahfatima9840]

Splendid!! Your method of first explaining each step before writing the program is amazing. I have been struggling since months to find a good computer teacher and I never understood these concepts but after watching your video I feel blessed. I have understood. Thank you❤️!

[@BTechComputerScience]

Hey thanks... ur satisfaction means a lot to me😊

[@sarahfatima9840]

@@BTechComputerScience No worries🤭💗

[@Mulllana_Haramudil-AlHarami]

CS sir with least technology you are best . Your explanation at each & step is amazing 😍. Keep it up ;

[@Reahroy-fr4jl]

Thank you so much ❤ please continue to do like these videos❤❤❤

[@vikrambahure8639]

very easy steps ...thanks sir

[@sreejayvlogs]

Awesome bro…. 😊 it’s so clear

[@kainaatmakhani6550]

u made my life very easy thankyou so much.

[@NailPassion999]

Excellent explanation😃

[@mounimouni224]

Detailed one..!! Great Thank you..!!

[@keerthanaselvaraj6791]

How to find the first,last and middle number in an given input in java ,post a video for this ques .The method of teaching in the notebook is easily understandable.Good teaching methodology.

[@anusharasumolla3017]

Thank you so much your videos helped me a lottttttt

[@ShivaKumar-yy2ym]

Thank you so munch... Great work 👍

[@mepreetii]

Hi sir you should initialize temp as double as math pow cant be in int data type

[@BTechComputerScience]

Yes correct!

[@payalnishad1854]

Superb bro. 🙏thanks alot for make coding this easy... I was unable to understand the armstorng concept but when I came across your video now I started considering myself pro at coding😝😂👍

[@BTechComputerScience]

😂👍

[@Kishore-xz6cb]

everyone learning the program meanwhile me getting saced in 2am by hearing a brid sound 4:28😂

[@sindhuhari2628]

Brother there we need to do explicit type conversion near applying power else we will get an lossy conversion error

[@BTechComputerScience]

Yes, students are smart and will figure it out😊, they won't like if I spoon feed everything! Thanks for supporting!

[@Giriagroandfashion]

How to do Brother??? Can You Please Explain

[@Misartlog_brush]

It was very helpful, thanks

[@BTechComputerScience]

Glad it was helpful 😊

[@docmusiq]

If your loss conversation, just change your temp data type from integer to double...eg declare your temp like: double temp; Your explanations are amazing, especially the way you break down the question through pseudo-code and you show every declared variable duty while executing the code...

[@BTechComputerScience]

Really glad u like it 😊

[@saikrishna-fg2so]

please copy the code in the comment session, it have some errors

[@sandhyabonagiri8330]

Tq alot bro....🥰🥰🥰🥰

[@ravinatram]

Pls give description of variables pls

[@venkatakumargangapatla4510]

Thank u soo much sir 🤝🤝🤝

[@Aishwarya_Shettar]

Sir,make vdo on Find a armstrong number btwn 2 numbers!

[@sindhuhari2628]

And why aren't you uploading videos these days

[@priyankapatil6521]

Sir ...plz how to generate random number par vedio banao ..

[@appuappu8466]

Write a program add two number without using additional operator in java. How to sir

[@SourabhPrajapatArts]

thanks bro

[@sureshirla4283]

Sir akkada 153 number iccham kabatti math.(temp 3 ) ani pettaru but asalu ye number ivvakunda Armstrong aa kadha ani telusukovadam ela

[@saikrishna-fg2so]

please copy the code in the comment session, it have some errors

[@antonychellamarul]

Sir, *Definition Check* An Armstrong number is a positive n-digit number that is equal to the sum of the nth powers of their digits. (not only by cubes ,cubes for only 3 digits). Ex: 8208 = (8^4 + 2^4 + 0^4 + 8^4) = 8208. *not by cubes* .

[@BTechComputerScience]

Yes that's true, this is for beginner level, once u learn this, we can do it for any number of digits. Easy.

[@aishwaryas5146]

Where is execution part?

[@durgabhavani5855]

Sir If u don't mine u r way of explanation is so nyc but u r voice is not audible properly please raise u r voice sir

[@BTechComputerScience]

Hey thanks for letting me know, I ll improve it

[@greeshmikaagarwal256]

Thank you

[@PreethiRenu]

anna ,Armstrong number in a given range in java edhuku coding vanum anna pls video upload 😔pannunga

[@kiranmairuben2978]

Error in temp= math.pow(temp, 3); pls help

[@ashishannappa6908]

It will typemissmatch

[@ashishannappa6908]

Try another method

[@sureshirla4283]

Temp=(int)math.pow(temp,3) try this bro

[@deamoneye5075]

Concept is Wrong, Pow(Num,Length) is right .

[@BTechComputerScience]

Yup.. that's right! But m just teaching the basics.. so that students can understand the core and then move to a little more complex programs where they can mix 'Armstrong' and 'count number of digits of the given number' to perform what you just mentioned

[@vishalrc6903]

i get error when i use math.pow conversion type error what to do now

[@BTechComputerScience]

Share the code, let me have a look

[@vishalrc6903]

@@BTechComputerScience where to share it? Insta?

[@BTechComputerScience]

@@vishalrc6903 just copy paste the code in the comment

[@StudyPulse-uh7hk]

❤❤❤

[@naveena1441]

👍👍👍👍👍👍👍

[@aishwaryas5146]

@3:05 so many mosquitoes my ears...

[@salmanparsi8239]

Very usefull you deserve a like

[@Chari-007]

👍👏👏👏👏

[@HiteshSote]

What is about 1634

[@aishwaryas5146]

Armstrong we will get 308 so answer is not armstrong

[@Giriagroandfashion]

Getting error at Math.pow line

[@kiranmairuben2978]

Error in temp= math.pow(temp,3); Pls help

[@BTechComputerScience]

Try importing this - import java.lang.Math;

[@mohammadsajid8924]

@@BTechComputerScience kr diya import tb bhi error aarha pls help

[@bumbada1]

@@mohammadsajid8924 if you have stored temp in int that can throw an error type cast it : temp= (int) Math.pow(temp,3);

[@bumbada1]

@@BTechComputerScience explanation: pow method returns a double so if your temp is not double, you need to type cast it

[@mahaperumal5872]

why divided by 10 please any one explain

[@Giriagroandfashion]

To get the Quotient i...e., 15

[@kainaatmakhani6550]

sir plzz make video of palindrome number in java?

[@BTechComputerScience]

Watch my palindrome for strings video, a good coder like u can easily modify it for numbers 😊

[@tech-learner4555]

How u fix ur cam frmd

[@BTechComputerScience]

it's a pretty messed up setup right now, previously I was using a phone holder like this one amzn.to/3ArD6YE

[@tech-learner4555]

Thanks 🙏🏻

[@Solomoon-ce5wx]

Not like it

[@Swatisirmour]

Too much complicated

[@BTechComputerScience]

Practice more, do more coding... then it might not seem very complicated!

[@abdulrahim7763]

tried without while loop..this is working fine for me (give any number within the limit of integer data type) Scanner sc=new Scanner(System.in); System.out.println("Enter any number to find out if it is a Armstrong number or not"); int input=sc.nextInt(); String s=""; String count=s.valueOf(input); int input_size = count.length(); int digit; double Armstrong=0; double result=0; int actual=input; if(input>0) { for(int i=1;i

[@BTechComputerScience]

It's really great that u tried on your own and came up with great logic.😊

[@muvvaranjithkumar7260]

thank you bro